Do you think placing 3 different bet on same game could make you win?

[Salahmu]

Although, I think this is just for a test run, perhaps I haven't tried it before but I want to know if anyone out there has already tried this methods and it works for them.
For instance;
You can have a two powerful team playing match today, and you selected a single bet and places three different bet both teams with the mindset that they would definitely win at last.
Do you think this could boost the way we gamble, let say to give us more winning results.

What do you think?

This type of strategy is called hedging or covering bets. The strategy look smart, because you will have a separate slip for team A, team B and two separate slips for their draws just in case they play draw.

You don't understand the strategy op meant, he is not talking about three different matches playing differently, what he meant is that if Manchester United is playing with Arsenal, he would bet Arsenal to win, Manchester United to also win and lastly also play them a draw and this is only in one match he is talking about, did you get the point now?, so actually if you understand the strategy you will not see it to be smart because you will definitely loss even if one part of the bet wins, this is abnormal strategy in gambling because what it only result is for the gambler to loss.

[Questat]

Do you think casinos have not seen it in advance? Of course, they do.

Its never new at all, a lot have tried that strategy to work, but they all end up only increasing their losses. One is enough, but doing it consistently will probably put you into a bigger loss, much more than what you anticipate.

Let's just face the fact that there can be no way to beat the house. If you insist doing this, its like you are just playing like a fool. You want to take an edge over the house, yet you end up being taken advantage of.

[Rabata]

You will end up being in loss; let's assume you made 3 different bets on a particular game. 1 bet option is with 1.5 odds. The 2nd bet option is the same or a little bit above. And the 3 bets have the same odds or a little bit more. If you win one of the 3, there is no way your winning will be able to give you a profit that will cover up all the staked amount unless if one of your option is with 3 odds and above and that’s where the winning comes from; I will call that pattern an easy way to lose money, not a smart strategy.

I think so, placing 3 different bet on the same games actually can't guarantee still profitable or win but its avoid will get draw and get back capital regarding if one match win but two matches left get loss. Firstly make speculation about odds each three placing bet balance or not before make this speculation, however if the same odds for three bet placing I think the final result only get back your capital.
I don't think good way for gambler placing until three bet at sport betting, why not choose with difference option like place bet for both team win the match or scoring the games. Its more interested and possibility will earn more for placing difference bet at sport betting.

Yes, there is no certainty of winning even in such a bet. A decision can be made by reviewing the odds of the bet. Gambling is definitely risky but if a gambler bets on all 3 of a same football game, his risk will be less, and he may not get any big return. Therefore, if you observe carefully, there is no need to put money in all three bets. You should put it in any one or two. The person who places the bet must decide what his financial situation and strategy will be. There is no way to avoid the risk in placing bets.

[Sandra_hakeem]

What do you think?

I think it's just BS. It’s kind of like thinking that if you bet on red and black in roulette, you’ll end up winning. If you bet on every possible outcome, you’re missing the point that the bookmakers have set the odds so that you’ll lose even in that scenario. So, I agree with Orpichukwu. You are not increasing your chances, you are increasing the cost.

Let's put this into perspective; in a single ticket or a parley (in sport games where there are a lot of options) let's assume the bookies offer 200+ options for a special sports game, then each option gets a dollar bet on a 1.50 odds, equals $200, how many of those options are featured on the winning board? Maybe 30. Each $1 ticket on a 1.50 odd will not pay anything more than $1.50, which means $33 minus tax (could even be less). What stupid way to waste money!