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Author Topic: Bitcoin puzzle (3,350.00 BTC's )  (Read 2491 times)
n0nce
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August 30, 2021, 06:17:42 PM
 #41

WORKED!
RESULT: 2000

PS. BlackHatCoiner I think you don't understand the curve. it is not receipt , it is math and you can do what you want with curve.

I'm gonna be honest, I'm right now not 100% what you are trying to do and what your result tells us, but if you were able to crack the key, you should just show us by moving the funds  Smiley

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August 30, 2021, 07:33:25 PM
 #42

PS. BlackHatCoiner I think you don't understand the curve. it is not receipt , it is math and you can do what you want with curve.
Look, I'm not an expert on the elliptic curves. I'm just interested and learn whenever I'm able to. Your way, indeed, works now that I've rethought about k2 being replaced by k1*2. The whole problem occurs when you know nothing for both k and r, but in this case you can find d given that you have one unknown value k and two unknown values r.

(Didn't actually try your equation, but the steps seem fine by me)

I'm gonna be honest, I'm right now not 100% what you are trying to do and what your result tells us, but if you were able to crack the key, you should just show us by moving the funds  Smiley
I don't think that interiawp tries to find the supposedly hidden 3,350 BTC; he/she just experiments with the maths of ECC as I've noticed from other threads.

If I understood OP correctly, this is not a puzzle or challenge created by them, instead they're trying to crack a key and thinking they're very close & encouraging others to find the solution.
OP should at least provide the source of the puzzle, where did he find it, by whom etc.

.
.HUGE.
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n0nce
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August 30, 2021, 07:59:50 PM
 #43

I don't think that interiawp tries to find the supposedly hidden 3,350 BTC; he/she just experiments with the maths of ECC as I've noticed from other threads.
Riiight I see. The thread should be renamed though if there is no puzzle  Cheesy

If I understood OP correctly, this is not a puzzle or challenge created by them, instead they're trying to crack a key and thinking they're very close & encouraging others to find the solution.
OP should at least provide the source of the puzzle, where did he find it, by whom etc.
Yup for sure, if it really is a puzzle, maybe there are some more details that could help to actually solve it which they lacked to mention in the initial post here.
Puzzles are exciting man but this thread is very confusing; first everyone thought that OP created a puzzle, then it turned out they have no private keys, now it's unsure if a puzzle even exists lol.

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n0nce
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August 31, 2021, 02:25:40 PM
 #44

Someone managed to solve this puzzle, did I miss something?
Doesn't seem so, funds never moved.

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August 31, 2021, 07:14:09 PM
 #45

Yup for sure, if it really is a puzzle, maybe there are some more details that could help to actually solve it which they lacked to mention in the initial post here.
Puzzles are exciting man but this thread is very confusing; first everyone thought that OP created a puzzle, then it turned out they have no private keys, now it's unsure if a puzzle even exists lol.

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September 01, 2021, 04:19:36 PM
 #46

hi everyone..!
I am not clever in crypto, but I do understand the maths. I started reading discussion from the beginning. some people they pretended like einstein..doing lot of mathematics until I though they cracked the private key...just wasted my time reading and trying to understand this shit mathematics...finally the fund is there.... Grin Grin Grin Grin Grin...no body cracked till now.? Huh why all these symbols and mathematics..? even my grand mum can write these symbols..

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September 01, 2021, 05:12:43 PM
 #47

I do have a custom ECC library in JS, it'll be straightforward to add r,s,z calculations and make a browser app that can compute these automatically, to remove manual errors.

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.BLACKJACK ♠ FUN.
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September 05, 2021, 04:45:57 PM
Last edit: September 05, 2021, 04:58:58 PM by bytcoin
 #48

yes
Here it is!

(((TESTNET)))

I sent two transactions to this address:muFPtSuYmYpaqdrNFtwNfm5j2fK2WMtRoz

Transaction 1: https://tbtc.bitaps.com/0faeffb396eebecdade89ef0f66aa002893c3dcb2787283f2d2e6a38edd1da1c/mmjRyw4Zgn7QQVuqTe4YLQmcn82b8aD2L6

z = 0xc8d3c14a3b190b6ea53ce4317fdd51ca1cf1a235dffbc3ce566507061f901a5a
r = 0x42c995eb98c38a8f3de7dde0f5ac63a67441a7e96b821f53931495bc6ea64cb0
s = 0x35a526e609d7022249d46d2392ff7e66b11a303d137204eb909867ae272c24b1

------------------------------------------------------------------------------------------------------------------------------------------------------------------

Transaction 2: https://tbtc.bitaps.com/4728a81966ae288b3c4d9ef781acd9cefe51b7869876abf8796f52940603014e/mmjRyw4Zgn7QQVuqTe4YLQmcn82b8aD2L6

z = 0x57b1d4f6111f1dd7b87db91931682bad285aa2587c6239f7d3beb319ff2e0834
r = 0x4f8bfa709c788b2ed59dd44a16e0c7b22ca7dece56d27144d418577a38b1d0d2
s = 0x096f65fa2a2c6c054b12981c42b0aece4ac861632a2900ced39070f0dd2e86e1

My address : mmjRyw4Zgn7QQVuqTe4YLQmcn82b8aD2L6

My public key : 028ce829db535d42389defbf9ba58731f56ddb1cc7a189e5e30a85d63eb225b5d2

The k value of the second transaction is double the first: k1 * 2 = k2
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September 05, 2021, 04:49:07 PM
 #49

You state that you're giving away 3,350 BTC and yet, you haven't provide us a signed message. What's your excuse for not providing a signed message?

If I understood OP correctly, this is not a puzzle or challenge created by them, instead they're trying to crack a key and thinking they're very close & encouraging others to find the solution.
However wrong assumptions were made and it turned out that it's not so easy to crack a Bitcoin private key  Roll Eyes Grin
Almost that... although I think it's considered a puzzle
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September 05, 2021, 05:09:49 PM
 #50

I do have a custom ECC library in JS, it'll be straightforward to add r,s,z calculations and make a browser app that can compute these automatically, to remove manual errors.
Great. I usually calculate manually, sometimes due to lack of attention it results in some errors
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October 04, 2021, 11:36:29 PM
Last edit: October 04, 2021, 11:49:16 PM by Seraphimjm
 #51

You state that you're giving away 3,350 BTC and yet, you haven't provide us a signed message. What's your excuse for not providing a signed message?

If I understood OP correctly, this is not a puzzle or challenge created by them, instead they're trying to crack a key and thinking they're very close & encouraging others to find the solution.
However wrong assumptions were made and it turned out that it's not so easy to crack a Bitcoin private key  Roll Eyes Grin
Almost that... although I think it's considered a puzzle
its been 6 months.  Do you have any plans on sharing educational material with results which can be reproduced to prove the theory?
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October 30, 2021, 05:41:00 AM
Last edit: October 31, 2021, 05:52:00 AM by albert0bsd
 #52

Well i just calculate some values for k1, k2 and the privatekey but the generated private key don't generate your publickey

Quote
k1: 0xbe404cba76f7018e965637f859560b59701ea7b2b50c3ba2d9899bc14e451032
k2: 0x7c809974edee031d2cac6ff0b2ac16b4258e727ebacfd709f340d8f5cc53df23
pvk: 0x8bfc718f4753611d61d043b499a2af787590cfb220959734c9c8c28406588ee

With any of the values k1 or k2 we can calculate the pvk with the next equation:

pvk = ( k*s - z)/r  (Mod N)

Using your rsz values and my values k1 and k2, both substitutions in equation always give me the same privatekey and well this obvious the equations assume that K2 = 2 * K1 and all the subsequent substitutions come from that supposition.

I heard from other people trying to solving this example in the testnet, that they also solved some privatekey but also they doesn't generate your publickey.



For those who wanna to know how or where the numbers come from, please read ECDSA: Elliptic Curve Signatures there are one equation, that we can use to solve some elements.


(1) :  s = k-1 * (z + r * d) (mod n)

That is the equation that generate the s value. d is the privatekey from that equation we can derive the private key with all the other values s,r,z and k

(2) :  d = ksr-1 - zr-1 (mod n)

We have 2 TX values (s,r,z) with an unknow k, but we "know" the relationship between the two k values

(3) : k2 = 2*K1

Since the equation (2) solve the same private key with the 2 distinct values of r,s,z and k of our transaction we can  use it in the next way

(4) : k1s1r1-1 - z1r1-1 = k2s2r2-1 - z2r2-1 (mod n)

if we substitute (3) in (4) and and then we can solve for k1

(5) : k1 = (z1r1-1 - z2r2-1) / (s1r1-1 - 2r2-1s2) (mod n)

Once that you have the value of k1 you can use it to solve k2 using the equation (3) and use the complete set of values r,s,z and k to solve the private key in the equation (2)



A little code in C using gmp to show this example:

Code:
/*
  gcc -o k1_solver k1_solver.c -lgmp
*/

#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <gmp.h>
#include <time.h>
#include <string.h>

struct Point {
mpz_t x;
mpz_t y;
};

struct Elliptic_Curve {
mpz_t p;
mpz_t n;
};

struct Elliptic_Curve EC;
const char *EC_constant_N = "FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141";

void calculate_pvk(mpz_t pvk,mpz_t r_inv,mpz_t s,mpz_t z,mpz_t k);

int main()  {
mpz_t z1,z2,r2,r1,s1,s2,k1,k2;
mpz_t a,b,c,d,e,f,r1_inv,r2_inv,f_inv;
mpz_t pvk_calulated;

mpz_init_set_str(EC.n, EC_constant_N, 16);
/* Set the R S Z values of the first TX */
mpz_init_set_str(r1,"42c995eb98c38a8f3de7dde0f5ac63a67441a7e96b821f53931495bc6ea64cb0",16);
mpz_init_set_str(s1,"35a526e609d7022249d46d2392ff7e66b11a303d137204eb909867ae272c24b1",16);
mpz_init_set_str(z1,"c8d3c14a3b190b6ea53ce4317fdd51ca1cf1a235dffbc3ce566507061f901a5a",16);
/* Set the R S Z values of the second TX */
mpz_init_set_str(r2,"4f8bfa709c788b2ed59dd44a16e0c7b22ca7dece56d27144d418577a38b1d0d2",16);
mpz_init_set_str(s2,"096f65fa2a2c6c054b12981c42b0aece4ac861632a2900ced39070f0dd2e86e1",16);
mpz_init_set_str(z2,"57b1d4f6111f1dd7b87db91931682bad285aa2587c6239f7d3beb319ff2e0834",16);

/*Init variables GMP stuff */
mpz_init(pvk_calulated);
mpz_init(r1_inv);
mpz_init(r2_inv);
mpz_init(a);
mpz_init(b);
mpz_init(c);
mpz_init(d);
mpz_init(e);
mpz_init(f);
mpz_init(k1);
mpz_init(k2);

/*This Operations are based in the suposition that k2 = 2 * k1 mod n   */
/* calcualte the r1 and r2 Invert*/
mpz_invert(r1_inv,r1,EC.n); // r1_inv = 1/r1
mpz_invert(r2_inv,r2,EC.n); // r2_inv = 1/r2

mpz_mul(a,z1,r1_inv); // a = z1 * r1_inv
mpz_mul(b,z2,r2_inv); // b = z2 * r2_inv
mpz_sub(c,a,b); // c = a - b


mpz_mul(d,r1_inv,s1); // d = r1_inv * s1

mpz_mul(e,r2_inv,s2); // e = r2_inv * s2
mpz_mul_ui(e,e,2); // e = 2 * e

mpz_sub(f,d,e); // f = d - f

mpz_invert(f_inv,f,EC.n); // f_inv = 1/f

mpz_mul(k1,f_inv,c); // k1 = f_inv * c
mpz_mod(k1,k1,EC.n); // k1 = k1 mod n

gmp_printf("k1: %Zx\n",k1);
mpz_mul_ui(k2,k1,2); // k2 = 2 * k1
mpz_mod(k2,k2,EC.n); // k2 = k2 mod n
gmp_printf("k2: %Zx\n",k2);

/* Calculate the pvk with the set of values of the first TX */
calculate_pvk(pvk_calulated,r1_inv,s1,z1,k1);
gmp_printf("pvk_calulated: %Zx\n",pvk_calulated);

/* Calculate the pvk with the set of values of the second TX */
calculate_pvk(pvk_calulated,r2_inv,s2,z2,k2);
gmp_printf("pvk_calulated: %Zx\n",pvk_calulated);
}

void calculate_pvk(mpz_t pvk,mpz_t r_inv,mpz_t s,mpz_t z,mpz_t k) {
mpz_t a,b;
mpz_init(a);
mpz_init(b);
mpz_set(a,k);
mpz_mul(a,a,s);
mpz_mul(a,a,r_inv);
mpz_set(b,r_inv);
mpz_mul(b,b,z);
mpz_sub(a,a,b);
mpz_mod(a,a,EC.n);
mpz_set(pvk,a);
mpz_clear(a);
mpz_clear(b);
}

Regards!

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October 31, 2021, 06:20:20 PM
 #53

Hello albert0bsd,
So, may i ask if this is a real legit puzzle that is solvable then?
or is this a fake puzzle?
and if this puzzle is solvable, what is the chances that actually someone unlock that 3350 BTC Address?
Regards!
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October 31, 2021, 09:21:00 PM
 #54

Hello albert0bsd,
So, may i ask if this is a real legit puzzle that is solvable then?
or is this a fake puzzle?
and if this puzzle is solvable, what is the chances that actually someone unlock that 3350 BTC Address?
Regards!

Well i don't believe that this puzzle is real, but that is what i believe based in what i know about the Elliptic Curve Signatures. The OP don't want to make a message signed with that publickey, that is a strong sign that is not real. but who knows.

Regards!

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