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Author Topic: Planning new farm.  (Read 829 times)
kazak-21
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November 09, 2015, 09:13:00 AM
 #1

Hello y'all.

Recently, I've got 16 AntMiner S5 and I wonder these days, what will be the better configuration for cooling all this?

All power consumption it's ready but cooling even not.

How I measure how much heat generated by each S5? Through BTU or CFM? I mean, I've thought use 1 or 2 extractors fans like the picture, but I would like to have an idea of heat generated and take those numbers and calculate how much exhaust fans I could need. Another doubt, is better setup a big hot aisle or little?

Below, I'm going to attach here the image to refer to planning and exhaust fan.

If somebody knows how much heat is generated by each S5 in BTU vs CFM, can comment here, will be a big helpful. My final idea is, extract the total of heat and every moment keep fresh the miners.

Too can be useful if somebody knows how can calculate the heat generate by each miner, knowing the watts, volt, etc. I want to know from where concludes that the BTU or CFM generated by each miner it is.

It's the planning.

http://postimg.org/image/5j9pnnbsn/

It's the extractor fan.

http://mlv-s1-p.mlstatic.com/ventiladores-extractores-industriales-desde-6-hasta-36-23305-MLV20247558475_022015-F.jpg

Good vibes y'all!!!

PD: First image show "extractor fans" I meant to say, exhaust fan. Sorry.
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QuintLeo
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November 09, 2015, 11:27:28 AM
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An S5 eats appx. 600 watts (at the wall including PS losses for a 90% appx. efficiency PS).

 That works out to appx. 2000 BTU.


 The fan in them is specced at appx. 200cfm.


 BTU and CFM are not related specifications.

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November 09, 2015, 04:03:17 PM
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An S5 eats appx. 600 watts (at the wall including PS losses for a 90% appx. efficiency PS).

 That works out to appx. 2000 BTU.


 The fan in them is specced at appx. 200cfm.


 BTU and CFM are not related specifications.


Could you show the math behind your answer? I guess thats what he is looking for.
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November 09, 2015, 06:26:08 PM
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S5 consumes ~550W DC, 30W of which is fan and controller.  With 90% efficiency for PSU that gives 590W at the wall of energy.  Energy can neither be created nor destroyed, so that 590W is going almost entirely to heat, with other losses due to mechanical friction (fan), radiation, light and noise accounting for a very minimal amount.  590W would mean 2,124,000 Joules in an hour, or 2,013 BTU's minus aforementioned energy "losses".

I'm not sure it's worth doing the math to be perfectly honest unless you were designing a massive data center.  Just put as big as possible ventilation fans to exchange air, and monitor ambient temp.  If it gets too high, add more....  I believe some of the large hosting centers have enough CFM to exchange all the air in the hosting area in a matter of seconds.

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November 09, 2015, 07:03:20 PM
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Just get 3-tons or 36,000 BTU of cooling with 3200 total CFM of air movement and you should be able to keep your room temp steady. 

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November 09, 2015, 07:44:42 PM
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S5 consumes ~550W DC, 30W of which is fan and controller.  With 90% efficiency for PSU that gives 590W at the wall of energy.  Energy can neither be created nor destroyed, so that 590W is going almost entirely to heat, with other losses due to mechanical friction (fan), radiation, light and noise accounting for a very minimal amount.  590W would mean 2,124,000 Joules in an hour, or 2,013 BTU's minus aforementioned energy "losses".

I'm not sure it's worth doing the math to be perfectly honest unless you were designing a massive data center.  Just put as big as possible ventilation fans to exchange air, and monitor ambient temp.  If it gets too high, add more....  I believe some of the large hosting centers have enough CFM to exchange all the air in the hosting area in a matter of seconds.

Just get 3-tons or 36,000 BTU of cooling with 3200 total CFM of air movement and you should be able to keep your room temp steady. 

I understood when you said those quantity. So, how many CFM and RPM must be the exhaust fan? The "heat side" is approximately 2metersx2metersx1meter.
Finksy
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November 09, 2015, 08:06:56 PM
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4 cubic meters = 141 cubic feet.  RPM doesn't matter, do some research on how much flow you should go on the fan.

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November 10, 2015, 10:29:28 AM
 #8

My easy rule of thumb is to remember that a common 1500 watt space heater generates a bit over 5000 BTU.

 For the record, 4 of my 5 S5s eat a hair over 600 watts "at the wall" with Seasonic X-1250 power supplies (during testing these were loaded up to a little LESS than 50% full capasity, so should have been a little over 90% efficient), as measured by my Brand wattmeter, at stock 350Mhz clock - the other one was 580 watts, but that one also underhashes consistantly by 10% or so at stock clock.

 I've seen a lot of reviews that show the S5 eating MORE than the "official" 590 watts at stock clock, commonly with the EVGA 1300 G2 "gold" PS.

 I honestly do NOT think that the 590 watt rating is a valid one, given how many S5's I've seen or have seen reported to be eating more power.
 I suspect the 590 watts was actually measured by Bitmain using their 1600 watt PS (which is Platinum rated or very close to that level).


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