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1  Local / Other languages/locations / Re: Universal language - mathematics on: May 06, 2013, 09:02:16 PM
1 = 0,9(recurring)

proof:

let x be equal to 0,9 (recurring)
10x = 9,9 (recurring)
10x - x = 9x = 9,9 (recurring) - 0,9 (recurring) = 9
9x = 9
x = 1
0,9 (recurring) = x = 1
0,9 (recurring) = 1  Tongue
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