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Author Topic: Earth, cubes and bitcoins  (Read 1050 times)
remotemass (OP)
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January 04, 2013, 06:46:23 AM
 #1

Take the smallest perfect sphere that can contain the entire Earth and its crust, and atmosphere: and make it fit perfectly a giant cube. That cube will have side aproximately twice the radius of the Earth plus twice the altitude of the atmosphere= 2*6378100m+2*120000m=12,996,200m, so

2,195,073,963,105,128,000,000 meters cube. We can imagine our giant cube divided into this number of one meter cube cubes. The frontiers that we will have on the surface from its intersection with the cubes, I will call cells.
Logically, the number of cells is about the number of square meters of the Earth, despite the fact that the form and area of them will be very different from each other.
My challenging is the following, estimate the market value in BTC of each of these cubes and cells.
Google Earth doesn't feature that yet...
Are many of those cubes and cells valuable? Would many want to buy the cube at the center of the Earth?
What about cubes from the atmosphere?

{ Imagine a sequence of bits generated from the first decimal place of the square roots of whole integers that are irrational numbers. If the decimal falls between 0 and 5, it's considered bit 0, and if it falls between 5 and 10, it's considered bit 1. This sequence from a simple integer count of contiguous irrationals and their logical decimal expansion of the first decimal place is called the 'main irrational stream.' Our goal is to design a physical and optical computing system system that can detect when this stream starts matching a specific pattern of a given size of bits. bitcointalk.org/index.php?topic=166760.0 } Satoshi did use a friend class in C++ and put a comment on the code saying: "This is why people hate C++".
Phinnaeus Gage
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January 04, 2013, 06:54:40 AM
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Grandpappy used to say, cube an sphere and miners will hash a path your door.
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