Private key missing 29 characters

[BlackHatCoiner]

Can you tell us more about the private key? You haven't convinced us that this wasn't a dark web deal and you shouldn't hide it, otherwise we can't help you. Anything that is being traded within an anonymous marketplace where each person uses a (pseudo)anonymous currency shouldn't be trusted.

You said that you used bitaddress.org, but you left it there. What happened with the middle characters during the generation? Didn't you write them down? Are these funds yours? How could you not care about your key since you received around the equivalent of four million dollars two years ago?

You can't really believe that you'll find it via brute forcing...

[1713911263]

1713911263

[1713911263]

1713911263

[1713911263]

1713911263

[bigvito19]

Hai guys,

            I have missing 29 characters of a wif private key with 488btc in it does anyone have idea about it how to reconstruct using permutation method and python i know a java script but it is good to find missing 8-10 characters but not for long characters, i know starting and ending but i dont know middle if any python script with gpu attribution added to it then its trying worth a shot.
Your views and suggestions please this is the address 1C8oHWB7htH139na4y8kG4w99MFrepseUv
Thank you

Why should i check entire range if i know upto 136bit please check start and end hex values mentioned in above post
B0BEA32711DBB7429BA37464FFBB4C8CDA2FFFFFFFFFFFFFFFFFFFFFFFFFFFFF -start
B0BEA32711DBB7429BA37464FFBB4C90901000000000000000000000000000 -end
8CDA2FFFFFFFFFFFFFFFFFFFFFFFFFFFFF
90901000000000000000000000000000
This is actual range
ignoring first part
No of Keys need to be checked :-1262600442496196964774503731383792304129 to be exact
this is the address i am looking for 1Btud1pqADgGzgBCZzxzc2b1o1ytk1HYWC

I see he said he has 2 addresses he is looking for so which address he is looking for that he has the partial private key for?


This one         1C8oHWB7htH139na4y8kG4w99MFrepseUv    488.54008752 BTC
  
or this one      1Btud1pqADgGzgBCZzxzc2b1o1ytk1HYWC     4900.00013272 BTC

[kaggie]

let me tell you something broh..
if you are sure it is yours..then go for it. it deserves to be searched.. i know it is impossible, but you don't have any other choice.
BUT, if you got it from DARK WEB, for get it, it is waste of time.

Maybe it's Satoshi's drive, lol.

Minimum

Code:

L39HAHFF1p6vxjBEe4YMxno11111111111111111111111111111
b0bea32711dbb7429ba37464ffbb4c8cda31ea17c6d85d063c0aa4d2c8d5e30f

It looks like a practical joke played out in a cipher.  That L3 line could be making fun, possibly containing intentional words "HAH" and "no".  Who knows what the author's intention was, if there was indeed such an intention. Sorry OP, but I'm 99% certain that you're wasting time.

[Alert31]

Hai guys,

            I have missing 29 characters of a wif private key with 488btc in it does anyone have idea about it how to reconstruct using permutation method and python i know a java script but it is good to find missing 8-10 characters but not for long characters, i know starting and ending but i dont know middle if any python script with gpu attribution added to it then its trying worth a shot.
Your views and suggestions please this is the address 1C8oHWB7htH139na4y8kG4w99MFrepseUv
Thank you

Why should i check entire range if i know upto 136bit please check start and end hex values mentioned in above post
B0BEA32711DBB7429BA37464FFBB4C8CDA2FFFFFFFFFFFFFFFFFFFFFFFFFFFFF -start
B0BEA32711DBB7429BA37464FFBB4C90901000000000000000000000000000 -end
8CDA2FFFFFFFFFFFFFFFFFFFFFFFFFFFFF
90901000000000000000000000000000
This is actual range
ignoring first part
No of Keys need to be checked :-1262600442496196964774503731383792304129 to be exact
this is the address i am looking for 1Btud1pqADgGzgBCZzxzc2b1o1ytk1HYWC

I see he said he has 2 addresses he is looking for so which address he is looking for that he has the partial private key for?


This one         1C8oHWB7htH139na4y8kG4w99MFrepseUv    488.54008752 BTC
  
or this one      1Btud1pqADgGzgBCZzxzc2b1o1ytk1HYWC     4900.00013272 BTC

I also noticed that, he put two different wallet address and he said he has a partial private key on the first wallet address. So, I think he is not really the owner of that wallet addresses with huge amount of bitcoin and just trying to know the private key base on his insane talent.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                               

[iconbtcx]

Hey all brothers,
 
what my point exactly is not you guys getting
so any wif private key has base58 characters 0-1,A-Z,a-z right
this the partial key L39HAHFF1p6vxjBEe4YMxno
recently i got some 35th and 36th letter L39HAHFF1p6vxjBEe4YMxno___________RM________________
what is exactly did is i retraced hex position back and forth and i calculated the private key point where we get matching upto first 23
This the hex B0BEA32711DBB7429BA37464FFBB4C900000207A551210D0BFB07740F939B011
this is the key L39HAHFF1p6vxjBEe4YMxnorYuzZ8gWzNxpP1Yuf5K7Mkbxao6Sz
after xno i slighty moved forward upto r so i retraced back
so i got key L39HAHFF1p6vxjBEe4YMxnnzzyTH8uAzpuaka5Mve1KwLUnW9D3k -- it has xnn -our target starts with xno
the hex is B0BEA32711DBB7429BA37464FFBB4C8CDA2FFFFFFFFFFFFFFFFFFFFFFFFFFFFF --its minimum
and i caclulated maximum hex B0BEA32711DBB7429BA37464FFBB4C9090100000000000000000000000000000 --its maximum
the key is L39HAHFF1p6vxjBEe4YMxnp1QiK7QGtu7PW3QBawhrq2Wd7f6qTN   -- it has xnp--- so this maximum range i observed and learnt that private key follws particular pattern for every step forward in hex value
like L39HAHFF1p6vxjBEe4YMxno, L39HAHFF1p6vxjBEe4YMxno1, L39HAHFF1p6vxjBEe4YMxno2 upto L39HAHFF1p6vxjBEe4YMxno9 then L39HAHFF1p6vxjBEe4YMxnoA-L39HAHFF1p6vxjBEe4YMxnoZ,then L39HAHFF1p6vxjBEe4YMxnoa-L39HAHFF1p6vxjBEe4YMxnoz then the next series starts L39HAHFF1p6vxjBEe4YMxnop so its moves in this pattern first 1-9,then A-Z then a-z.
is there any python scripts that permutates and validates the checksum matching our address with base58 chracters within the above start and end ranges,
the address for this target key is 1Btud1pqADgGzgBCZzxzc2b1o1ytk1HYWC
Thanks for your advice and suggestion

[iconbtcx]

Here i caluclated for 64 puzzle in this way
hex:-8000000000000000  
dec:-9223372036854775808     end dec:- 18446744073709551615
wif:-KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYvLz3frbdQvwtiEXdcN
1/4 dec:-11529215046068469760
1/4page:-90071992547409920
wif:-KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYy1aGkYHUQAHaMZgodk
half:- 13835058055282163712
wif:- KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZ1gAVqDyKPMSmqu4gLM
3/4dec:- 16140901064495857664
wif:- KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZ4LkiuufANZhDQQv7rU
end:-18446744073709551615
wif:-KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZ71LwzbM1MmwA5Y2AFF
for puzzle 64 19 letter need to be permutate,
i divided the entire key space into 4 equal parts then calculated
KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3q this is partilkey Yv, Yw,Yx,Yy,Yz, Z1,Z2,Z3,Z4,Z5,Z6,Z7 are the next seires where the 64 puzzle wif would be
like
KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYv
KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYw
KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYx
...............
KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZ1
................
KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZ7
a python script with permutation that validates checksum with gpu attribution can solve it in matter of hours
thank you

[Trancefan]

nope brother
the private key starts with L3
the key ranges you posted private keys start with K
3803496f04b8c0f3e8335eb24b07a4a15335d37bff03bafbb19640a287e0609a
Ky6bKVgbJPFRiAPxvBo4ftiAMkKCBjAbWfVRWEevsHxgULTthBFB

Sorry, I made two mistakes.
First is adding 1 less character (total 51 instead of 52). The correct values are:
Minimum

Code:

L39HAHFF1p6vxjBEe4YMxno11111111111111111111111111111
b0bea32711dbb7429ba37464ffbb4c8cda31ea17c6d85d063c0aa4d2c8d5e30f

Maximum

Code:

L39HAHFF1p6vxjBEe4YMxnozzzzzzzzzzzzzzzzzzzzzzzzzzzzz
b0bea32711dbb7429ba37464ffbb4c908969f5b84b442e0734743c599dec7459

Diff:
1253753004473247624297767682974128968010 = 1.25E+39 (which is close to your initial value).

Second is that the number I posted is all permutations of the base58 characters if they are placed in their missing positions (ie. 58²⁹) instead of using the method above since all missing characters are from one place at the end without anything in between.

i can able to recover last or even mid where missing seven to eight or upto 10 in matter of minutes thats not an issue
its more than 10 that whats the issue is i am expermienting on it anyway thanks for your suggestions brother

Up to 12 characters from the end can be recovered very easily since you'd essentially be checking less than a million keys. The problem is that the numbers grow very fast as the number of missing chars increase.

This is wrong:

Code:

L39HAHFF1p6vxjBEe4YMxno11111111111111111111111111111
b0bea32711dbb7429ba37464ffbb4c8cda31ea17c6d85d063c0aa4d2c8d5e30f

Maximum

Code:

L39HAHFF1p6vxjBEe4YMxnozzzzzzzzzzzzzzzzzzzzzzzzzzzzz
b0bea32711dbb7429ba37464ffbb4c908969f5b84b442e0734743c599dec7459

The correct is:
b0bea32711dbb7429ba37464ffbb4c8cda31ea17c6d85d063c0aa4d2c8d5e30f=L39HAHFF1p6vxjBEe4YMxnnzzzzzzzzzzzzzzzzzzzzzzfskX9dq
b0bea32711dbb7429ba37464ffbb4c908969f5b84b442e0734743c599dec7459=L39HAHFF1p6vxjBEe4YMxnozzzzzzzzzzzzzzzzzzzzzzv62YdrY