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UPDATED TO $20!

https://i.imgur.com/x6yURuu.jpg

All variables are positive constants. Also, L>mu and M>s_k

a) Find formulas for alpha, xi, kappa, and c in terms of the remaining variables that satisfy the inequalities, where the expression for alpha does not involve radicals (roots)

b) Find formulas for alpha, xi, kappa, and c in terms of the remaining variables that satisfy the inequalities, where the value of kappa is as small as possible

$10 for each part, willing to pay separately. Can use an escrow service.

Offer valid until tomorrow, April 23rd!

EDIT: Will pay $20 for EITHER a) or b) !!!! Extend deadline until 8pm UTC April 24th.

When i seen the word Algebra i was ready for the challenge. But this, this is called a headache.

I know  ;)
That's why I'm increasing the bounty to $20

this isn't algebra it is physics

Looks like algebra to me! :)
It's just variable manipulation, no physical meaning.

there is no variants this is alpha physics

Sorry, I never even heard of alpha physics.

I can do this job and will PM you the results in few minutes. However, I can type those variables but can write them in words instead.

As long as the answer works I don't care what format it is in.

don't be scared by all those variables, it may look complicated, but it's pretty easy, just a normal inequality

btw https://www.wolframalpha.com  ;D

Completed the task but my head is spinning now  ::) Hope the answers are right  :)

I sent you a PM.

lol....When i seen the word Algebra i was ready to die....I just hate maths , physics and history from my childhood....but thanks for this questions now I can challenge my friends ;D

Why hate maths? It is infact the best subject as there is nothing you don't need to memorize anything besides the formulas. This problem (if I got it right) was quite simple but the use of too many variables made it complex.

Good work i hope you did.But you should have escrow otherwise your hard work at the problem may get wasted.

Best Regards.

I hate maths due to less guidence....my parents or teachers didn't gave me much guidence so i never practised them and now I still hate it

Well, I dont want a debate here but this is very incorrect reason, someone who wants to gain knowledge can't be stopped by such fullish barriers. Remember " Its not your mistake if you were born poor but its your fault if you die poor".

Best Regards.

Checking the solution!

Am I correct that you are suggesting the following?

k=1

alpha=(u + L)/2uL

e =4uL - 1

c=(sk/m - 1)/(1 + 1/(4uL - 1))*2u²L/(u + L)²

EDIT: I still need to check it, but I don't think it will work, since your first three lines contain a mistake...
1/k - 2alpha*u*L/(u + L) <=0;
1/k <= 2alpha*uL/(u + L);
k<=(u + L)/2alpha*uL

EDIT2: This solution does not work, since for u = 1, L =2, the second (original) equation does not hold.
(1+4*1*2-1)*(3)/(2*1*2) - 2/(1+2) = 5.3333... which is not <=0

Bounty still open!!

Don't know if you posted it yourself or not but these guys can't solve it. https://2ch.hk/cc/res/98420.html

Is the calculation for some purpose? Are you trying to let someone else donyou homework ;)? Or are just trying to have fun when people burn their brain juice away?

I think I have the answer, can you escrow the funds? Also do you think you can extend the date a few more days?

Edit: Nevermind, I'll just post the answers. Only for part a)

alpha = (mu)/[(mu+L)(mu+3L)]
xi = 3L/u
c = (s_k)(u+L)(u+L)(u+3L)(u+3L)/3L
k = (1/[(s_k)/m-(1+1/xi)*c*alpha*alpha*2*L)] + (mu+L)/[2*alpha*mu*L]

If it is correct, please send the BTC to this address: 13MLwx49jT4a2SSwD17qu1uaG1sbGMdrzi

Im still confuse with math question, for this one, very difficult for me! Im usually can answer for aljabar question!

I just checked and noticed I substituted a wrong value for alpha and so the result is incorrect. I can see that another memebr has tried solving the equation and if by chance his solution too is incorrect, I can try again.  :)

you can use Mathematica to solve this problem, it's not hard.

the answer is n ^ n + b ^ = c n ^

TriggerX,

Let u=1/100, L=2/100, s=1, m=2

Then xi = 6, c = 147/2000000, a = 100/21.

In that case the first three inequalities hold, but the last one doesn't.

BOUNTY STILL OPEN!!!!!

EDIT: I will pay $20 for EITHER a) or b) !!!! Will extend the deadline 24 hours from now.

xi = 2L/mu
alpha = 1/(1+xi)(mu+L)
c = (s_k)/(2*xi*mu*m*alpha*alpha)
k=(1/[(s_k)/m-(1+1/xi)*c*alpha*alpha*2*L)] + (mu+L)/[2*alpha*mu*L]

Is this correct?

TriggerX, this looks extremely close! Still need to carefully check

I am not Math genius, but in high school we were told that if we had 5 variables and 4 equations for it, then it wouldn't be unsolvable . Wouldn't that be true for this case ?   

math make me crazy insane lol , goodluck to everyone .

May want to rephrase that a bit

where is the fund being escrowed ? Show us the proof ?

TriggerX did not request an escrow. I'm checking his solution at this moment. If it's good, I'll send the money.

so triggerx already won this contest?

Yes, TriggerX got an answer. Thanks everyone!
Contest closed.

TriggerX, money sent.
Would you mind posting the steps to the solution?

It took 30 minutes to figure it out and I don't want to type it all out again haha. If I have time I may post it here again.

As for the BTC, I have received it, thanks.