stompix


January 29, 2014, 01:22:02 AM 

Fwiw I haven't seen him claim that anywhere in his thread, and honestly think he's well enough versed in math to know he will not be able to crack an address with any amount of bitcoins in it in the foreseeable feature. I don't really know what he's trying to achieve, though.
The thread has several instances of newbie accounts providing single pubkeys which evil claims to crack e.g: https://bitcointalk.org/index.php?topic=421842.msg4800547#msg4800547Ah, I see, my apologies. edit: he's saying the addresses need to be " generated completely as to the manual" though... So , I generate an address , send him the private key and then he can crack it? =))))))))))))0





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prezbo


January 29, 2014, 01:24:16 AM 

So , I generate an address , send him the private key and then he can crack it? =))))))))))))0
If it's the kind of address public key his program is searching for, sure. However the chances of any reallife addresses that have coins in it falling into that range are abysmal.




fpgaminer


January 29, 2014, 01:49:42 AM 

Here's what's going on. EvilKnievel has precomputed a couple points on the secp256k1 curve. Specifically points where the exponent is of the form 2**N. (see 1,2) He then wrote a program, the "cracker", that can search the area around those points. If a Bitcoin keypair lies close to one of those points, his program will find it. This isn't dangerous. It's improbable (~impossible) that any uniformly random Bitcoin keypairs are weak to his precomputed points. The secp256k1 keyspace is, for all practical purposes, infinitely large. It doesn't matter if EvilKnievel had a gabilliongajillion precomputed points and all the computing power in the universe. His approach still wouldn't crack a normal Bitcoin keypair. To me, having just read EvilKnievel's thread, it sounds like he's insinuating that there is danger here. He's insinuating that a uniformly random Bitcoin keypair has a reasonable chance of being tractably close to one of his precomputed points. There is no reasonable chance of this, and his claims are ridiculous. The thread should be closed as a scam, because he's asking for money on misleading premises. If he has nothing to hide, why was his HTML generator obfuscated? I'll help and deobfuscate the generator for everyone. Here's the algorithm: Pick a random N, [128, 255]. Pick a random M, [1, 20000000]. Spit out 2**N  M as a private key.
See the problem? He just needs to take a generated public key, add G to it ~20,000,000 until it matches one of the 128 precomputed keys (which are of the form 2**N), and BAM the private key is "cracked". This doesn't make Bitcoin weak. It never will. It's a rainbow table attack. But mankind will never have enough computational and storage power to make rainbow tables work against secp256k1. As for the bitprobing.com "project". That's a load of bollocks. If you don't believe what the experts have to say about ECDSA, that's fine. But go learn group theory and number theory first, before asking the public to help run unsubstantiated "experiments." I know these forums are intentionally softmodded, and appreciate that to an extent. But it's times like these I wish the forums were more aggressively moderated so that EvilKnievel could just be banned for misleading and scamming people. (1) Actually, he fscked this up. He interpretes the decimal result of 2**N as hexadecimal. (2) 2**128 is 340282366920938463463374607431768211456. Interpret that as a hexadecimal private key and you get a public key of 04864f29af3191e135f5c78499271961f2313110fb2a296bf072733475529da1fb4d5cef64d1212 a946775bfb2db5319fb618089ae8806d618f44d68d3bdb18650. The least significant 32bits of the X coordinate is 0x529da1fb. That matches one of the constant in his script. I assume the rest match similarly.




gmaxwell
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January 29, 2014, 02:19:01 AM 

so that EvilKnievel could just be banned for misleading and scamming people.
The crappy and super slow implementation of ECC arithmetic linked to on that website checks keys generated against a couple thousand 32 bit values. (Why use a slow thing like that if you've supposedly got some amazing gpu thing). My guess was that he's using this as bait to get people to run that program and the values that its looking for are all 'near' high value keys. Or other wise it just another lame market manipulation attempt. Either way, ... if he actually can crack something I welcome him to go solve any of the 200,000 keys I listed and collect his bounty. Thanks for decoding his JS, I'd just ignored it.

Bitcoin will not be compromised



Mivexil


January 29, 2014, 02:32:08 AM 

To motivate people participating in this, I am paying BTC for participating in this study. However, the BTC have to come from somewhere and it is hard to get some scientific funding.
This sounds a bit strange to me... So, you are "cooperating" with others to crack the keys and share the proceeds? Actually I am not cracking anything. I am trying to determine the distribution of complete random addresses (with no balance whatsoever) around certain points on the elliptic curve. Most people say (or better "repeat what they've heard"): "Well if the addresses are completely random and come from a good entropy source, there will be no patterns in the distribution at all". But who tells us this is the true? Nobody to my knowledge has ever questioned it nor is there any literature about this published. For instance, I think something different, and thus I perform a larger (mathematical) analysis on how random bitcoin addresses really are. You're basically breaking ECDSA, claiming that privkeytopubkey transition results in a nonuniform distribution.




cp1


January 29, 2014, 04:37:13 AM 

So he wrote a script to generate a (relatively) small and predictable number of keys that he then "cracks" to prove his program works. Of course because the number of keys that he can crack is something like 1/1e39 of the number of possible keys there's literally no chance he can crack an address that has anything in it to steal. So instead he sells his program for 2 BTC, if he even sells 1 copy then he'll have more BTC than if he had actually used his program.




Altoidnerd


January 29, 2014, 05:37:36 AM 

http://en.wikipedia.org/wiki/Babystep_giantstepWhat? Why does this "cyclic group" appear to have two operations? This is invoking the ring structure I guess? Sloppy article! Evil can't (and never said he could) crack fair keys. He has shown something subtly different. Nobody should be afraid, nor do I think he could be called a scammer for selling software, unless he is lying about something.




jaesyn
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January 29, 2014, 05:52:09 AM 

The paradox here is that if someone has broken ECDLP and obtains the keys to the kingdom (BTC and all of the other crypto coins that rely on ECDSA), and they go public with it, then they will assume ownership of nothing because the currency would cease to have any value.
Does this mean that ECDLP remains unsolved? Not necessarily. There are attacks based on randomly finding collisions in the EC space in order to derive unknown variables in the algebraic space (Pollard Rho and Kangaroo come to mind), and a clever person may have figured out ways to make this more efficient, or at least less random in nature. Hopefully, they remain clever and not seek fame or attention.
In this case, though, I agree that it appears the script on GitHub is being used as a vehicle for a distributed search for the private keys that generate wellknown public keys... or similarly, a search for "k" that results in a wellknown signature R value (which can then be used to derive the private key for the public key used by that signature).




fpgaminer


January 29, 2014, 06:16:42 AM 

nor do I think he could be called a scammer for selling software, unless he is lying about something. The current title of his thread is: "[WTS] OpenCL Based, Optimized BTC PrivateKey Cracker with Sources [WITH VIDEO]" The first post says things like: And who knows, this tool is giving you good chances to get one of these lost 10 MILLION US$ accounts This project is [...] to recover lost private keys. Working on real bitcoin network with real addresses and real coins. This again shows you that there is an infinite number of weak bitcoin addresses. The only thing in the first post of that thread that indicates that this isn't what people think it is, is the following: Randomly generated Bitcoin Adresses are used (however they are all specialweak). Which is incredibly confusing, but alludes to the fact that the program only works on special keys that no one is likely to ever find in the wild. So, if all that isn't misleading, I don't know what is. I guess if what he's doing is acceptable, I might as well sell my "OpenCL Based, Optimized BTC Miner with Sources, 10 TH/s". It works with any SHA256 Proof of Work (however they are all specialweak)! You could crack that 10 MILLiON US$ chain of blocks!




Altoidnerd


January 29, 2014, 06:32:09 AM 

So, if all that isn't misleading, I don't know what is. I guess if what he's doing is acceptable, I might as well sell my "OpenCL Based, Optimized BTC Miner with Sources, 10 TH/s". It works with any SHA256 Proof of Work (however they are all specialweak)! You could crack that 10 MILLiON US$ chain of blocks!
Well, I do think if one is not savy or paying attention they would misunderstand what he is saying  yes this will mislead many. But then he also said if you're not savy, and don't know what you're doing this isn't for you. Yes he's a salesman, but he's not scamming... just an interesting word choice and provocative, tabloidish title.




Zangelbert Bingledack
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January 29, 2014, 07:16:08 AM 

Actually I am not cracking anything. I am trying to determine the distribution of complete random addresses (with no balance whatsoever) around certain points on the elliptic curve. Most people say (or better "repeat what they've heard"): "Well if the addresses are completely random and come from a good entropy source, there will be no patterns in the distribution at all".
But who tells us this is the true? Nobody to my knowledge has ever questioned it nor is there any literature about this published. For instance, I think something different, and thus I perform a larger (mathematical) analysis on how random bitcoin addresses really are.
Random means "no pattern," by definition. You could question whether addresses are truly being generated randomly, but you can't question whether addresses that are ex hypothesi random might actually have a pattern  at least not without falling into incoherence.




medUSA
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January 29, 2014, 07:43:25 AM 

The maths well exceeded my comprehension. It seems the approach is a "hit and miss and aim again". Could it be summerized as "possible but improbable"?
Whether the cracking scrypt works or not... At least OP has stated that address is safe when the public key is not broadcasted, thus confirming reusing addresses is not safe, this is all I need to know.




BurtW
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January 29, 2014, 08:36:49 AM 

It seems to me EK has simply shown us something we all already know. If there is a weakness in the random number generator used to generate the private keys and this RNG weakness is known or can be determined then the search space for the public key > private key problem can be reduced. All EK has done is prove that given public keys calculated from private keys generated by his personal totally bogus nonRNG (NRNG ^{TM}) he can easily recover the private keys. EK: A bit of advice. You published your program too soon. It would have not been that much more work and would have been a lot more convincing if you had taken the time to do the hashing in your program so that you could show it "cracking" Bitcoin addresses. You also made the mistake of trying to sell it here in a forum filled with people that know more about cryptography than you do. Next time add the hashing and pitch your wares on a less technical forum. Here is a pitch that might work for you (somewhere else, not here): Everyone! I have a program that can crack weak Bitcoins addresses. Only 2 BTC. Immediate download! After downloading the program you can easily check the program for youself and make sure it is working for you! Do the following steps. Be sure to follow the instructions exactly: 1) Generate a random private key using my patented NRNG ^{TM} program here: http://WeakPrivateKeys.org2) Take this private key to bitaddress.org or any web site of your choice that will calculate a Bitcoin address from a private key and generate the Bitcoin address. 3) Enter this random Bitcoin address into the progam. 4) Run the program and see just how fast it can crack the Bitcoin address and recover the public and private keys! 5) You can run this procedure as many times as you like. Each time you will be given a different private key by the NRNG ^{TM} and each time you will be totally surpirsed at how fast your new Bitcoin address cracking program can recover the key pair from just the Bitcoin address! Just imagine the wealth that awaits you once you run this program on some of the Bitcoin addresses that contain thousands of Bitcoins! It will be just like taking candy from a baby!

Our family was terrorized by Homeland Security. Read all about it here: http://www.jmwagner.com/ and http://www.burtw.com/ Any donations to help us recover from the $300,000 in legal fees and forced donations to the Federal Asset Forfeiture slush fund are greatly appreciated!



prezbo


January 29, 2014, 10:07:18 AM 

Two operations? It only has one, multiplication.




Altoidnerd


January 29, 2014, 12:01:28 PM 

Two operations? It only has one, multiplication. ...x = i m + j I count two. The group operation was previously defined as the multiplication...




prezbo


January 29, 2014, 12:32:26 PM 

Two operations? It only has one, multiplication. ...x = i m + j I count two. The group operation was previously defined as the multiplication... that's in the exponent, which is an integer  A^x = A^(im+j) = A^(im)*A^j, if you will.




jaesyn
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January 29, 2014, 01:13:12 PM 

Two operations? It only has one, multiplication. ...x = i m + j I count two. The group operation was previously defined as the multiplication... that's in the exponent, which is an integer  A^x = A^(im+j) = A^(im)*A^j, if you will. Don't confuse the DLP with the ECDLP, though. Similar concepts, but ECDLP doesn't use exponents (it uses EC multiplication instead, which is the operation that is intractable). Q is public key, n is order of G, set m = sqrt(n) Babystep (i) Giantstep (j) is then to find a collision: i*G = Q − jm*G or, in other words, find the sum of two points, i*G + jm*G, that collide with the public key point Q that you're trying to solve. The private key will be i + jm (mod n).




prezbo


January 29, 2014, 01:39:40 PM 

Two operations? It only has one, multiplication. ...x = i m + j I count two. The group operation was previously defined as the multiplication... that's in the exponent, which is an integer  A^x = A^(im+j) = A^(im)*A^j, if you will. Don't confuse the DLP with the ECDLP, though. Similar concepts, but ECDLP doesn't use exponents (it uses EC multiplication instead, which is the operation that is intractable). Q is public key, n is order of G, set m = sqrt(n) Babystep (i) Giantstep (j) is then to find a collision: i*G = Q − jm*G or, in other words, find the sum of two points, i*G + jm*G, that collide with the public key point Q that you're trying to solve. The private key will be i + jm (mod n). Obviously, once you change the group from multiplicative to additive it won't be an exponent anymore But in the end, it's all just notation, the concept is exactly the same.




cp1


January 29, 2014, 05:05:58 PM 

It's a good reminder to only generate addresses using "reliable" methods. EK could buy out the top google listing for bitcoin paper wallet and replace its RNG with his own fake RNG.




