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Author Topic: Seuntjie' Dice bot programmers mode discussion.  (Read 76976 times)
velesIII
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June 18, 2019, 02:19:50 PM
 #1201

Hello! Strategy for Dice bot
There is a great strategy that anyone can help write code.
The main bet is always 0.00000001 Satoshi randomized to less than 50.
We are waiting for the numbers <50 to drop out three times.
For example 75, 55, 51.
After that, increase the rate based on the balance
Balance / 2/2/2/2/2/2/2/2/2/2 ten times divided by two.
The resulting bet is played at <50, that is, we check the availability of the series.
As soon as the loss occurs, it drops out> 50.
Increase bid by * 2
____________________________________________________________
We bet on by less, if we win then continue with the bet to check the series to bet on> 50 before losing, and then we return to the main bet 0.00000001.
If we lose, we increase the bet by * 2 and again put on less.
If we win, we continue with the Balance / 2/2/2/2/2/2/2/2/2/2 bet divided by 2 again to check the series to be> 50 before losing, and then we return to the main bet 0.00000001.
Twice our bet did not win with an increase.
______________________________________________________________
Then, according to anology, we continue to increase the stakes and set it already at <50, too, if we lose 2 times.
We have 6 bids left until the deposit is drained.
They can be divided as you like. 3 bets> 50, 3 bets <50.
Or 1,2> 50.
In manual mode, the strategy shows excellent results.
But painful tiring. Who can help?
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June 19, 2019, 10:32:18 PM
 #1202

I'm sorry... but I don't really understand the strategy as you have explained it.
The main bet is always 0.00000001 Satoshi randomized to less than 50.
We are waiting for the numbers <50 to drop out three times.
For example 75, 55, 51.
After that, increase the rate based on the balance
Balance / 2/2/2/2/2/2/2/2/2/2 ten times divided by two.
The resulting bet is played at <50, that is, we check the availability of the series.
As I understand it, you're min-betting with 50% chance (low) until you get 3 losses in a row? Then you divide your balance in half 10 times... effectively (balance / 2^10) => (balance / 1024)... and make that your bet amount... while still betting "low" (< 50)?


But then I get very lost here:
Quote
As soon as the loss occurs, it drops out> 50.
What do you mean "it drops out> 50"? Huh


Quote
Increase bid by * 2
____________________________________________________________
We bet on by less, if we win then continue with the bet to check the series to bet on> 50 before losing, and then we return to the main bet 0.00000001.
If we lose, we increase the bet by * 2 and again put on less.
If we win, we continue with the Balance / 2/2/2/2/2/2/2/2/2/2 bet divided by 2 again to check the series to be> 50 before losing, and then we return to the main bet 0.00000001.
Twice our bet did not win with an increase.
As far as I can understand here... you're saying we bet "low" until we win (increasing by *2)... If win then continue to bet at the higher amount? then reset to 0.00000001 once we lose?... then wait for another 3 losses in a row... then repeat the entire process? Huh

Unfortunately, this is very confusing and I really don't understand how the strategy works at this point.



Quote
______________________________________________________________
Then, according to anology, we continue to increase the stakes and set it already at <50, too, if we lose 2 times.
We have 6 bids left until the deposit is drained.
They can be divided as you like. 3 bets> 50, 3 bets <50.
Or 1,2> 50.
And here you're just randomly betting hi/low? Huh

I know it is difficult to try to put into words how the strategy works... but perhaps you could list a series of bets (amount + hi/low) and results to demonstrate how it works in the various examples.

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June 20, 2019, 05:55:22 AM
 #1203


Hi!
1 Satoshi is the initial bet, until 3 bets fall out less for freebitcoin 5000, for example (4004,3888,1009) or more than 5000 for example (5420,8865,5215)
any combinations.
After that, we begin to increase the stack balance / 2 * 10
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June 20, 2019, 06:01:40 AM
 #1204

Further, as soon as the rate was increased, we believe that a series of rates went from our example (4004,3888,1009), then logically it would be 4185,3545,1475, etc. before the first loss bet, for example 8565,
Similarly (5420,8865,5215), we believe that 7852,9995 will fall further before losing, for example, 1565
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June 20, 2019, 07:39:21 AM
 #1205

If we get a loss by the fourth bet, then we begin to double it * 2
We have 10 moves to the exit from the loss.
We alternate them 3 more than 5000, 2 less than 5000 and 3 more than 5000, 2 less than 5000. This is the worst scenario. When all the moves will be used.
And so the example went to the series (4004,3888,1009) these stacks of 1 satoshi no matter they won or lost or 4004, won 3888 lost, 1009 won.
It is important for us that they are all less than 5000. This is a condition for raising stacks. Similar with rates higher than 5000.

Example (4004,3888,1009) new balance rate / 2 * 10 we believe that there will be a long series.
If you received a winnings for example 1245, then again we bet on the continuation of the series. Until the first loss 7585.
If the number of winnings is more than 4 to 40, then we immediately return the stack by 1 satoshi to the beginning.
If the loss hit the intended win 1-3.
After we start this bet increase * 2 and
In our example, a loss of 7585 (balance / 2 * 10) * 2 is set to more than 5000.
________________________________________________________________
If they won the example 5478.
 Then we make the next bet.
(balance / 2 * 10) / 2
Half from originally increased. And again we check a series of rates higher than 5000. (this is for increasing profitability). If a series has gone then we click well before the first loss. If you immediately lose, then return to 1 satoshi To the top of the script.
__________________________________________________________________
If the loss is for example 1005, then the new rate (balance / 2 * 10) * 3
and again we put on more than 5000.
___________________________________________________________________
If you won for example 8999 then repeat:
Then we make the next bet.
(balance / 2 * 10) / 2 namely this.
(not this rate (balance / 2 * 10) * 3)
Half from originally increased. And again we check a series of rates higher than 5000. (this is for increasing profitability). If a series has gone then we click well before the first loss. If you immediately lose, then return to 1 satoshi To the top of the script.
_________________________________________________________________
If the loss is for example 2582, then the new rate (balance / 2 * 10) * 4
and now we put on less than 5000.
Twice put on more than 5000 now we change less than 5000.
Similar with the following rates up to level 10.
Betting combinations for betting with an increase * 2
2 less 3 more 3 less 2 more
You need to make it possible to change the sequence:
For example:
1 less, 1 more, 3 more, 2 less 3 more.
The most important
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June 20, 2019, 07:46:44 AM
 #1206

Make a set of examples with bet amounts, chance, win/loss result etc.

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June 20, 2019, 08:46:54 AM
 #1207

Hi, can someone help me with this strategy :The basebet is 0.00000001 placed at 1.8711X payout and bethigh=true.This bet is placed continuously until two consecutive win happens. when two consecutive win happens the nextbet becomes 0.00000100 placed at 1.8711X and bethigh=false.If this bet is a win then the conditions get back to initial that is 0.00000001 and bethigh=true.And if the bet was a loss, then also the conditions get back to initial and search for two consecutive wins and when two wins occur, the nextbet becomes 0.00000200.And again continues to initial conditions.

For example:
basebet=0.00000001 1.8711X  bethigh=true
1st bet-loss
2nd bet-loss
3rd bet-loss
4th bet-win
5th bet-win
Now above two consecutive win occurs.
So condition for next bet is 0.00000100 1.8711X bethigh=false.
6th bet-win/loss
Here for the 6th bet either the result is a win or a loss the condition for 7thbet is the initial conditions i.e.,
0.00000001 1.8711X and bethigh=true and continues until again two consecutive win occurs.
7thbet-loss
8th bet - loss
9th bet -win
10th bet -win
Now if the 6th bet was a loss then the 11th bet will be 0.00000200 1.8711X and bethigh=false.And if the 6th bet was a win, then 11th bet will be 0.00000100 1.8711X and bethigh=false.Now again for 12 th bet conditions get back to initial and continues until two consecutive win occurs. When the two win happens the nextbet will be chosen with respect to the result of 11th bet i.e., it will be double the bet at 11 th bet  if it was a loss or 0.00000100 if a win.



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June 23, 2019, 10:36:15 AM
 #1208

Make a set of examples with bet amounts, chance, win/loss result etc.
Would you like to write code base on the example of bet amounts, chance, win/loss result etc to make it more helpful for us or something else, thanks in advance if you write the code.


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June 23, 2019, 03:06:22 PM
 #1209

Would you like to write code base on the example of bet amounts, chance, win/loss result etc to make it more helpful for us or something else, thanks in advance if you write the code.
I don't get your question. Seunjti will be only write the code for dicebot after you tell him what's your strategy with base bet, winning chance, % after lose or %after win, how many rolls, etc.
How can he write the code if there is no such information?

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June 24, 2019, 06:13:14 AM
 #1210

Seunjti will be only write the code

No I won't. I generally don't help with programmer mode scripts. I might give a hint or a nudge in the correct direction or show you where something went wrong IF you tried it yourself, but I most definitely do not write scripts for people from scratch.

There are other members of the community that does help though, like HCP and chilly2k. You can also post on forum.seuntjie.com, there are some people over there that help as well.

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June 24, 2019, 09:12:17 AM
 #1211

Hello! The above strategy is written which I use myself. If you turn it into a bot, then there will be a fairy tale. In this form, as described above, I have been testing for more than six months. The results are excellent. Anyone help with writing the code.
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June 24, 2019, 07:03:58 PM
 #1212

Hello! The above strategy is written which I use myself. If you turn it into a bot, then there will be a fairy tale. In this form, as described above, I have been testing for more than six months. The results are excellent. Anyone help with writing the code.

Just remember all strategies works in the beginning till you hit it worse red streak ;-) but it can be a fairytale is you stop on time

.....1% HOUSE EDGE.....
.....FAUCET 3.5K...........
.....RAINBOT
10K..........






















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June 26, 2019, 05:08:30 AM
 #1213

basebet=0.00000001
nextbet=basebet
Chance=47
function dobet()

if!win then
nextbet=basebet*1
else
nextbet=basebet
end

bethigh=true
print(curentprofit)

count=count+3
if lastBet.Roll >50.00 and lastBet.Roll <99.99 then
count=0
end

if win then
nextbet=basebet*3
end
if currentstreak==-1 then
nextbet=basebet
end
bethigh=false
print(curentprofit)
if currentstreak==-1 then
nextbet=previousbet*2
end
if win then
nextbet=previousbet*2/2
end
if win then
nextbet=previousbet*2/2
end
if win then
nextbet=previousbet*2/2
end
if win then
nextbet=previousbet*2/2
end

if currentstreak==-1 then
nextbet=basebet

bethlow=false
print(curentprofit)

count=count+3
if lastBet.Roll >0.01 and lastBet.Roll <49.99 then
count=0
end

if win then
nextbet=basebet*2
end
if currentstreak==-1 then
nextbet=basebet
end
end

bethigh=true
print(curentprofit)
if currentstreak==-1 then
nextbet=previousbet*2
end
if win then
nextbet=previousbet*2/2
end
if win then
nextbet=previousbet*2/2
end
if win then
nextbet=previousbet*2/2
end
if win then
nextbet=previousbet*2/2
end
if currentstreak==-1 then
nextbet=basebet
end
end


Hello! That's what I got according to the logic of statistics. But some functions do not work correctly. Cannot catch 3 consecutive bets <50 or> 50. See what is wrong.
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July 18, 2019, 09:29:06 PM
 #1214

@Agent009

This script should do what you've asked... As always, it hasn't been extensively tested (I simply used the simulation and exported the results to check it), so use at your own risk!

You will need to modify the "edge" variable to match the "House Edge" of the site you want to play on... 1% HouseEdge = 1... 0.8% HE = 0.8 etc. Then set the basePayout and baseBet to suit your requirements. They are defaulted to 10x payout and 0.00000010 BTC

Code:
-------------------------------------------------------------------------------
--
-- Payout Martingalge Script for Agent009 by HCP
--
-- BTC Donations to: 33gzi64cvCr4i9ECGPwvZktzS2qknRUFhC
--
-------------------------------------------------------------------------------

edge       = 1 -- set to the house edge of your site
basePayout = 10 -- set to the base payout that you want
payout     = basePayout

chance     = (100 - edge) / payout -- calculate chance based on house edge
baseChance = chance

baseBet = 0.00000010 -- 1 "unit"
nextbet = baseBet -- set our initialBet

bethigh = false

function dobet()

    if win then
        -- reset to base bet/chance/payout
        nextbet = baseBet
        chance  = baseChance
        payout  = basePayout
       
    else
        -- increase payout
        payout  = payout + 1
       
        -- recalculate chance
        chance  = (100 - edge) / payout
       
        -- increase bet by 1 unit
        nextbet = previousbet + baseBet
    end

end

Agent009
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July 19, 2019, 12:50:15 AM
 #1215

@Agent009

This script should do what you've asked... As always, it hasn't been extensively tested (I simply used the simulation and exported the results to check it), so use at your own risk!

You will need to modify the "edge" variable to match the "House Edge" of the site you want to play on... 1% HouseEdge = 1... 0.8% HE = 0.8 etc. Then set the basePayout and baseBet to suit your requirements. They are defaulted to 10x payout and 0.00000010 BTC

Code:
-------------------------------------------------------------------------------
--
-- Payout Martingalge Script for Agent009 by HCP
--
-- BTC Donations to: 33gzi64cvCr4i9ECGPwvZktzS2qknRUFhC
--
-------------------------------------------------------------------------------

edge       = 1 -- set to the house edge of your site
basePayout = 10 -- set to the base payout that you want
payout     = basePayout

chance     = (100 - edge) / payout -- calculate chance based on house edge
baseChance = chance

baseBet = 0.00000010 -- 1 "unit"
nextbet = baseBet -- set our initialBet

bethigh = false

function dobet()

    if win then
        -- reset to base bet/chance/payout
        nextbet = baseBet
        chance  = baseChance
        payout  = basePayout
       
    else
        -- increase payout
        payout  = payout + 1
       
        -- recalculate chance
        chance  = (100 - edge) / payout
       
        -- increase bet by 1 unit
        nextbet = previousbet + baseBet
    end

end

HCP thank you very much! Smiley
I will test it today and then talk about the results...
seuntjie
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July 19, 2019, 11:41:00 AM
Merited by HCP (2)
 #1216

you can use site.edge to get the edge for the site you are currently playing on.

The site object contains some basic details for the site and the users stats as they come from the site, and the class definition can be found at https://github.com/Seuntjie900/DiceBot/blob/master/DiceBot/cDiceBot.cs#L5976

sleepyeyed
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July 31, 2019, 04:47:31 PM
 #1217

How can I calculate the probability of rolls if I start at chance=1 and keep increasing the chance by 1 on each loss? What would be the probability that it would reach chance=90? also, how would I increase each bet on loss so that it would stay in profit or at least break even? In my code below I'm toying with using exponents, but I'm just throwing random numbers at it to see what sticks so far.
Code:
basebet=1
nextbet=basebet
chance=1
function dobet()

if win then
nextbet=basebet
chance=1
end

if !win then
chance=chance+1
nextbet=previousbet*1.165^1.75
end
seuntjie
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August 01, 2019, 07:19:30 AM
 #1218

How can I calculate the probability of rolls if I start at chance=1 and keep increasing the chance by 1 on each loss? What would be the probability that it would reach chance=90? also, how would I increase each bet on loss so that it would stay in profit or at least break even? In my code below I'm toying with using exponents, but I'm just throwing random numbers at it to see what sticks so far.
Code:
basebet=1
nextbet=basebet
chance=1
function dobet()

if win then
nextbet=basebet
chance=1
end

if !win then
chance=chance+1
nextbet=previousbet*1.165^1.75
end

Not sure about the probability, my stats isn't that good.

How to calculate the next bet to ensure you break even: You will need to track your streak profit. to do this, have a variable that you add your losses to when you lose and reset when you win.
Then you can use the formulas payout=(100-edge)/chance and profit=(betamount*payout)-betamount to calculate what your bet amount should be

so if you've had 30 losses in a row and you have, say, -35 profit for the losing streak, you can calculate your next bet to break even using

-(streakprofit) = (x * ((100- site.edge)/chance))-x
refactors to
x= -(streakprofit)/payout
(this assumes streakprofit is negative)

sleepyeyed
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August 01, 2019, 12:04:09 PM
 #1219

Quote
Not sure about the probability, my stats isn't that good.

How to calculate the next bet to ensure you break even: You will need to track your streak profit. to do this, have a variable that you add your losses to when you lose and reset when you win.
Then you can use the formulas payout=(100-edge)/chance and profit=(betamount*payout)-betamount to calculate what your bet amount should be

so if you've had 30 losses in a row and you have, say, -35 profit for the losing streak, you can calculate your next bet to break even using

-(streakprofit) = (x * ((100- site.edge)/chance))-x
refactors to
x= -(streakprofit)/payout
(this assumes streakprofit is negative)


I kind of understand this, but am unsure of how I can fit this into my code so that it works correctly. So does the x variable represent my next bet? Sorry for my programming logic ignorance. I'll try my best at wrapping my head around it for now.
docthusinh
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September 06, 2019, 03:38:05 PM
 #1220

Not sure if the programming mode support this:

betsides = [L, H, L, L, H, L, H, H, L, L....]
stakes = [1, 1, 1, 2, 3,4, 5, 6...]
betodds = [2, 2, 2, 3, 4, 5, ....]

if win
 nextside = betsides[0]
 nextstake = stakes[0]
 nextodd = betodds[0]

else //lose
 nextside = betsides[currentstreak]
 nextstake = stakes[currentstreak]
 nextodd = betodds[currentstreak]

Questions are:
1) Will above variables taken for use in the bot (nextside, nextstake, nextodd)? If not, how to implement above?
2) Is the first lose will cause currentstreak = 1?
3) If above array list suported, what is the maximum size? Basically I need 3000+
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