Understood, and I agree. I plan on playing for a bit, likely next week, and will then post my spreadsheet with auto calculations to share (updating it before I do with next round of gameplay). Not selling, just sharing. It doesnt integrate into PD at all, all it does is visualize betting strategies, took me a while to get the rounding patterns correct that PD uses, sometimes its Round Up, sometimes Round Down, and it does this at different decimal points depending on the variable its calculating.
Having this down really helps show the odds of "At 2.5 X Payout what are the odds of rolling 5000 rolls before hitting a streak that would bust to insufficient funds". It also factors back into the equation average per roll winnings into your BankRoll.
It works well when you use betting strategies that have a bust level of 1 in 800,000 rolls or greater. The higher the odds of busting, an odd multiplier comes into play I have yet to figure out.
Meaning if you played a AutoBet round where based on bankroll you could survive 25 consecutive losses based on starting bet, increase on loss, and payout factor, etc - and that 25 loss streak had a 1 in 1,000,000 chance in happening - the same (at least from what I can tell) is not true for the same odds (1 in 1,000,000) where the streak is only 8 deep.
Meaning odds aside, you will fare better with a larger depth regardless of identical odds.
If you dont believe me, try this simulation:
BankRoll: 0.05
PayOut: 2.25 X
Increase on Loss: 110%
Starting Bet: 0.00000002
Under this scenario, the odds of busting according to my tables are you would bust at 20 Consecutive Losses. The Odds of that happening work out to an occurance rate of 1 in 2.17 Million Rolls. So with a 44% Chance of Winning on 1 Roll, the occurance odds of rolling 20 straight losses are 1 in 2,170,000.
Now that said running a second simulation, with a much shallower depth of busting, the same does not (at least from my experience) hold true.
BankRoll: 0.05
PayOut: 1.123 x
Increase on Loss: 800%
Starting Bet: 0.00000040
Under this scenario, the odds of busting according to my tables are you would bust at 6 Consecutive Losses. The Odds of that happening work out to an occurance rate of 1 in 2.17 Million Rolls. So with a 88.16% Chance of Winning on 1 Roll, the occurance odds of rolling 6 straight losses are 1 in 2,170,000.
However, the Second Scenario listed plays much riskier and will bust far sooner regardless of the math behind the rolls.
Unless my math is flawed... Feel free to chime in here if so.
CD
Having this down really helps show the odds of "At 2.5 X Payout what are the odds of rolling 5000 rolls before hitting a streak that would bust to insufficient funds". It also factors back into the equation average per roll winnings into your BankRoll.
It works well when you use betting strategies that have a bust level of 1 in 800,000 rolls or greater. The higher the odds of busting, an odd multiplier comes into play I have yet to figure out.
Meaning if you played a AutoBet round where based on bankroll you could survive 25 consecutive losses based on starting bet, increase on loss, and payout factor, etc - and that 25 loss streak had a 1 in 1,000,000 chance in happening - the same (at least from what I can tell) is not true for the same odds (1 in 1,000,000) where the streak is only 8 deep.
Meaning odds aside, you will fare better with a larger depth regardless of identical odds.
If you dont believe me, try this simulation:
BankRoll: 0.05
PayOut: 2.25 X
Increase on Loss: 110%
Starting Bet: 0.00000002
Under this scenario, the odds of busting according to my tables are you would bust at 20 Consecutive Losses. The Odds of that happening work out to an occurance rate of 1 in 2.17 Million Rolls. So with a 44% Chance of Winning on 1 Roll, the occurance odds of rolling 20 straight losses are 1 in 2,170,000.
Now that said running a second simulation, with a much shallower depth of busting, the same does not (at least from my experience) hold true.
BankRoll: 0.05
PayOut: 1.123 x
Increase on Loss: 800%
Starting Bet: 0.00000040
Under this scenario, the odds of busting according to my tables are you would bust at 6 Consecutive Losses. The Odds of that happening work out to an occurance rate of 1 in 2.17 Million Rolls. So with a 88.16% Chance of Winning on 1 Roll, the occurance odds of rolling 6 straight losses are 1 in 2,170,000.
However, the Second Scenario listed plays much riskier and will bust far sooner regardless of the math behind the rolls.
Unless my math is flawed... Feel free to chime in here if so.
CD
Your argument is invalid.
Every bet has its own chance of wining/losing.
The bet you make is nothing to do with the other you have made before.
You can lose 10 times in a row on a %90 winning chance game and believe me it can happen a lot more than 1/2900000 times.