Sorry about that. I was too eager to send coins. I should have probably made a post confirming that I would be doing the transaction, before sending bitcoins.

There have been instances in the past (like this) when I had a confirmed deal and then somebody else entered. I didn't feel good about it all.

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I am not familiar with steam accounts. Would you be willing to buy the game at a particular price in case of a default? I would be okay to give the loan if the collateral can be sold for 100%+ of the loan. I am willing to take risk on the interest portion.




Just curious - How do you plan to get BTC to repay this loan?

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Gentle reminder.
Repayment of loan due today.
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I think you should order the articles in such a way
1) RBI releases, articles containing comments made by RBI
2) Articles in mainstream Indian publications (Economic Times, Business Standard, Hindu, etc)
3) Articles in crypto magazines.

The reason I say this is because the credibility of crypto publications in the eyes of the RBI may be low.

Some comments made by Raghuram Rajan on Bitcoin can be found here
http://profit.ndtv.com/news/economy/article-there-are-concerns-about-crony-capitalism-raghuram-rajan-718524

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On a lighter note, you should take care of your decimals.
The OP talks about 0.66 BTC for the last 2 problems (instead of 0.066) 

Thanks! That was helpful

(a)
(5,0) - Xo
(17,0) - Xo
(18,0) - Xe

To check the solution, we can list down the antecedents of (5,0)
(4,1), (3,0), (2,1), (1,0), (0,1)
So (5,0) has 5 antecedents and our answer is correct.

So the element (x,0) can be defined to fall under
Xe:  x is even
Xo: x is odd
Xi is a null set

(b) Similarly (y,1) can be define to fall under
Ye: y is even
Yo: y is odd
Yi is a null set

(c) The bijection is defined as
F(x,0) = (x+1,1), if x is even
F(x,0) = (x-1,1), if x is odd.

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Could you help me with the notation for the third question.
What is Xe, Xo, Xi?
Have they been defined elsewhere?

Here goes my attempt at proposition 6.7

Proof that the function is injective
Let F(S) = F(T) = A (which belongs to P(X))

Given the definition of F, we note that S is defined by
S(x) = 1, for all x belongs to A
S(x) = 0, for all x does not belong to A

We also note that since F(T) = A, T is defined by
T(x) = 1, for all x belongs to A
T(x) = 0, for all x does not belong to A

Since the definitions of S and T are identical, we conclude that S = T

Proof that the function is surjective
Let A belong to P(X)
Define the function J from X into |^-2^-| such that
J (x) = 1, for all x belongs to A
J (x) = 0, for all x does not belong to A

We note that F(J) = A, for any A
Hence F is surjective.

Since F is injective and surjective, it is bijective.

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Some small clarifications with respect to the first question

1) What is under your fingertips in the scanned image?
2) Does |^-2^-| indicate the set with just 2 elements {0,1}?
3) Is P(X) defined elsewhere?