Solo mining LTC keeps moving to new block - Normal?

[ditchmagnet]

I started solo mining yesterday and solved 2 blocks, but I noticed it just keeps grabbing a new block ever few minutes, so how can it take the time to solve one?  Is that what it is supposed to do?  I thought it was supposed to work a block till it was solved.  I am using cgminer on Windows 7 64bit.

[Etlase2]

You are building on a block chain, so your software updates when someone else finds a block so that you continue the chain. It doesn't hurt your ability to find new blocks if someone else found one. It's just another piece of random information added to the hash.

[ditchmagnet]

Ok, I was confused since I thought I was working on the "block" shown under the IP, and that keeps changing every time a new block is detected.  So am I actually continuing to work on my original block and the name changes?  I don't understand what is really happening.
https://i.imgur.com/jPdMh.jpg

[Revalin]

Yes that's normal. You always want to base the next block on the highest available one, so every time a new block is broadcast you start from there. This is not a setback because each new hash is as equally likely to solve it, so it's not like you're starting over.

If everyone kept working on the same old block we would still be on block #1, solving it over and over with ever increasing size.

[ditchmagnet]

OK, is that how bitcoin works too?  Cause I thought the reason a BTC pool would get stuck on  a round for so long was because they couldn't solve the block they had.

[Revalin]

Yes, it's the same as BTC.  A pool's round is until the pool solves a block and therefore has some reward to distribute. The pool will go through many blocks in a round until they get one.

On LTC you'll see the blocks go even faster because it's set up to average 2.5 minutes instead of 10.

[PandaMiner]

I've seen "new block detected" at 1 minute intervals every now and again, but it's rare. I even saw once two blocks within 2 seconds of each other, although that may have been due to a polling issue.