Title: [SOLVED] Skill Testing Math Question -- 0.08 BTC Reward Post by: notbatman on July 22, 2015, 04:23:47 PM Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s?
Earth's radius at the equator: 6,371,000 m Earth's velocity at the equator: 464 m/s Average weight of a person: 84,000 g formula: centripetal_force = mass * velocity^2 / radius Please provide the answer in grams and show your work! Title: Re: Skill Testing Math Question Post by: Gleb Gamow on July 22, 2015, 06:22:39 PM Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s? Earth's radius at the equator: 6,371,000 m Earth's velocity at the equator: 464 m/s Average weight of a person: 84,000 g formula: centripetal_force = mass * velocity^2 / radius 0.8/464 X 84,000 = ____ Did I do that right? Full Disclosure: I was the first one finishing the test and got a perfect 800 on the math section of the SAT back in 1978, but have probably forgotten more than half of what I've learnt back in the day. I taught myself calculus because it wasn't offered in my high school. I purchased a Timex Sinclair 1000 from Radio Shack (circa 1983), read the manual and learnt how to program a clock via Basic. Upon the first read-through, I quickly realized that I could program a clock to run backwards. Without referencing the program further, I implemented the program and it worked as I envisioned it. I then realized how boring this computer programming bullshit was, so I abandoned all future efforts. And you guys thought I was an idiot. ::) https://upload.wikimedia.org/wikipedia/commons/d/da/Zx81-timex-manipulated.jpg Ironically, during the same basic timeframe on some other part of the world, some dude named Andreas Antonopoulos immersed himself with basically the same device. I wonder what ever happened to him. :'( Title: Re: Skill Testing Math Question Post by: notbatman on July 23, 2015, 06:56:10 AM I'm considering adding a reward, is 0.01 BTC enough?
Title: Re: Skill Testing Math Question Post by: Gleb Gamow on July 23, 2015, 07:10:01 AM Please provide the answer in grams and show your work! 144.82758612 gms .8/464 = 0.00172413793 0.00172413793 X 84,000 = 144.82758612 Title: Re: Skill Testing Math Question Post by: notbatman on July 23, 2015, 08:10:47 AM Please provide the answer in grams and show your work! 144.82758612 gms .8/464 = 0.00172413793 0.00172413793 X 84,000 = 144.82758612 The merry-go-round is slowed to a fraction of its regular speed, the centripetal force countering gravity is also reduced and the average person weighs less according to your answer? I'm sorry but the average person is going to weigh more not less as the centripetal force is reduced. Consider two magnets stuck together with one of them tied to a string. If you twirl the magnets fast enough the one held on will fly off once the centripetal force exceeds the magnetic force holding them together. I do however appreciate your attempt at answering the question all-be-it a less than serious attempt. Title: Re: Skill Testing Math Question Post by: notbatman on July 23, 2015, 08:20:26 AM How about a 0.1 BTC reward, would that be enough to get a serious attempt at answering this question? That's almost $28 USD.
Title: Re: Skill Testing Math Question Post by: lolnapp on July 23, 2015, 08:28:29 AM How about a 0.1 BTC reward, would that be enough to get a serious attempt at answering this question? That's almost $28 USD. I think 0.02BTC would do. Just a small rewards for attach people :D Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: notbatman on July 23, 2015, 03:16:48 PM I've added a 0.01 BTC reward for the first correct answer.
Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: sukamasoto on July 23, 2015, 03:33:38 PM Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s? Let me tryEarth's radius at the equator: 6,371,000 m Earth's velocity at the equator: 464 m/s Average weight of a person: 84,000 g formula: centripetal_force = mass * velocity^2 / radius Please provide the answer in grams and show your work! ( 464-0.8 )^2 / 464^2 * 84,000 = 83,710.5945303210463 gram sent to here 1E1j2uMTLfXMDM6YZrWSnXPneRsVbht8k3 If my answer satisfy you ;D Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: JLynn171 on July 23, 2015, 03:43:56 PM 0.64/ 6,371,000 =4077440
4077440x84,000= 342504960000gs? Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: notbatman on July 23, 2015, 04:44:36 PM Let me try ( 464-0.8 )^2 / 464^2 * 84,000 = 83,710.5945303210463 gram sent to here 1E1j2uMTLfXMDM6YZrWSnXPneRsVbht8k3 If my answer satisfy you ;D The centripetal force that counters the gravitational force has been reduced to a fraction of what it normally is. How can they (the average person) possibly weigh 0.3 kg less? 0.64/ 6,371,000 =4077440 4077440x84,000= 342504960000gs? You got a nice big number so you're going in the right direction but, where did you get '0.64' from? Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: notbatman on July 23, 2015, 04:46:08 PM Tip: the SI unit for force (in this case centripetal force) is the Newton. 1 newton = 101.971621 grams.
Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: JLynn171 on July 23, 2015, 05:02:55 PM Let me try ( 464-0.8 )^2 / 464^2 * 84,000 = 83,710.5945303210463 gram sent to here 1E1j2uMTLfXMDM6YZrWSnXPneRsVbht8k3 If my answer satisfy you ;D The centripetal force that counters the gravitational force has been reduced to a fraction of what it normally is. How can they (the average person) possibly weigh 0.3 kg less? 0.64/ 6,371,000 =4077440 4077440x84,000= ? You got a nice big number so you're going in the right direction but, where did you get '0.64' from? 3358826275.7929483145119366102849gs 0.8^2?= 0.64? Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: notbatman on July 23, 2015, 07:09:38 PM Using the information you've provided I've formatted your response to make it readable...
Quote from: JLynn171 0.8^2 = 0.64 0.64 / 6371000 = 4077440 4077440 * 84000 = 342504960000 342504960000 / 101.971621 = 3358826275.7929483145119366102849 grams (velocity^2 / radius) * mass = 342,504,960,000 grams 342,504,960,000 / 101.971621 = 3,358,826,275.7929483145119366102849 newtons So based on your response your answer is about 3,358,826,276 newtons or 342,504,960 kg, is that correct? We're getting close but I don't think we've arrived at a BTC reward yet... Problems I can see: a) your giving results from your force formula in grams not newtons. b) your mass is still incorporating a velocity of 464 m/s to get 84 kg. c) many other issues. Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: notbatman on July 23, 2015, 07:49:05 PM Tip: The SI unit of mass is the kilogram. Mass is not the same as weight.
Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: GSLynn on July 23, 2015, 09:48:56 PM Using the information you've provided I've formatted your response to make it readable... Quote from: JLynn171 0.8^2 = 0.64 0.64 / 6371000 = 4077440 4077440 * 84000 = 342504960000 342504960000 / 101.971621 = 3358826275.7929483145119366102849 grams (velocity^2 / radius) * mass = 342,504,960,000 grams 342,504,960,000 / 101.971621 = 3,358,826,275.7929483145119366102849 newtons So based on your response your answer is about 3,358,826,276 newtons or 342,504,960 kg, is that correct? We're getting close but I don't think we've arrived at a BTC reward yet... Problems I can see: a) your giving results from your force formula in grams not newtons. b) your mass is still incorporating a velocity of 464 m/s to get 84 kg. c) many other issues. lol ok i will break out pen and paper now i been trying do it in my head all day Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: GSLynn on July 24, 2015, 01:16:06 AM ok so mass=x 84,000=x(464^2)/6,371,000 ----
x/101= 25,202 0.64 / 6371000 = 4077440 4077440 *25,202 = 102759642880g's or 102,759,642.880Kg ^^^ I think *** am i getting closer? Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: BAGOBO on July 24, 2015, 02:25:57 AM So what are you looking for ?
The mass shift or looking for the exact mass ? How about 0.8^2 / 464^2 * 84,000 = 0.2497026 gram Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: googleindo on July 24, 2015, 02:52:59 AM this is going to be games and rounds section sir.
i dont like math sigh .... Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: Justin00 on July 24, 2015, 04:56:54 AM pie squared - 2
let me know when you need my addy for reward. Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: lili song on July 24, 2015, 08:00:46 AM Centripetal_force 1 = centripetal_force 2
84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m mass = 84,290.4 g Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: notbatman on July 24, 2015, 05:05:45 PM Centripetal_force 1 = centripetal_force 2 84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m mass = 84,290.4 g So you're saying that the force on an average person from being whipped around at 464 meters per second is 290.4 grams? :D There's a ride at PlayLand called the Gravitron, you should ride it sometime! Also, the only velocities that should be used here are 464 m/s and 0.8 m/s. Where on Earth did you get 463.2 m/s from? Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: notbatman on July 24, 2015, 05:06:50 PM pie squared - 2 let me know when you need my addy for reward. Let this spin for a bit... ;) Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: notbatman on July 24, 2015, 08:14:41 PM So what are you looking for ? The mass shift or looking for the exact mass ? "...the weight..." Quote How about 0.8^2 / 464^2 * 84,000 = 0.2497026 gram You're short a few kg. Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: BAGOBO on July 25, 2015, 06:08:47 AM here's another attempt
r = 6,371,000 m v = 464 m/s m = 84,000 gr cf = m* v^2 / r = 84,000 gr * (464 m/s)^2 / 6,371,000 m =2,838.62251 gr.m/s^2 if v = 0.8 m/s then cf = m * v^2 / r m = cf * r / v^2 = 2,838.62251 gr.m/s^2 * 6,371,000 m / (0.8 m/s)^2 = 28,257,600,000 gr Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: notbatman on July 25, 2015, 07:47:33 AM While I've provided the average weight of a person in grams and requested the answer in grams the SI unit for mass is the kilogram.
Also keep in mind the fact that mass is not the same as weight. Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: ndnh on July 25, 2015, 07:48:17 AM Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s? Earth's radius at the equator: 6,371,000 m Earth's velocity at the equator: 464 m/s Average weight of a person: 84,000 g formula: centripetal_force = mass * velocity^2 / radius Please provide the answer in grams and show your work! 84000 * 0.8^2/6,371,000 = 0.00843823575 grams. Er.. wait.. something is wrong? Edit: Re-attempt. I assume that weight and mass in both cases are equally proportional. Honestly, I know nothing Physics. ;D OH okay, so this centripedal force acts against gravity? I see. Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: Gleb Gamow on July 25, 2015, 07:51:00 AM While I've provided the average weight of a person in grams and requested the answer in grams the SI unit for mass is the kilogram. Also keep in mind the fact that mass is not the same as weight. This is fucked up on so many levels! Does this now mean that I wasn't even close with my answer? If so, that really makes me out to look like a fool. :'( Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: ndnh on July 25, 2015, 08:03:14 AM Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s? Earth's radius at the equator: 6,371,000 m Earth's velocity at the equator: 464 m/s Average weight of a person: 84,000 g formula: centripetal_force = mass * velocity^2 / radius Please provide the answer in grams and show your work! 84000 * 0.8^2/6,371,000 = 0.00843823575 grams. Er.. wait.. something is wrong? Edit: Re-attempt. I assume that weight and mass in both cases are equally proportional. Honestly, I know nothing Physics. ;D OH okay, so this centripedal force acts against gravity? I see. At the Equator. Quote If you weighed 100 pounds at the north pole on a spring scale, at the equator you would weigh 99.65 pounds, or 5.5 ounces less. 84,000 * 9.79/0.00843823575 = 97456390.6916 grams. ;D Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: notbatman on July 25, 2015, 03:33:09 PM ... we'll apply the calculation used to answer this skill testing question to the north pole as a test of its validity later...If you weighed 100 pounds at the north pole on a spring scale, at the equator you would weigh 99.65 pounds, or 5.5 ounces less. Quote 84,000 * 9.79/0.00843823575 = 97456390.6916 grams. ;D a) The SI unit for mass is the kilogram. b) Where do you get '9.79' from? c) Again, where do you get '0.00843823575' from? d) How is the result of your calculation in grams and not newtons? e) Many other issues. Title: Re: Skill Testing Math Question -- 0.08 BTC Reward Post by: notbatman on July 25, 2015, 03:34:07 PM I've increased the reward to 0.08 BTC.
Title: Re: Skill Testing Math Question -- 0.08 BTC Reward Post by: ralle14 on July 25, 2015, 05:58:42 PM given: if the equatorial velocity was slowed to 0.8 m/s?
Earth's radius at the equator: 6,371,000 m Earth's velocity at the equator: 464 m/s Average weight of a person: 84,000 g formula: centripetal_force = mass * velocity^2 / radius 84,000 * (464-0.8/464)^2 / 6,371,000 = 2838.60141269 newtons 2838.60141269 *101.97 = 289452.186052 grams this is my try :) i think im missing something Title: Re: Skill Testing Math Question -- 0.08 BTC Reward Post by: notbatman on July 25, 2015, 06:12:43 PM given: if the equatorial velocity was slowed to 0.8 m/s? Earth's radius at the equator: 6,371,000 m Earth's velocity at the equator: 464 m/s Average weight of a person: 84,000 g formula: centripetal_force = mass * velocity^2 / radius 84,000 * (464-0.8/464)^2 / 6,371,000 = 2838.60141269 newtons 2838.60141269 *101.97 = 289452.186052 grams this is my try :) i think im missing something a) The SI unit for mass is the kilogram. b) You've only attempted to calculate part of the problem. c) Other issues with the part you've attempted. Title: Re: Skill Testing Math Question -- 0.08 BTC Reward Post by: jambola2 on July 25, 2015, 07:53:21 PM Reduction in weight = Change in centripetal force = m(V^2)/r - m(v^2)/r = 84(464^2 - 0.8^2)/6,371,000 = 2.83861407
However, since centripetal force is in Newtons, this is in Newtons. Converting it to mass equivalent with the number you gave (1 newton = 101.971621 grams) 2.83861407 Newtons * 101.971621 Grams per newton = 289.458078111 Grams heavier Wait what really? So less? Let's look at the equation of centripetal force again. Let's calculate the total centripetal force for any person Mass in kg * (velocity)^2 / Radius 84 KG * 464 * 464 / 6,371,000 The thing you notice is that the radius is so large it makes the speed look extremely tiny. Quote So you're saying that the force on an average person from being whipped around at 464 meters per second is 290.4 grams? :D There's a ride at PlayLand called the Gravitron, you should ride it sometime! Also, the only velocities that should be used here are 464 m/s and 0.8 m/s. Where on Earth did you get 463.2 m/s from? Yes it is so low! The author of that response made a mistake (464^2 - 0.8^2) =/= (463.2^2) , but was correct for the rest. I'm not sure if you're playing a prank on the forums, but that's what happens when something is inversely proportional to the radius of something, and that radius is HUGE. The fact that someone noted that this was consistent with NASA calculations regarding weight at the poles hints that your idea is wrong. Leaving margin for error, I can say with certainty that the weight of the average person will be approximately 826.59 Newtons. (YES, Google it. The SI unit of weight is Newton, not mass) Or, to use your extremely weird scale of stating weights in mass equivalent, 84,289.46 grams. Can't vouch for accuracy, may vary between 84,280 and 84,300 grams. And here's my address: 1FRkoJDy8CwZ84RSeMs2tCEKBdVfHu32Ra Title: Re: Skill Testing Math Question -- 0.08 BTC Reward Post by: notbatman on July 25, 2015, 08:33:59 PM Reduction in weight = Change in centripetal force = m(V^2)/r - m(v^2)/r = 84(464^2 - 0.8^2)/6,371,000 = 2.83861407 However, since centripetal force is in Newtons, this is in Newtons. Converting it to mass equivalent with the number you gave (1 newton = 101.971621 grams) 2.83861407 Newtons * 101.971621 Grams per newton = 289.458078111 Grams heavier Wait what really? So less? Let's look at the equation of centripetal force again. Let's calculate the total centripetal force for any person Mass in kg * (velocity)^2 / Radius 84 KG * 464 * 464 / 6,371,000 The thing you notice is that the radius is so large it makes the speed look extremely tiny. Quote So you're saying that the force on an average person from being whipped around at 464 meters per second is 290.4 grams? :D There's a ride at PlayLand called the Gravitron, you should ride it sometime! Also, the only velocities that should be used here are 464 m/s and 0.8 m/s. Where on Earth did you get 463.2 m/s from? Yes it is so low! The author of that response made a mistake (464^2 - 0.8^2) =/= (463.2^2) , but was correct for the rest. I'm not sure if you're playing a prank on the forums, but that's what happens when something is inversely proportional to the radius of something, and that radius is HUGE. The fact that someone noted that this was consistent with NASA calculations regarding weight at the poles hints that your idea is wrong. Leaving margin for error, I can say with certainty that the weight of the average person will be approximately 826.59 Newtons. (YES, Google it. The SI unit of weight is Newton, not mass) Or, to use your extremely weird scale of stating weights in mass equivalent, 84,289.46 grams. Can't vouch for accuracy, may vary between 84,280 and 84,300 grams. And here's my address: 1FRkoJDy8CwZ84RSeMs2tCEKBdVfHu32Ra Best attempt yet... but, I need some time to go over it and some sleep. If I can't poke any holes in it I'll send the 0.08 BTC. EDIT: Reviewing the other posts it looks like 'lili song' (19jD5PfF5TqeF5xJWa5US2rM7GHVr5hdX) may have beaten you to it especially with your margin of error... Centripetal_force 1 = centripetal_force 2 84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m mass = 84,290.4 g Oh, my precious Bitcoins, this isn't looking good for me. 'lili song' did however post while the reward was 0.01 BTC. I'm still going over the numbers... Title: Re: Skill Testing Math Question -- 0.08 BTC Reward Post by: jamrud on July 25, 2015, 08:56:12 PM its too hard :D
84000*464^2/6,371,000 2838.622 G Title: Re: Skill Testing Math Question -- 0.08 BTC Reward Post by: ridery99 on July 25, 2015, 09:13:08 PM Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s? Earth's radius at the equator: 6,371,000 m Earth's velocity at the equator: 464 m/s Average weight of a person: 84,000 g formula: centripetal_force = mass * velocity^2 / radius Please provide the answer in grams and show your work! It's 4567,85 g Title: Re: Skill Testing Math Question -- 0.08 BTC Reward Post by: Panzzer on July 25, 2015, 09:22:33 PM Lilisong answer answer is correct?
Title: Re: [SOLVED] Skill Testing Math Question -- 0.08 BTC Reward Post by: notbatman on July 25, 2015, 10:11:47 PM 'lili song' is the winner! (19jD5PfF5TqeF5xJWa5US2rM7GHVr5hdX) <-- 0.07 BTC
'jambola2' is the runner up. (1FRkoJDy8CwZ84RSeMs2tCEKBdVfHu32Ra) <-- 0.01 BTC I decided not to be a cheap ass and reward the entire 0.08 BTC but, lili song's works sucks so jamola2 gets 0.01 BTC of her reward. Technically lili song posted while the reward was 0.01 BTC so consider yourself lucky. Title: Re: Skill Testing Math Question -- 0.08 BTC Reward Post by: notbatman on July 25, 2015, 10:12:17 PM Title: Re: [SOLVED] Skill Testing Math Question -- 0.08 BTC Reward Post by: notbatman on July 25, 2015, 11:59:35 PM Don't think this proves that the Earth is a spinning globe, it doesn't. It does however prove that I'm
NASA and the rest of the establishment are a den of vipers. Their eggheads have however defiantly crunched all the numbers. I won't make the same mistake twice. Math is the only science you can be 100% sure of the results and I'm going to find a hole in their global conspiracy. The Earth is flat! Title: Re: [SOLVED] Skill Testing Math Question -- 0.08 BTC Reward Post by: Gleb Gamow on July 26, 2015, 02:28:31 AM Don't think this proves that the Earth is a spinning globe, it doesn't. It does however prove that I'm NASA and the rest of the establishment are a den of vipers. Their eggheads have however defiantly crunched all the numbers. I won't make the same mistake twice. Math is the only science you can be 100% sure of the results and I'm going to find a hole in their global conspiracy. The Earth is flat! I was wonder why YouTube was suggesting me the likes of Saudi Cleric Was Right: USA Faked Moon Landing - Coriolis Effect Fraud (https://www.youtube.com/watch?v=oCSvx5ONIB8) lately. It's because I commented on this thread. Bad, notbatman! ;) Title: Re: [SOLVED] Skill Testing Math Question -- 0.08 BTC Reward Post by: lili song on July 26, 2015, 08:28:48 AM 'lili song' is the winner! (19jD5PfF5TqeF5xJWa5US2rM7GHVr5hdX) <-- 0.07 BTC 'jambola2' is the runner up. (1FRkoJDy8CwZ84RSeMs2tCEKBdVfHu32Ra) <-- 0.01 BTC I decided not to be a cheap ass and reward the entire 0.08 BTC but, lili song's works sucks so jamola2 gets 0.01 BTC of her reward. Technically lili song posted while the reward was 0.01 BTC so consider yourself lucky. Woah ::) I can't believe it that I'm the winner Thanks notbatman ;D and thanks for jambola2 for clarification (since english is not my mother tongue, I can't argument just like you did. ) Title: Re: [SOLVED] Skill Testing Math Question -- 0.08 BTC Reward Post by: jambola2 on July 26, 2015, 02:49:17 PM 'lili song' is the winner! (19jD5PfF5TqeF5xJWa5US2rM7GHVr5hdX) <-- 0.07 BTC 'jambola2' is the runner up. (1FRkoJDy8CwZ84RSeMs2tCEKBdVfHu32Ra) <-- 0.01 BTC I decided not to be a cheap ass and reward the entire 0.08 BTC but, lili song's works sucks so jamola2 gets 0.01 BTC of her reward. Technically lili song posted while the reward was 0.01 BTC so consider yourself lucky. Woah ::) I can't believe it that I'm the winner Thanks notbatman ;D and thanks for jambola2 for clarification (since english is not my mother tongue, I can't argument just like you did. ) Yup, you owe me one for proving you right ;) And notbatman, shoot me a PM the next time you're hosting this sort of stuff. This was fun, and the free BTC for a few minutes of work was more fun :P Title: Re: [SOLVED] Skill Testing Math Question -- 0.08 BTC Reward Post by: sukamasoto on July 27, 2015, 06:04:05 AM i want to reclamation
From your question, you are looking for weight in grams. in physics weight are united with Newton, not in grams. but in real world sometimes people call mass as weight. Quote from: lili song on July 24, 2015, 08:00:46 AM Centripetal_force 1 = centripetal_force 2 84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m mass = 84,290.4 g and u claimed this answer as the winner. So the answer you are looking is mass not weight. from this https://en.wikipedia.org/wiki/Weight is the description of weight physics and this https://en.wikipedia.org/wiki/Mass is the description of mass in physics if you are reading it carefully, in paragraph 2 of description of mass you will read "An object on the Moon would weigh less than it would on Earth because of the lower gravity, but it would still have the same mass". so whenever you are, whatever the velocity or radius of the planet your mass will still same, but your weight will change. and I want to straighten our concept about centripetal force. from lili song answer centripetal force 1 = centripetal force 2. This is completely wrong! As far as i know centripetal force change as the related variable change. Sorry, lili, i did not mean to blame you. this for the reference of the centripetal force description http://www.regentsprep.org/regents/physics/phys06/bcentrif/default.htm So, the answer should still same mass(weight) 84,000 grams Title: Re: Skill Testing Math Question -- 0.01 BTC Reward Post by: ndnh on July 27, 2015, 06:58:59 AM btw, that is already accounted for here:
Quote Leaving margin for error, I can say with certainty that the weight of the average person will be approximately 826.59 Newtons. (YES, Google it. The SI unit of weight is Newton, not mass) Or, to use your extremely weird scale of stating weights in mass equivalent, 84,289.46 grams. Can't vouch for accuracy, may vary between 84,280 and 84,300 grams. To clarify, (I know some basic Physics) Mass is universal. Same everywhere. SI unit is kg - kilogram. Weight varies. SI unit is Newton. This one is a little weird answer: Centripetal_force 1 = centripetal_force 2 84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m mass = 84,290.4 g I just corrected that here: ;D Centripetal_force 1 = centripetal_force 2 84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m weight (in grams) = 84,290.4 g The question clearly states: Quote Please provide the answer in grams and show your work! There is no problem is weight is stated in grams just because SI unit happens to be Newtons. jambola2 is right. and this should be: ;D Title: Re: [SOLVED] Skill Testing Math Question -- 0.08 BTC Reward Post by: jambola2 on July 27, 2015, 07:19:42 AM i want to reclamation From your question, you are looking for weight in grams. in physics weight are united with Newton, not in grams. but in real world sometimes people call mass as weight. Quote from: lili song on July 24, 2015, 08:00:46 AM Centripetal_force 1 = centripetal_force 2 84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m mass = 84,290.4 g and u claimed this answer as the winner. So the answer you are looking is mass not weight. from this https://en.wikipedia.org/wiki/Weight is the description of weight physics and this https://en.wikipedia.org/wiki/Mass is the description of mass in physics if you are reading it carefully, in paragraph 2 of description of mass you will read "An object on the Moon would weigh less than it would on Earth because of the lower gravity, but it would still have the same mass". so whenever you are, whatever the velocity or radius of the planet your mass will still same, but your weight will change. and I want to straighten our concept about centripetal force. from lili song answer centripetal force 1 = centripetal force 2. This is completely wrong! As far as i know centripetal force change as the related variable change. Sorry, lili, i did not mean to blame you. this for the reference of the centripetal force description http://www.regentsprep.org/regents/physics/phys06/bcentrif/default.htm So, the answer should still same mass(weight) 84,000 grams As ndnhc pointed out, and as I already said in my answer, I gave it in mass equivalent. What do I mean by mass equivalent? The weight is 826.59 N, but it is the same weight of an object with mass of 84,289.46 grams on the surface of the earth. OP asked for it in grams, so I gave it in mass equivalent. Read my answer, it is different from lili's answer, but straightens out a lot of things he said, better explaining them. He has a valid reason for being unable to explain it too, as English is not his first language either. |