Bitcoin Forum

The Wings Of Trust - 42x60cm 16,5'x23,6' (Error piece) + CERTIFICATE OF AUTHENTICITY 1of12

- Choose a number between 00 - 50 (no random)



LIST:

00 - Darker45
01 - dirtbike
02 - doblezero
03 - Steeley
04 - BTCLiz
05 - 5tift
06 - Cryptogreatdane
07 - thiago007
08 - heisty
09 - sweeteye
10 - MoparMiningLLC
11 - The_Crypto_Kid
12 - icopress
13 - geo
14 - Danydee
15 - Snowlynx
16 - krogoth
17 - haloxon
18 - bullrun2020bro
19 - PawGo
20 - sunnybwoy
21 - xSlyy
22 - LitLitBit
23 - est2013
24 - examplens
25 - Ratimov
26 - Frank AlpenCoin
27 - Dernoste
28 - Yabes
29 - owlcatz
30 - XYZo
31 - Vizique
32 - PontiusTP
33 - 2stout
34 - GazetaBitcoin
35 - Remsjack
36 - -doubleU-
37 - noorman0
38 - Saxoshi
39 - m2017
40  - sam00
41 - delfastTions
42 -  tweetious
43  - cygan
44 - Selassiesoildier
45 - Mbitr
46 - HedgeFx
47 - Mortare
48 - bullion-n-btc
49 - bitbollo
50 - JanEmil

For more Mx12 Bitcoin art here: https://bitcointalk.org/index.php?topic=5362071.0

Good Luck!

42 - tweetious

Please and thank you!

02-doblezero
Thanks

38- Saxoshi

Thanks

01-dirtbike

cheers! Thanks for the raffle!

27 - Dernoste
Thx

Thank you for this raffle!

35 - Remsjack, please!

76 - MoparMiningLLC

Oops stops at 50

Will take 10 - MoparMiningLLC

Thanks!

11 - The_Crypto_Kid please - and thank you!  ;D

20 -sunnybwoy
Thanks!

Awesome!  Thanks.

13 - geo

50 - JanEmil
Merry Christmas

7 please Thank you

05 -5tift
Thanks!

33 - 2stout

Thx!

03

Thank you
Steeley

#36 - -doubleU-

Thank you  8)

31 - Vizique

Cheers!
Viz

16 krogoth  thanks

Feeling lucky with number #40 today ;)
Thanks for the giveaway mx12.levins!

15 - Snowlynx

Thank you!

21 for me please! Good luck everyone!

4 - BTCLiz

Thanks!

19 - PawGo

Thanks!

Ill take 05 please and thank you

05 Already taken :) Gave you number 06

41 - delfastTions

Thanks!

14 - Danydee

Thank you :D

43 - cygan
thanks bro

23 - est2013

Thanks  :)

08 please, heisty

thank you!

18 - bullrun2020bro

Thanks a lot and good luck to all participants! Merry Christmas everyone!  :)

Thankyou  :)

45 - Mbitr please

Merry Xmas to all and good luck  :)

48 bullion-n-btc

49 -bitbollo
thank you

30 XYZo : Thanks

46 HedgeFx

Thank you!

09
thanks!

12 - icopress

Thanks!  :D

44: Selassiesoildier

Blessings

00- Darker45

Please and thank you! Merry Christmas! :D

37 - noorman0

ty

29 - owlcatz

Thanks! :D

Wow great work!

09 - LitLitBit

Thanks!

32 - PontiusTP

Number 9 already taken
22 - LitLitBit

#39 - m2017
Let's try our luck.

47 - Mortare
thnx

24 - examplens

26 - Frank AlpenCoin
thank you

28-Yabes, Last spot?

Thank you

"IN 10 MINUTES WILL ANNOUNCE WINNER"

Congratulations number 08 - heisty :) BTCBTCBTC You are the winner!!!

For information I used Python to find the winner:
https://i.ibb.co/WWCK1W7/Screen-Shot-2021-12-21-at-18-46-10.png (https://ibb.co/BVksRVv)
https://i.ibb.co/qnCVVVq/Screen-Shot-2021-12-21-at-18-45-07.png (https://ibb.co/DbYTTTc)

I'll gladly accept the win but agree that the random number generator is a bit unconventional.  Thank you for hosting this raffle, I've replied to your PM.   

Happy holidays all. ;D

Is it just me or does the random number generator only pick a number between 1 and 10.. not trying to be a bitter loser but 40 people were excluded?

Just eyeballing the script it might be the case that only numbers 1-10 were considered...  If this is what happened I'd be fine with picking a future block to ensure a fair re-roll.

If you put the following Code into a Python interpreter

import random
print(random.randrange(1,10))

then you will print a random integer (a full number) from 1 to 9.
The 1 is included and the 10 isn't.
I also think that's a bit "unconventional" for a raffle with 50 people :D

You could go ahead and use the following code:

import random
print(random.randrange(1,51)

This will include 1-50.
As others have mentioned before. You could also pick a bitcoin block in the future and let the last 2 digits of the hash of the block decide the winner. If its above 50, just go with the next block.
Just make sure to announce the block you chose before it is mined ;)

worth noting is that the spot "00" was also included so a range of 1-51 would exclude that individual as well.  This was really 51 participants and only 9 were actually in the drawing.

Oh,
I will create another raffle as well and use blockchain this time. I never had exp with using hash/blockchain for raffles. Can you tell me how the raffle like this work? We have 50 or 100 numbers how you will pick up the winner? Let's say it was Bitcoin Block 715,145 00000000000000000008cfd241b914ea2e441a0529dd47c549a33220ec852a82

---

I have recorded video as well, the screenshot is only example.

import random
print(random.randrange(0,50))

If you are okey with it, we can re-roll picking up one of the next blocks, your choice BTC

That means 82 is the winner.
What is taken is the last 2 digits of the hash number (letters excluded).

Another example, in case block number 715144 has hash 00000000000000000008a226f5aa338d009b2decd1e6094cc6645bfc0f9bb4fa

Then, 94 is the winner

Got it thanks! Please let me know if you are okey Heisty with re-roll

Noorman0 forgot to mention that if the winning number does not match any number that was chosen by one of the participants, then the winner is determined by the means of the next block, (and so on until a winner is found). Anyway, you should probably wait for heisty's answer, (wouldn't he mind) since this is a free giveaway and only you have the right to decide how the winner is selected, unless of course you are talking about another prize drawing  ;)

Yep, cool with me!

Bitcoin Block 715155

---

 Bitcoin Block 715,155
00000000000000000005361522a4ae9050cfda787f635c12f26be14d5ba73288
 No winner
Next Bitcoin Block ...

Congratulations! / https://blockchair.com/bitcoin/block/715156

Thanks to MX for the raffle and heisty for the surrender. Class act, both of you.

congrats to Mortare! and thank you for the raffle mx12!

Wow, this is reay cool. Thank you very much!