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Author Topic: [ARCHIVE] Bitcoin challenge discusion  (Read 28951 times)
Kakmakr
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July 20, 2019, 11:37:29 AM
 #21

It is unfortunate that challenges like these are so complicated and that only a few people with specialized hardware and knowledge can take part in this. We need challenges like this that can give open participation to a lot more people, without specialized knowledge to garner a lot more publicity for Bitcoin.

I know it is difficult to create something that would be more accessible for the average guy on the street, but it can be something that can be done by a group of people with different knowledge on several topics and something where groups can all benefit from the rewards. We had something like this before, but the prize was not this big.  Roll Eyes

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malevolent
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July 20, 2019, 11:44:19 AM
 #22

It is unfortunate that challenges like these are so complicated and that only a few people with specialized hardware and knowledge can take part in this. We need challenges like this that can give open participation to a lot more people, without specialized knowledge to garner a lot more publicity for Bitcoin.

Earlier on the puzzle was accessible to everyone with a cheap computer, if it was any easier a single person could have quickly snagged the whole prize. Making each key progressively more difficult to find ensures the challenge will remain open to all for a very long time.

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zielar (OP)
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July 20, 2019, 10:22:53 PM
 #23

For my certainty: what range applies to address 105 (this is the first of the unused, which has the output and pubkey transactions). Something I have to check, high compartment, and it's time to waste a pity :-) According to my calculations, the beginning is 0000000000000000000000000000000000000100000000000000000000000000?

If you want - you can send me a donation to my BTC wallet address 31hgbukdkehcuxcedchkdbsrygegyefbvd
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July 20, 2019, 10:44:50 PM
 #24

For my certainty: what range applies to address 105 (this is the first of the unused, which has the output and pubkey transactions). Something I have to check, high compartment, and it's time to waste a pity :-) According to my calculations, the beginning is 0000000000000000000000000000000000000100000000000000000000000000?
Correct me if I'm wrong but start: 100000000000000000000000000 2^104
                                          end: 1ffffffffffffffffffffffffff 2^105 -1
Plz share if you get any luck
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July 21, 2019, 01:53:55 AM
 #25

For my certainty: what range applies to address 105 (this is the first of the unused, which has the output and pubkey transactions). Something I have to check, high compartment, and it's time to waste a pity :-) According to my calculations, the beginning is 0000000000000000000000000000000000000100000000000000000000000000?
Correct me if I'm wrong but start: 100000000000000000000000000 2^104
                                          end: 1ffffffffffffffffffffffffff 2^105 -1
Plz share if you get any luck

105 bits = 1 + 26x4bits,  so the  range is  obviously
100000000000000000000000000  to 1FFFFFFFFFFFFFFFFFFFFFFFFFF
good luck  Roll Eyes
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July 21, 2019, 05:01:04 AM
 #26

By the way, isn't it kinda scary that a few keys in 80 and 90 bit ranges were already found? Many users have passwords with less bits of security, and passwords also aren't random, so bruteforce can be optimized. Or am I missing something, and those keys were cracked with some algorithm rather than brute force?
you are missing the difference between Asymmetric (elliptic curve) cryptography and Encryption (like Block ciphers). i am not an expert but the algorithms are very different. for example in this topic's case the algorithm (when starting from a certain private key like 2^90) can be simplified to a very simple single point addition but in breaking something like AES you still need to brute force the whole thing.

Quote
if you want to have fun, you can program something. i did that a while ago in c# for small ones as a "challenge" to my skills knowing there is no other reward.

So, I did it and it takes 2.5 ms for me to calculate an address from a raw private key  Cry

doesn't seem that bad. my normal point multiplication takes 42 ms using BigIntegers...
that's not the whole thing though, it is all about the LOOP where you have to repeat the same thing, and  you shouldn't work with raw private key and addresses. you start with the bytes and end with hash bytes and skip any unnecessary conversions.

It is unfortunate that challenges like these are so complicated and that only a few people with specialized hardware and knowledge can take part in this. We need challenges like this that can give open participation to a lot more people, without specialized knowledge to garner a lot more publicity for Bitcoin.

I know it is difficult to create something that would be more accessible for the average guy on the street, but it can be something that can be done by a group of people with different knowledge on several topics and something where groups can all benefit from the rewards. We had something like this before, but the prize was not this big.  Roll Eyes
this is not a giveaway. i believe it is more like a test of the security of a 256 bit elliptic curve, and the incentive is the way to keep an eye on it. the conclusion so far is that 256 is very safe since so far after years of work only ~90 bits of it is searched and the "rewards" were claimed. because of that it is not for the "average guy" while that average guy can still start learning more about ECC and gets his hands dirty...

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j2002ba2
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July 21, 2019, 06:37:07 AM
 #27

#100 - af55fc59c335c8ec67ed24826

Lucky with only 69% of the expected time - 1d 22:49:48 of the 2d 19:46:27 expected.
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July 21, 2019, 06:59:30 AM
 #28

#100 - af55fc59c335c8ec67ed24826

Lucky with only 69% of the expected time - 1d 22:49:48 of the 2d 19:46:27 expected.

What tool and what hardware you have used?
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July 21, 2019, 12:15:00 PM
Last edit: July 21, 2019, 01:26:31 PM by BurtW
 #29

#100 - af55fc59c335c8ec67ed24826

Lucky with only 69% of the expected time - 1d 22:49:48 of the 2d 19:46:27 expected.
Great!  zielar can fill in the #100 entry in the table in the OP.  Congrats on your 1 BTC (approx $10,000) bounty!

For private key 000000000000000000000000000000000000000af55fc59c335c8ec67ed24826

I get:

Uncompressed Bitcoin Address:  1Bv8fD7w52gWTRpnAMTLPvMrsfpX6bySpe
Compressed Bitcoin Address: 1KCgMv8fo2TPBpddVi9jqmMmcne9uSNJ5F

What is your expected time for #105 (approx another $10,500)?

My "back of the envelope" estimate for the estimated times, assuming you can afford or have access to the required hardware:

#100 = 50.0 bits of security was estimated at about 3 days
#105 = 52.5 bits of security will be about 3 x 22.5 = about 17 days
#110 = 55.0 bits of security will be about 3 x 25.0 = about 96 days
#115 = 57.5 bits of security will be about 3 x 27.5 = about 543 days = 1.49 years
#120 = 60.0 bits of security will be about 3 x 210.0 = about 3,072 days = 8.41 years ***
#125 = 62.5 bits of security will be about 3 x 212.5 = about 17,378 days = 47.56 years
#130 = 65.0 bits of security will be about 3 x 215.0 = about 98,304 days = 269.14 years

The last one would be:

#160 = 80.0 bits of security will be about 3 x 230.0 = about 3,221,225,472 days = 8,819,234 years

*** From what I understand 120 bits would be a new world record for "cracking" an EC key pair.

Quote
On 2 December 2016, Daniel J. Bernstein, Susanne Engels, Tanja Lange, Ruben Niederhagen, Christof Paar, Peter Schwabe, and Ralf Zimmermann announced the solution of a generic 117.35-bit elliptic curve discrete logarithm problem on a binary curve, using an optimized FPGA implementation of a parallel version of Pollard's rho algorithm. The attack ran for about six months on 64 to 576 FPGAs in parallel.[30]

From https://en.wikipedia.org/wiki/Discrete_logarithm_records

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July 21, 2019, 01:18:49 PM
Last edit: July 27, 2019, 09:29:17 AM by j2002ba2
 #30

What is your expected time for #105?
I was using 4x Tesla V100 for it. Here is a table with expected times:

|------+-------------------+-------------------|-------------------|
| bits |      4x V100      |     100x V100     |    27648x V100    |
|------+-------------------+-------------------|-------------------|
|  100 |       2d 19:52:51 |          02:42:54 |          00:00:35 |
|  105 |           16 days |          15:21:34 |          00:03:19 |
|  110 |           90 days |       3d 14:53:14 |          00:18:51 |
|  115 |  1 year  147 days |           20 days |          01:46:39 |
|  120 |  7 years 341 days |          116 days |          10:03:23 |
|  125 | 44 years 323 days |  1 year  290 days |       2d 08:53:15 |
|  130 |       253 years   | 10 years  57 days |      13d 09:48:19 |
|  135 |     1,436 years   | 57 years 166 days |      75d 20:24:23 |
|  140 |     8,125 years   |         325 years |  1 year   64 days |
|  145 |    45,964 years   |       1,838 years |  6 years 237 days |
|  150 |   260,011 years   |      10,400 years | 37 years 225 days |
|  155 | 1,470,848 years   |      58,833 years |         212 years |
|  160 | 8,320,376 years   |     332,815 years |       1,203 years |
|------+-------------------+-------------------|-------------------|

Looks like a "world record" would be 120 bits.

Edit: added timings for the fastest (June 2019) top500 supercomputer - Summit.
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July 21, 2019, 01:20:24 PM
 #31

Hey, I got the math right this time!  (pats self on back)

But, I did not go look up the original source for the world record and trusted someone else's post on the number.  I have fixed my post above and taken back my pat on the back.

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July 21, 2019, 01:30:09 PM
 #32

#100 - af55fc59c335c8ec67ed24826

Lucky with only 69% of the expected time - 1d 22:49:48 of the 2d 19:46:27 expected.
Great!  zielar can fill in the #100 entry in the table in the OP.  Congrats on your 1 BTC (approx $10,000) bounty!

+ about 320 USD from BCH Address.

The last one would be:

#160 = 80.0 bits of security will be about 3 x 230.0 = about 3,221,225,472 days = 8,819,234 years
No problem, we will wait  Wink Cheesy Cheesy
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July 21, 2019, 01:43:14 PM
 #33

What is your expected time for #105?
I was using 4x Tesla V100 for it. Here is a table with expected times:

|------+-------------------+-------------------|
| bits |      4x V100      |     100x V100     |
|------+-------------------+-------------------|
|  100 |       2d 19:52:51 |          02:42:54 |
|  105 |           16 days |          15:21:34 |
|  110 |           90 days |       3d 14:53:14 |
|  115 |  1 year  147 days |           20 days |
|  120 |  7 years 341 days |          116 days |
|  125 | 44 years 323 days |  1 year  290 days |
|  130 |       253 years   | 10 years  57 days |
|  135 |     1,436 years   | 57 years 166 days |
|  140 |     8,125 years   |         325 years |
|  145 |    45,964 years   |       1,838 years |
|  150 |   260,011 years   |      10,400 years |
|  155 | 1,470,848 years   |      58,833 years |
|  160 | 8,320,376 years   |     332,815 years |
|------+-------------------+-------------------|

Looks like a "world record" would be 120 bits.

Congratulations on your find! Now go buy some cloud GPU time with your big bounty and crack the next one. Cheesy
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July 21, 2019, 02:19:42 PM
Last edit: September 08, 2019, 07:26:26 PM by bigvito19
 #34

01 0000000000000000000000000000000000000000000000000000000000000001 1BgGZ9tcN4rm9KBzDn7KprQz87SZ26SAMH
02 0000000000000000000000000000000000000000000000000000000000000003 1CUNEBjYrCn2y1SdiUMohaKUi4wpP326Lb
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09 00000000000000000000000000000000000000000000000000000000000001d3 1CQFwcjw1dwhtkVWBttNLDtqL7ivBonGPV
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14 0000000000000000000000000000000000000000000000000000000000002930 1ErZWg5cFCe4Vw5BzgfzB74VNLaXEiEkhk
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62 000000000000000000000000000000000000000000000000363D541EB611ABEE 1Me6EfpwZK5kQziBwBfvLiHjaPGxCKLoJi                 
63 0000000000000000000000000000000000000000000000007CCE5EFDACCF6808 1NpYjtLira16LfGbGwZJ5JbDPh3ai9bjf4

65 000000000000000000000000000000000000000000000001A838B13505B26867 18ZMbwUFLMHoZBbfpCjUJQTCMCbktshgpe

70 0000000000000000000000000000000000000000000000349B84B6431A6C4EF1 19YZECXj3SxEZMoUeJ1yiPsw8xANe7M7QR

75 0000000000000000000000000000000000000000000004C5CE114686A1336E07 1J36UjUByGroXcCvmj13U6uwaVv9caEeAt
 
80 00000000000000000000000000000000000000000000ea1a5c66dcc11b5ad180  1BCf6rHUW6m3iH2ptsvnjgLruAiPQQepLe

85 00000000000000000000000000000000000000000011720c4f018d51b8cebba8  1Kh22PvXERd2xpTQk3ur6pPEqFeckCJfAr

90 000000000000000000000000000000000000000002ce00bb2136a445c71e85bf  1L12FHH2FHjvTviyanuiFVfmzCy46RRATU

95 0000000000000000000000000000000000000000527a792b183c7f64a0e8b1f4  19eVSDuizydXxhohGh8Ki9WY9KsHdSwoQC

100 000000000000000000000000000000000000000af55fc59c335c8ec67ed24826 1KCgMv8fo2TPBpddVi9jqmMmcne9uSNJ5F
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July 21, 2019, 07:19:45 PM
 #35

Update

format #n x%    --> n is case #n and x is how far in % is the key from the lower bound of the corresponding keyspace.

#08 75% ,  #09  82% ,  #10  00% ,  #11  13% ,  #12  31% ,  #13  27% ,   #14  29% ,  #15  64% ,
#16  57% ,  #17  46% ,  #18  52% ,  #19  36% ,  #20  65% ,  #21  73% ,  #22  43% ,  #23  33% ,
#24  72% ,  #25  98% ,  #26  63% ,  #27  67% ,  #28  70% ,  #29  49% ,  #30  92% ,  #31  96% ,
#32  44% ,  #33  66% ,  #34  65% ,  #35  17% ,  #36  23% ,  #37  46% ,  #38  07% ,  #39  18% ,
#40  83% ,  #41  33% ,  #42  32% ,  #43  68% ,  #44  75% ,  #45  14% ,  #46  46% ,  #47  70% ,
#48  36% ,  #49  45% ,  #50  09% ,  #51  83% ,  #52  87% ,  #53  50% ,  #54  11% ,  #55  67% ,
#56  23% ,  #57  92% ,  #58  39% ,  #59  82% ,  #60  97% ,  #61  24% ,  #63  95% ,  #65  66% ,
#70  64% ,  #75  19% ,  #80  83% ,  #85  09% ,  #90  40% ,  #95  29% ,  #100  37%   

He is the resulting histogram (10 bins) which display how these keys are distributed

   0% -  10%        ∎∎∎∎
 10% -  20%        ∎∎∎∎∎∎
 20% -  30%        ∎∎∎∎∎∎
 30% -  40%        ∎∎∎∎∎∎∎∎
 40% -  50%        ∎∎∎∎∎∎∎∎
 50% -  60%        ∎∎∎
 60% -  70%        ∎∎∎∎∎∎∎∎∎∎
 70% -  80%        ∎∎∎∎∎∎
 80% -  90%        ∎∎∎∎∎∎
 90% - 100%       ∎∎∎∎∎∎

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July 23, 2019, 12:04:57 PM
 #36

i think today/tomorrow i open 62
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July 23, 2019, 12:47:08 PM
 #37

Amazing!
Some could change his life with 'simply' solving this one Smiley


yap

i studying python + mathematics + probability theory + bitcoin insideout)))
)) oit's really interesting
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July 23, 2019, 04:33:04 PM
Last edit: July 23, 2019, 06:06:30 PM by Firebox
 #38

drotika, open your PM for newbies please.
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July 24, 2019, 02:43:32 AM
 #39

Drotika:
Bit: 75
Pubkey: 049f6eee498ebd1f4430e9af95e212c365da105b525973b59b17bcf4c4cda3f71da4750479a47af b676ebcc0e7ff10e116c2b810c173f602ae0d95602b1a26fd2c
Pubkey (compressed): 029f6eee498ebd1f4430e9af95e212c365da105b525973b59b17bcf4c4cda3f71d
Address: 1DdM6MipUFcHADvxSjg2NvNvDj4eU9Y7sP
Address (compressed): 1HzpRSSBdpgFBwq2P7a8fvAssVimy9d3RP

Sorry, but 75 bit is easy with pollard kangaroo
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July 24, 2019, 01:04:23 PM
 #40

https://github.com/ralphleon/Python-Algorithms/blob/master/Cryptology/pollard.py
https://gist.github.com/natmchugh/7dbd7e4f7c55d915db1e
https://gist.github.com/thomdixon/dd1e280681f16535fbf1

which one is it?
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