S4VV4S


June 17, 2014, 12:04:49 PM 

The chance to hit a address in use is about:
1.34*10^43 %
0.000,000,000,000,000,000,000,000,000,000,000,000,000,013,4 %
So there is a chance? LOL BTW nobody answered my question: How does one actually SAY this : 1,461,501,637,330,902,918,203,684,832,716,283,019,655,932,542,976









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Timmmaahh


June 17, 2014, 12:11:42 PM 

Wolfram alpha well sure there is a chance.. its like winning the lottory 35 times a row ;)

Crowdfund a students life: 1MxQX4MsF3N3oGpawfgM72K5vzEPeLjTyR



Ekaros


June 17, 2014, 12:19:41 PM 

The chance to hit a address in use is about:
1.34*10^43 %
0.000,000,000,000,000,000,000,000,000,000,000,000,000,013,4 %
So there is a chance? LOL BTW nobody answered my question: How does one actually SAY this : 1,461,501,637,330,902,918,203,684,832,716,283,019,655,932,542,976 http://en.wikipedia.org/wiki/Names_of_large_numbersStart from there to: find the largest number and then start going down.




Timmmaahh


June 17, 2014, 12:21:45 PM 

1 Point 46 Quindecillion

Crowdfund a students life: 1MxQX4MsF3N3oGpawfgM72K5vzEPeLjTyR



rarkenin


June 17, 2014, 12:29:42 PM 

1 Point 46 Quindecillion Let me provide more significant figures in my wording: One quindecillion, four hundred sixtyone quattuordecillion, five hundred one tredecillion, six hundred thirtyseven duodecillion, three hundred thirty undecillion, nine hundred two decillion, nine hundred eighteen nonillion, two hundred three octillion, six hundred eightyfour septillion, eight hundred thirtytwo sextillion, seven hundred sixteen quintillion, two hundred eightythree quadrillion, nineteen trillion, six hundred fiftyfive billion, nine hundred thirtytwo million, five hundred fourtytwo thousand, nine hundred seventysix. Or, http://tts.imtranslator.net/TYni




S4VV4S


June 17, 2014, 12:30:06 PM 

Thanks guys, I was actually expecting to hear the full number I am pretty curious to know how long it will be, like a paragraph or so.




S4VV4S


June 17, 2014, 12:30:37 PM 

1 Point 46 Quindecillion Let me provide more significant figures in my wording: One quindecillion, four hundred sixtyone quattuordecillion, five hundred one tredecillion, six hundred thirtyseven duodecillion, three hundred thirty undecillion, nine hundred two decillion, nine hundred eighteen nonillion, two hundred three octillion, six hundred eightyfour septillion, eight hundred thirtytwo sextillion, seven hundred sixteen quintillion, two hundred eightythree quadrillion, nineteen trillion, six hundred fiftyfive billion, nine hundred thirtytwo million, five hundred fourtytwo thousand, nine hundred seventysix. Or, http://tts.imtranslator.net/TYni^^^ We have a winner and it is a paragraph




Lauda
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GUNBOT Licenses 20% with ref. code 'GrumpyKitty'


June 17, 2014, 12:33:48 PM 

At my current calculations it would take all 7 billion people in the world to use 2,087,859,481,901,289,883,148 addresses. in other words, they would all have to generate 114,403,259,282,262,459 a day for 50 YEARS to run out of addresses. Running out of addresses is unfathomable.
Or in other words, that will never happen. One shouldn't worry about this, these is enough room for everyone to have many addresses.




ljudotina
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June 17, 2014, 12:36:27 PM 

Add adresses and wallets that are intentionaly deleted after some time etc. Not only there is shitload of them, they recicyle too. Cool stuff if you ask me. It's really hard to express how large this numbers are to someone not close to mathematic and phisics. For example i tryed to explain this to my father and i just gave up after some time. Now that i have this block of text (name of number) i think it's gonna be much closer to him....just to see how freaking long does it take to pronounce it




S4VV4S


June 17, 2014, 12:38:20 PM 

At my current calculations it would take all 7 billion people in the world to use 2,087,859,481,901,289,883,148 addresses. in other words, they would all have to generate 114,403,259,282,262,459 a day for 50 YEARS to run out of addresses. Running out of addresses is unfathomable.
Or in other words, that will never happen. One shouldn't worry about this, these is enough room for everyone to have many addresses. I am not worried anymore. I was working on something that uses a new address each time. That's why I was asking Add adresses and wallets that are intentionaly deleted after some time etc. Not only there is shitload of them, they recicyle too. Cool stuff if you ask me. It's really hard to express how large this numbers are to someone not close to mathematic and phisics. For example i tryed to explain this to my father and i just gave up after some time. Now that i have this block of text (name of number) i think it's gonna be much closer to him....just to see how freaking long does it take to pronounce it It is quite long innit?




maok


June 17, 2014, 12:43:29 PM 

There are currently around 200.000 adresses in use: https://blockchain.info/de/charts/nuniqueaddressesThe chance to hit a address in use is about: 1.34*10^43 % 0.000,000,000,000,000,000,000,000,000,000,000,000,000,013,4 % the number you give is the daily count which is more likely ~150.000 addresses used daily. The number of users on blockchain.info alone is approaching 2 millions( https://blockchain.info/charts/mywalletnusers), if you count all other wallets users its a figure of nearly 5 millions users or more. Nevertheless he chance of address collision is still vvvvvvvery low.

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AuroraHF


June 17, 2014, 12:44:37 PM 

It'll take literally forever to run out of unique addresses. So don't worry about it, it won't even be used up even after hundreds of years.




Eotnak


June 17, 2014, 02:54:15 PM 

Page 3 and no sphere pic.
I always enjoy the analogies of these threads. They're different every time. I'd like to know the actual odds of creating duplicate addresses vs. 1000 people winning the lottery everyday for a year. Give me some time and I'll do it myself...

username.bitcoinwallet.com onename.io/support



DannyHamilton
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June 17, 2014, 02:56:17 PM 

Page 3 and no sphere pic.
I always enjoy the analogies of these threads. They're different every time. I'd like to know the actual odds of creating duplicate addresses vs. 1000 people winning the lottery everyday for a year. Give me some time and I'll do it myself...
Which lottery? There are hundreds of them, and they each have different odds.




Syke
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June 17, 2014, 03:06:02 PM 

It's simple, really. If you somehow had vast amounts of computing power, you could mine all of the rest of the bitcoins faster than you could crack a single address.

Buy & Hold



DannyHamilton
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June 17, 2014, 03:09:22 PM 

It's simple, really. If you somehow had vast amounts of computing power, you could mine all of the rest of the bitcoins faster than you could crack a single address.
All you need to do that is to maintain more than 50% of the total network hashing power for the next 125 years or so. It's often called a 51% attack.




Eotnak


June 17, 2014, 03:52:06 PM 

Page 3 and no sphere pic.
I always enjoy the analogies of these threads. They're different every time. I'd like to know the actual odds of creating duplicate addresses vs. 1000 people winning the lottery everyday for a year. Give me some time and I'll do it myself...
Which lottery? There are hundreds of them, and they each have different odds. Fair enough. NY Lottery 6 numbers, chances of 1 person winning 1 time is 1 in 45,057,474 http://nylottery.ny.gov/wps/portal/!ut/p/c4/04_SB8K8xLLM9MSSzPy8xBz9CP0os_jggBC3kDBPE0MLC0dnA09vT0fLQDNvA0dfU_2CbEdFALmTnU!/?PC_7_SPTFTVI4188AC0IKIA9Q6K0QS0_WCM_CONTEXT=/wps/wcm/connect/NYSL+Content+Library/NYSL+Internet+Site/Home/Jackpot+Games/LOTTO/Lotto++Chances+of+Winning

username.bitcoinwallet.com onename.io/support



DannyHamilton
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June 17, 2014, 03:59:06 PM 

Page 3 and no sphere pic.
I always enjoy the analogies of these threads. They're different every time. I'd like to know the actual odds of creating duplicate addresses vs. 1000 people winning the lottery everyday for a year. Give me some time and I'll do it myself...
Which lottery? There are hundreds of them, and they each have different odds. Fair enough. NY Lottery 6 numbers, chances of 1 person winning 1 time is 1 in 45,057,474 If you are trying to find a private key that will allow you to spend the bitcoins associated with a particular bitcoin address... There are 2 ^{160} possible addresses. 2 ^{160} = 1.46 X 10 ^{48}So, the odds of finding such a private key are 1 in 1.46 X 10^{48}The odds of winning the NY lottery 6 numbers Y times in a row are: 1 in 45,057,474 ^{Y}45,057,474 ^{6} = 8.37 X 10 ^{45}45,057,474 ^{7} = 3.77 X 10 ^{53}So the odds of finding such a private key are a bit better than winning the NY lottery 7 times in a row.




Eotnak


June 17, 2014, 04:16:13 PM 

Page 3 and no sphere pic.
I always enjoy the analogies of these threads. They're different every time. I'd like to know the actual odds of creating duplicate addresses vs. 1000 people winning the lottery everyday for a year. Give me some time and I'll do it myself...
Which lottery? There are hundreds of them, and they each have different odds. Fair enough. NY Lottery 6 numbers, chances of 1 person winning 1 time is 1 in 45,057,474 If you are trying to find a private key that will allow you to spend the bitcoins associated with a particular bitcoin address... There are 2 ^{160} possible addresses. 2 ^{160} = 1.46 X 10 ^{48}So, the odds of finding such a private key are 1 in 1.46 X 10^{48}The odds of winning the NY lottery 6 numbers Y times in a row are: 1 in 45,057,474 ^{Y}45,057,474 ^{6} = 8.37 X 10 ^{45}45,057,474 ^{7} = 3.77 X 10 ^{53}So the odds of finding such a private key are a bit better than winning the NY lottery 7 times in a row.Math is awesome, thanks!! I wish I was better at it. I thought the odds were actually going to be a lot more distant than that...but then when I thought about it, Those are the odds of a single person buying a single ticket on 7 different drawings and winning every time. That person cannot ever have purchased a ticket in the past, or ever again in the future...Or as you put it, 7 times in a row.

username.bitcoinwallet.com onename.io/support



DannyHamilton
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June 17, 2014, 04:22:00 PM 

If you are trying to find a private key that will allow you to spend the bitcoins associated with a particular bitcoin address...
There are 2^{160} possible addresses. 2^{160} = 1.46 X 10^{48}
So, the odds of finding such a private key are 1 in 1.46 X 10^{48}
The odds of winning the NY lottery 6 numbers Y times in a row are: 1 in 45,057,474^{Y}
45,057,474^{6} = 8.37 X 10^{45}
45,057,474^{7} = 3.77 X 10^{53}
So the odds of finding such a private key are a bit better than winning the NY lottery 7 times in a row.
Math is awesome, thanks!! I wish I was better at it. I thought the odds were actually going to be a lot more distant than that...but then when I thought about it, Those are the odds of a single person buying a single ticket on 7 different drawings and winning every time. That person cannot ever have purchased a ticket in the past, or ever again in the future...Or as you put it, 7 times in a row. This would be why I generally don't bother playing the lottery. People don't realize how much the odds are stacked against them. Winning multiple times on a single ticket each time multiplies those already astonomical odds to dizzying heights. The best description I've heard of for government run lotteries is: "A lottery is a government tax levied on the absence of mathematical skills."




