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 Author Topic: Any way to see total YACoin network hashrate?  (Read 925 times)
serge79
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 May 10, 2013, 12:08:24 AM

I can't find proper command in the help section of the console.
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Vycid
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 May 10, 2013, 01:45:14 AM

I can't find proper command in the help section of the console.

As far as I know, there isn't a way to tell directly. However, we can approximate from the difficulty using the following relation:

Code:
Hashrate = Difficulty * 2^32 / 600

At the current difficulty ~ 0.6482, that means we can guess 4640000 hashes/sec, i.e. 4.64 MHash/s.

EDIT: Hold on, that's clearly wrong. Let me figure out what the correct equation is.

serge79
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Activity: 154

 May 10, 2013, 01:49:37 AM

I can't find proper command in the help section of the console.

As far as I know, there isn't a way to tell directly. However, we can approximate from the difficulty using the following relation:

Code:
Hashrate = Difficulty * 2^32 / 600

At the current difficulty ~ 0.6482, that means we can guess 4640000 hashes/sec, i.e. 4.64 MHash/s.

EDIT: Hold on, that's clearly wrong. Let me figure out what the correct equation is.

TY
Vycid
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Activity: 294

♫ the AM bear who cares ♫

 May 10, 2013, 02:06:34 AM

I can't find proper command in the help section of the console.

As far as I know, there isn't a way to tell directly. However, we can approximate from the difficulty using the following relation:

Code:
Hashrate = Difficulty * 2^32 / 600

At the current difficulty ~ 0.6482, that means we can guess 4640000 hashes/sec, i.e. 4.64 MHash/s.

EDIT: Hold on, that's clearly wrong. Let me figure out what the correct equation is.

TY

Well, I can't find the information anywhere. I'd have to dig through the YACoin code, I suspect.

That relation is valid for BTC and LTC and their derivatives (Bytecoin, FTC etc), however Novacoin derivatives like YACoin have some weirdness with their difficulty adjustment (like varying the block reward), so I'm guessing that's why the difficulty/hashrate computation is inaccurate.

Sorry I wasn't more help. Maybe someone more knowledgeable has the answer.

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