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1  Bitcoin / Bitcoin Discussion / Re: Simple question about Elliptic Curve Cryptography on: April 15, 2015, 04:59:47 PM
That will never happen for the group used in Bitcoin. That specific point, is not a point on the elliptic curve used by Bitcoin. Such a point, call it Q, would have order 2, i.e. 2Q = O, the point at infinity. However, the points on the elliptic curve Y^2 = X^3 + 7 over Fp form a cyclic group of order a huge prime (almost as large as p). Hence not divisible by 2 and therefore no elements of order 2.
2  Bitcoin / Development & Technical Discussion / Re: My Bitcoin Microsoft Visual C++ fork on: March 18, 2015, 05:10:34 PM
Great if you will do a version for VS2013.
I got past my previous issue thanks to your help. Currently I'm stuck on the qt build.
Btw when running your Tests, it reports memory leaks. Is that expected?
3  Bitcoin / Development & Technical Discussion / Re: My Bitcoin Microsoft Visual C++ fork on: March 17, 2015, 01:19:19 AM
Looks really good. Thanks.
Taking your code I have been able to build the libraries and bitcoind using VS2013. I had to disable USE_UPNP as I got link errors about missing symbols like _memicmp. How did you avoid that?
Another question, why do you have "cxxflags="-Zc:whar_t-" when building Boost?
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