I like traditional methods
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Yes, I think it was a payout from pool or something, because at pool statistics the value per mined block 279 was 0 (and it is correct with algorithm, because the reminder is 1.368). Got it! Thanks for the quick replies. Anyone can check if the algorithm works. From the blockchain we take blockHeight and diff. Example block 294 with diff 1.420. Then we divide 294 by 1.420 to get 207.0423. In order to get the reminder we need non-integer part of 207.0423 (which is 0.0423) and again multiply it by diff. So reminder is 0.0423*1.420 = 0.06 So this example shows that reward is if the reminder is also less than 0.1 Maybe the final algorithm generates the reward if... reminder is in (0.01,1)? Or just in (0,1)?
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Yes, I think it was a payout from pool or something, because at pool statistics the value per mined block 279 was 0 (and it is correct with algorithm, because the reminder is 1.368).
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So there's 10 billion total and half are not 0s right now. I'd expect it to be rarer than 5 billion.
I wrote it several times, that probability of hitting reward on block equals 1/diff for diff > 1 and 0.9 for diff < 1. The payout is 1, so even if the anomaly will occur EVERY time, then in order to generate 5 milions (not bilions) coins it would need 10 years. But if diff will quicky be higher than 2, then in the same period of time (10 years) there would be generate less that 2.5 milions For diff greater than 10 there would be about 500k coins (in the 10 years period).
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Can I get some clarification as to when rewards are sent out.
In the stats it says: "Block Reward = 0 (unless certain conditions are met, then Block Reward = 1)" {and} If remainder equals exactly 0 then reward is 10 If remainder equals exactly 100 then reward is 100
But later on under "How it works" it says: "...if the remainder of the block number (nHeight) divided by the difficulty falls between 1 and 0.1 or is exactly 0..."
So which is it? Exactly 100 or between 1-0.1?
Between 0.1 - 1. The case with exactly 10 or 100 will NEVER happen
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I wonder if this should have been solo mining only and no pools. The result of pool mining is that anyone can and will achieve something - e.g. as I said earlier in the thread I've pointed my laptop (<5 kh/s) at it for less than an hour and got 0.000256.
Ya looking at how things are going I think maybe i should of made it so the remainder should fall exactly on 0. But I think it is because the difficulty is low so more coins are going into circulation. When the difficulty rises so does the rarity of the coin. If the difficulty stays at 1 then every block will be an anomaly, if the difficulty is at 2 then every even numbered block becomes an anomaly. This I didn't expect but still makes the coin that much more unpredictable. You did not expected? Someone wrote it at the beginning of the thread and I also wrote it some posts above. The probability of hitting anomaly is about 1/diff, and for diff < 1 the anomaly accurs almost every time If the remainder fall exactly on 0, there would be ANY anomaly, because diff is double/float number, so the probability of hitting remainder 0 is EXACTLY 0. Oops ya you're right... I guess I meant that I didn't expect the diff to sit at ~1 for so long. So in order to make this coin more rare we would need more miners. Correct? Yes, exactly. Like I said, the probability of hitting reward on block is about 1/diff, so at diff=2, it is 1 per two block, at diff=5 it is 1 per 5 blocks, etc. And seting reward when reminder is exactly 0 has no sense, because reminder will NEVER be 0
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Btw how many "few coins" were premined?
Not much, just few. After the release block numbers where < 100 and I didn't watch from the start A more defined amount would be nice. Less than 5, 10, 250? I might be wrong, but I believe it was around 2 coins. Additionally - I can confirm that coins mined via the pool are now confirming! Good job guys! Yeah but still we don't have windows wallet to withdraw
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Btw how many "few coins" were premined?
Not much, just few. After the release block numbers where < 100 and I didn't watch from the start A more defined amount would be nice. Less than 5, 10, 250? I think that less than 10
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Btw how many "few coins" were premined?
Not much, just few. After the release block numbers where < 100 and I didn't watch from the start
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I wonder if this should have been solo mining only and no pools. The result of pool mining is that anyone can and will achieve something - e.g. as I said earlier in the thread I've pointed my laptop (<5 kh/s) at it for less than an hour and got 0.000256.
Ya looking at how things are going I think maybe i should of made it so the remainder should fall exactly on 0. But I think it is because the difficulty is low so more coins are going into circulation. When the difficulty rises so does the rarity of the coin. If the difficulty stays at 1 then every block will be an anomaly, if the difficulty is at 2 then every even numbered block becomes an anomaly. This I didn't expect but still makes the coin that much more unpredictable. You did not expected? Someone wrote it at the beginning of the thread and I also wrote it some posts above. The probability of hitting anomaly is about 1/diff, and for diff < 1 the anomaly accurs almost every time If the remainder fall exactly on 0, there would be ANY anomaly, because diff is double/float number, so the probability of hitting remainder 0 is EXACTLY 0.
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There is no way this is a rarer than 42 coin.
Depends on the "rare" deffinition That is true that the will be more CGA than 42 coins, but in the CGA case the "rareness" means that with diff increase the reward decrease and it is random in some sense It means that it is more difficult to obtain
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You right, but I think that diff will never be higher than the block number. The higher diff, the lower probability of hitting anomaly. At diff < 1 the anomaly occurs almost every time. The key thing will be also diff retarget. It is scheduled for 3 blocks but with some restrictions? Say max +15% and -50% or something like that?
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Yeah, you right. So probably the condition itself has some problem with comparision double/float such small numbers
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Try manualy check all values of: diff = GetDifficulty(); fmod(nHeight, diff); and condition fmod(nHeight, diff) > 0.0000001. Then you should be able to find what is wrong... Probably diff = GetDifficulty() is 0.
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Try to check manualy the value fmod(1,0.00024414) ? Maybe function fmod returns 0 if the true reminder is less than 0.00001. Sorry for multiply edits
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Hey! I'm a mathematician, what do you need to figure out?
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Code is almost finished! Generated first test anomaly yesterday. Don't have a release date yet so I'll keep you all posted! If your curious how the math will play out here is some ruff examples: So the formula is nHeight % diff. And the remainder needs to fall between 1 and 0.1 or equal exactly 0: In the example with block number 3 and difficulty 0.01, the remainder is 0 (not 0.01) so there is an anomaly Also a question to the devs: maybe it is a good idea to create a coin similar to Primecoin (Primecoin generates Cunningham chains of prime numbers and already has a few new records). Maybe it is possible an algorithm that, for example, generates zeros of Riemann zeta-function?
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Network hash has been going up..100mh…300mh..it even hit 1gh an hour ago. does anyone know something I don’t?
I don'nt know, but I have seen similar situations on some pools for other coins. I think that some big farm is skipping throught new altcoins, not listed on big exchanges, like Cryptsy... Or maybe it is Mr Cryptsy
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Yeah, seems like google translate. I did not use google translate. I lived in Poland for almost 10 years. In most cases google translate makes no sense. Translate this thread to polish on google translate and then check my thread. I'm native Polish. The translate looks good but there are a few mistakes. If you want I can send you some changes.
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250MH/s net hash rate Nice BatCoin
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