This is the final private key in decimal:126272244427365764086102017718794198001099243823071433146875 =957496696762772407663*237871847045914904726285415*554405551875,

Can someone explain how Phemex got from this concatenated stage: 957496696762772407663 - 237871847045914904726285415 - 554405551875
(The 3 number strings we were tasked to discover from each of the 3 steps, although the third step was never mentioned or hinted at. i.e. - You had to guess you were looking for a 12 digit number to add on to the end using a word from the portrait which was converted from the obscure Ripple alphabet) and converting it into the Private Key Decimal number that = 126272244427365764086102017718794198001099243823071433146875 ?

Basically, how is the 3 string number converted to that decimal number and how is that decimal number converted into a WIF and Hex? Is Java the only way?
It can't be done on your bog standard Brainwallet website at that stage. Only once you have the WIF (Compressed or uncompressed) and/or the Hex number can you use it to find the corresponding correct Public Keys on Brainwallet or Bitcoinpaperwallet etc.