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Author Topic: [Raffleception] Win Tickets to "The Raffle of All Raffles II" #27 - 4 tickets.  (Read 385 times)
Hhampuz (OP)
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January 28, 2017, 01:42:02 AM
Last edit: January 28, 2017, 02:14:54 AM by Hhampuz
 #1

So we are currently filling the biggest raffle in btct history right now, read more about it here.

While doing this I realize that a lot of people might not want to pay 0.06 for a ticket when there's a 1 in 256 chance to win. So I came up with the idea of doing a raffle within a raffle - Raffleception!

So here's how we'll do it:

16 spots, classic raffle. There will be 2 prizes of 2 tickets each. Once this is filled we will Select two blocks and whoever has the correct characters at the end of those blocks will win the prizes.

The prizes: Winner and runner up will get 2 tickets each to "The Raffle of All Raffles II".

Price per ticket: 0.0154BTC.

Pay to this address only: 1D32LQzjyjRKCFPfeUw9xDExE6YmLkdBfB

Max spots: None.

0 - ironmarvel2
1 - ironmarvel2
2 - wheelz1200
3 - wheelz1200 - Block #450356 - Congratz!
4 - Hhampuz
5 - ironmarvel2 - Block #450357 - Congratz!
6 - TMAN
7 - ironmarvel2
8 - TMAN
9 - TMAN
a - wheelz1200
b - wheelz1200
c - actmyname
d - TMAN
e - ironmarvel2
f - ironmarvel2


You can not trade the ticket for the BTC equivalent. One ticket can only win once.

Please pay asap and include the txID with your post so we do not wait around with this one for too long.

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Hhampuz (OP)
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January 28, 2017, 01:42:39 AM
Last edit: January 28, 2017, 02:10:02 AM by Hhampuz
 #2

The following blocks will determine the winners:

1st: Block #450356
2nd: Block #450357

Good luck gents!

actmyname
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January 28, 2017, 01:49:31 AM
 #3

Hopefully this time I'll c more luck.

41e81b2afaa567987f5d4d8b22645d8104a45f950a8542f5e5db2cfeb4591273

Is there a possibility to do a later raffle where it's split into four winners?

Hhampuz (OP)
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January 28, 2017, 01:53:35 AM
 #4

Hopefully this time I'll c more luck.

41e81b2afaa567987f5d4d8b22645d8104a45f950a8542f5e5db2cfeb4591273

Is there a possibility to do a later raffle where it's split into four winners?

Thank you for playing again Smiley.

Do you mean that we do it like this one, but roll 4 blocks where we give out 1 ticket each? I think that could work, can try it later and see if we'll find the players Smiley

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January 28, 2017, 02:10:43 AM
 #5

And full!

#450356 & 450357!

Next one will be a bit different, we'll give out 4 tickets but we'll roll 4 blocks. Meaning 1 block = 1 ticket.

Good luck!

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