This thread

https://bitcointalk.org/index.php?topic=1217368.0did a great job in finding out the +EV point of the Nitrogen dice jackpot. Now we have a similar challenge to work out the same thing for FortuneJack's new dice jackpot. It works differently.

The house edge is the same 1%

The min bet is 0.01฿

If you win you get 80% of the jackpot (50% if you bet 0.0001 and 20% if you bet 0.000001)

In order to win you have to roll a four figure number starting with a 1, then starting with a 2, then starting with a 3, through to 7. For example

17.65

27.65

37.65

47.65

57.65

67.65

77.65

Here is how FortuneJack explains it

Thanks to BTF user ndnhc this is what we come up with

Bet amount : 0.01฿

Probability of rolling 1x.xx : 0.1

Probability of hitting the jackpot : 0.1^7

Number of rolls needed on average : 1/0.1^7 = 10000000

฿ wagered required on average : 100000

House edge : 1000฿

To be positive EV, the jackpot should be more than 1000/0.8 = 1250฿

Bet amount : 0.0001฿

Probability of hitting the jackpot : 0.1^7

Number of rolls needed on average : 1/0.1^7 = 10000000

฿ wagered required on average : 1000

House edge : 10฿

To be positive EV, the jackpot should be more than 10/0.5 = 20฿

Bet amount : 0.000001฿

Probability of hitting the jackpot : 0.1^7

Number of rolls needed on average : 1/0.1^7 = 10000000

฿ wagered required on average : 10

House edge : 0.1฿

To be positive EV, the jackpot should be more than 0.1/0.2 = 0.5฿.

The last one appears to be the most attractive option. What do yall think did we miss something? The first case of 1250฿ will probably never happen!

FWIW I used to find FortuneJack slightly shady but they have kept on improving and running an honest operation, I quite like them now. Here is a full review.

https://bitroll.com/bitcoin-dice-reviews/fortunejack-dice-review/Roll good.