InceptionCoin
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 Offline
Activity: 108
Merit: 10
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February 25, 2016, 05:48:20 PM
Last edit: February 25, 2016, 06:00:37 PM by InceptionCoin |
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I played around with Destiny 3-symbol addresses and wrote very dumb python script to get desired prefix(by full iterating). if someone needs
# type here desired prefix
IWANT="DES"
#do not change anything after the signal
#BEEP
b58_digits = '123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz'
def base58_encode(n):
l = []
while n > 0:
n, r = divmod(n, 58)
l.insert(0,(b58_digits[r]))
return ''.join(l)
lw=len(IWANT)
result=""
for i in IWANT:
if not i in b58_digits:
print "Address contain non b58 symbol"
exit()
for i in range(16**6):
pk=int(hex(i)+"0"*(8-len(hex(i))) + "0"*44,16)
adr=base58_encode(pk)
if adr[:lw]==IWANT:
result=hex(i)+"0"*(8-len(hex(i))) + "0"*44
break
result_string='base58Prefixes[PUBKEY_ADDRESS] = list_of'
for i in range(1,16):
st=result[i*2:i*2+2]
if st=="00":
break
else:
result_string+="(%d)"%int('0x'+st,16)
result_string+=";"
print result_string
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Skilled C++ and Python programmer. Looking around to create solid longterm coin by myself. Do you have any ideas? Feel free to PM me.
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proletariat
Legendary
Offline
Activity: 1246
Merit: 1005
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February 25, 2016, 05:53:24 PM |
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willing to buy a few @ 7,500 sats PM me if interested.
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VenMiner
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February 25, 2016, 07:50:59 PM |
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Guys help me with this, i want to know if i am not wrong.
If when POW end will be arround 213.000 coins, with POS at 10% year if all coin is staking will be generate just arround 60 coins per day?
if it is true, here are a awesome potential, the inflation of this coin is really low.
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zsnorbi
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February 25, 2016, 07:58:47 PM |
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Guys help me with this, i want to know if i am not wrong.
If when POW end will be arround 213.000 coins, with POS at 10% year if all coin is staking will be generate just arround 60 coins per day?
if it is true, here are a awesome potential, the inflation of this coin is really low.
Your math is right but actual coins will be much less than 60/day as not the whole supply will stake |
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kampretkabur
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February 25, 2016, 07:58:53 PM |
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Guys help me with this, i want to know if i am not wrong.
If when POW end will be arround 213.000 coins, with POS at 10% year if all coin is staking will be generate just arround 60 coins per day?
if it is true, here are a awesome potential, the inflation of this coin is really low.
not sure about how to calculate this, but with POS starts at POW, might be les than 210000 when POW ends, this coin looks good already n stake is working great |
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TheInfidel
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February 25, 2016, 08:04:49 PM |
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Guys help me with this, i want to know if i am not wrong.
If when POW end will be arround 213.000 coins, with POS at 10% year if all coin is staking will be generate just arround 60 coins per day?
if it is true, here are a awesome potential, the inflation of this coin is really low.
not sure about how to calculate this, but with POS starts at POW, might be les than 210000 when POW ends, this coin looks good already n stake is working great Agree it looks great already. It however needs to get listed on an exchange ASAP. I really need to catch some dumping on this because my stake weight is a bit on the low side.  Any news about an exchange listing? |
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VenMiner
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February 25, 2016, 08:07:40 PM |
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Wow thanks for answers guys, this coin look really good, i hope dev team see the gold in this project...  |
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DestinyTeam (OP)
Newbie
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Activity: 56
Merit: 0
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February 25, 2016, 08:23:48 PM |
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VenMiner
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February 25, 2016, 08:37:33 PM |
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Great, happy trading for all. |
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bhokor
Legendary
Offline
Activity: 966
Merit: 1000
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February 25, 2016, 08:57:10 PM |
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I played around with Destiny 3-symbol addresses and wrote very dumb python script to get desired prefix(by full iterating). if someone needs
# type here desired prefix
IWANT="DES"
#do not change anything after the signal
#BEEP
b58_digits = '123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz'
def base58_encode(n):
l = []
while n > 0:
n, r = divmod(n, 58)
l.insert(0,(b58_digits[r]))
return ''.join(l)
lw=len(IWANT)
result=""
for i in IWANT:
if not i in b58_digits:
print "Address contain non b58 symbol"
exit()
for i in range(16**6):
pk=int(hex(i)+"0"*(8-len(hex(i))) + "0"*44,16)
adr=base58_encode(pk)
if adr[:lw]==IWANT:
result=hex(i)+"0"*(8-len(hex(i))) + "0"*44
break
result_string='base58Prefixes[PUBKEY_ADDRESS] = list_of'
for i in range(1,16):
st=result[i*2:i*2+2]
if st=="00":
break
else:
result_string+="(%d)"%int('0x'+st,16)
result_string+=";"
print result_string
Hi thank you for share, which version of python are you using, i am trying to run in 3.5.1 and i am getting "missing parenthesis in call to print", some idea what can it be? |
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InceptionCoin
Member
Offline
Activity: 108
Merit: 10
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February 26, 2016, 05:25:12 AM |
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...
Hi thank you for share, which version of python are you using, i am trying to run in 3.5.1 and i am getting "missing parenthesis in call to print", some idea what can it be?
Now it should work with any python version # type here desired prefix
IWANT="inc"
#do not change anything after the signal
#BEEP
b58_digits = '123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz'
def base58_encode(n):
l = []
while n > 0:
n, r = divmod(n, 58)
l.insert(0,(b58_digits[r]))
return ''.join(l)
lw=len(IWANT)
result=""
for i in IWANT:
if not i in b58_digits:
print "Address contain non b58 symbol"
exit()
for i in range(16**6):
pk=int(hex(i)+"0"*(8-len(hex(i))) + "0"*44,16)
adr=base58_encode(pk)
if adr[:lw]==IWANT:
result=hex(i)+"0"*(8-len(hex(i))) + "0"*44
break
result_string='base58Prefixes[PUBKEY_ADDRESS] = list_of'
for i in range(1,16):
st=result[i*2:i*2+2]
if st=="00":
break
else:
result_string+="(%d)"%int('0x'+st,16)
result_string+=";"
print(result_string)
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Skilled C++ and Python programmer. Looking around to create solid longterm coin by myself. Do you have any ideas? Feel free to PM me.
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DestinyTeam (OP)
Newbie
Offline
Activity: 56
Merit: 0
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February 26, 2016, 08:43:01 AM |
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...
Hi thank you for share, which version of python are you using, i am trying to run in 3.5.1 and i am getting "missing parenthesis in call to print", some idea what can it be?
Now it should work with any python version # type here desired prefix
IWANT="inc"
#do not change anything after the signal
#BEEP
b58_digits = '123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz'
def base58_encode(n):
l = []
while n > 0:
n, r = divmod(n, 58)
l.insert(0,(b58_digits[r]))
return ''.join(l)
lw=len(IWANT)
result=""
for i in IWANT:
if not i in b58_digits:
print "Address contain non b58 symbol"
exit()
for i in range(16**6):
pk=int(hex(i)+"0"*(8-len(hex(i))) + "0"*44,16)
adr=base58_encode(pk)
if adr[:lw]==IWANT:
result=hex(i)+"0"*(8-len(hex(i))) + "0"*44
break
result_string='base58Prefixes[PUBKEY_ADDRESS] = list_of'
for i in range(1,16):
st=result[i*2:i*2+2]
if st=="00":
break
else:
result_string+="(%d)"%int('0x'+st,16)
result_string+=";"
print(result_string)
It is possible to calculate desired bits without iterating, there is no hashing after adding version byte, so its just a simple math to recalculate from numeration system with base 58 to hex. However looks like for FootyCash developer ( https://bitcointalk.org/index.php?topic=1374929.20) it was too hard Thank you for sharing Slack community is slowly growing. If you want to be inside please pm me your email.
All plans and updates before official announcement!
Welcome |
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mefisto
Newbie
Offline
Activity: 54
Merit: 0
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February 26, 2016, 06:49:27 PM |
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Half every 5 days
Block 1-6750 - 16 coins
Block 6751-13500 - 8 coins
Block 13501-20250 - 4 coins
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little by halving ... less than 24 hours
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VenMiner
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February 26, 2016, 06:59:38 PM |
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Half every 5 days
Block 1-6750 - 16 coins
Block 6751-13500 - 8 coins
Block 13501-20250 - 4 coins
........................................
little by halving ... less than 24 hours
I think with the POS working the halving is like every 2.5 days... |
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DestinyTeam (OP)
Newbie
Offline
Activity: 56
Merit: 0
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February 27, 2016, 10:27:02 AM |
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TheInfidel
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February 27, 2016, 11:58:45 AM |
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Well that's a start. In the meantime I have been able to collect more coins, I actually have some stake weight now. Now to see how many more and how cheap they get, seems I and maybe one or two others are the only ones with any interest in this coin. Time as always will tell if the prices allowed me to make a killing or if it will be added to my collection of many bags. |
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DestinyTeam (OP)
Newbie
Offline
Activity: 56
Merit: 0
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February 27, 2016, 05:35:23 PM |
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and next halving at block 13501
Happy mining and trading. News coming on monday
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TheInfidel
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February 27, 2016, 05:40:32 PM |
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and next halving at block 13501
Happy mining and trading. News coming on monday
Nice to hear from you. However you seem to not be paying attention Suprnova already mining on block 13655 making the next halving 20251 |
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Alter35
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February 27, 2016, 06:33:16 PM |
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sell 2000 des for 0,06 bt
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