[SOLVED] HACKATHON - 0.1 BTC - satoshihack.com

[ca333]

IT S SOLVED. https://blockchain.info/address/1hackxBzktVKWn1FnkSBFoWQC1tWL9nFa

winner please post here. so you get the place in Hall of Fame + 500.000 QoraCoins.

can you post the solution? now the wallet its empty so we can check it

LEVEL 1: the secret code is hided in the second JS-function. You MUST SCROLL DOWN.
LEVEL 2: The URL passes variable to PHP. You must change the variable "68934a3e9455fa72420237eb05902327" which is md5("false") and make it md5("true") = "b326b5062b2f0e69046810717534cb09". in example: http://www.md5-hash.com/md5-text-encrypt
LEVEL3: "<!--%67%6F%6F%64%6A%6F%62%0A%09%09%09-->" is hided in sourcecode. This is URL encoded string. You make the url-decoding: http://meyerweb.com/eric/tools/dencoder/ and it give you: "goodjob"

LEVEL 4: this is again a md5 hash of the value true. 1 can also be true. so md5(1) = "c4ca4238a0b923820dcc509a6f75849b"

LEVEL 5: The key is hided IN the photo. You open the photo in ANY texteditor or with cat/nano/vi/vim and you see on the end of the file:
"5OEDrG8yU1ortreRJXeyVed24BDOatCGvok8PQDthB9M5wVBvChn". so we now from level 1 the hint ROT5. This mean ROT5(originalkey) ="5OEDrG8yU1ortreRJXeyVed24BDOatCGvok8PQDthB9M5wVBvCh". the "n" is one character too much because private keys associated with uncompressed public keys are 51 characters and always start with the number 5 on mainnet.
so you only do it reverse ROT26-ROT5 = ROT21: i.e with: http://planetcalc.com/1434/ and you get real privkey: "5JZYmB8tP1jmomzMESztQzy24WYJvoXBqjf8KLYocW9H5rQWqXc"

[olcaytu2005]

IT S SOLVED. https://blockchain.info/address/1hackxBzktVKWn1FnkSBFoWQC1tWL9nFa

winner please post here. so you get the place in Hall of Fame + 500.000 QoraCoins.

can you post the solution? now the wallet its empty so we can check it

LEVEL 1: the secret code is hided in the second JS-function. You MUST SCROLL DOWN.
LEVEL 2: The URL passes variable to PHP. You must change the variable "68934a3e9455fa72420237eb05902327" which is md5("false") and make it md5("true") = "b326b5062b2f0e69046810717534cb09". in example: http://www.md5-hash.com/md5-text-encrypt
LEVEL3: "<!--%67%6F%6F%64%6A%6F%62%0A%09%09%09-->" is hided in sourcecode. This is URL encoded string. You make the url-decoding: http://meyerweb.com/eric/tools/dencoder/ and it give you: "goodjob"

LEVEL 4: this is again a md5 hash of the value true. 1 can also be true. so md5(1) = "c4ca4238a0b923820dcc509a6f75849b"

LEVEL 5: The key is hided IN the photo. You open the photo in ANY texteditor or with cat/nano/vi/vim and you see on the end of the file:
"5OEDrG8yU1ortreRJXeyVed24BDOatCGvok8PQDthB9M5wVBvChn". so we now from level 1 the hint ROT5. This mean ROT5(originalkey) ="5OEDrG8yU1ortreRJXeyVed24BDOatCGvok8PQDthB9M5wVBvCh". the "n" is one character too much because private keys associated with uncompressed public keys are 51 characters and always start with the number 5 on mainnet.
so you only do it reverse ROT26-ROT5 = ROT21: i.e with: http://planetcalc.com/1434/ and you get real privkey: "5JZYmB8tP1jmomzMESztQzy24WYJvoXBqjf8KLYocW9H5rQWqXc"

it had been very easy 

[ca333]

IT S SOLVED. https://blockchain.info/address/1hackxBzktVKWn1FnkSBFoWQC1tWL9nFa

winner please post here. so you get the place in Hall of Fame + 500.000 QoraCoins.

I am the winner!


Thanks for the hackathon, ca333. Looking forward to more in the future

Congratulations! Post/Send me your QORA-address and i send you 500K Qora. also suggest hodl the qora. We work on it and price is already +20% in some day. It will make + many % in next weeks...

The next hackathon start next week because i find the sponsor now will fund new hackathon!

THANK YOU ALL FOR PARTICIAPTE!!! I hope you have fund in it and it make the brain hot! Next week i make similar difficulty. So come back!

[ca333]

IT S SOLVED. https://blockchain.info/address/1hackxBzktVKWn1FnkSBFoWQC1tWL9nFa

winner please post here. so you get the place in Hall of Fame + 500.000 QoraCoins.

can you post the solution? now the wallet its empty so we can check it

LEVEL 1: the secret code is hided in the second JS-function. You MUST SCROLL DOWN.
LEVEL 2: The URL passes variable to PHP. You must change the variable "68934a3e9455fa72420237eb05902327" which is md5("false") and make it md5("true") = "b326b5062b2f0e69046810717534cb09". in example: http://www.md5-hash.com/md5-text-encrypt
LEVEL3: "<!--%67%6F%6F%64%6A%6F%62%0A%09%09%09-->" is hided in sourcecode. This is URL encoded string. You make the url-decoding: http://meyerweb.com/eric/tools/dencoder/ and it give you: "goodjob"

LEVEL 4: this is again a md5 hash of the value true. 1 can also be true. so md5(1) = "c4ca4238a0b923820dcc509a6f75849b"

LEVEL 5: The key is hided IN the photo. You open the photo in ANY texteditor or with cat/nano/vi/vim and you see on the end of the file:
"5OEDrG8yU1ortreRJXeyVed24BDOatCGvok8PQDthB9M5wVBvChn". so we now from level 1 the hint ROT5. This mean ROT5(originalkey) ="5OEDrG8yU1ortreRJXeyVed24BDOatCGvok8PQDthB9M5wVBvCh". the "n" is one character too much because private keys associated with uncompressed public keys are 51 characters and always start with the number 5 on mainnet.
so you only do it reverse ROT26-ROT5 = ROT21: i.e with: http://planetcalc.com/1434/ and you get real privkey: "5JZYmB8tP1jmomzMESztQzy24WYJvoXBqjf8KLYocW9H5rQWqXc"

how should we know to delete the "n" letter at the end of key? also i deleted it and tried with rot5, but didn't. because you say rot21 know. where rot26 comes from?

also; "Private keys associated with compressed public keys are 52 characters and start with a capital L or K on mainnet (c on testnet)" i

private keys associated with uncompressed public keys are 51 characters and ALWAYS start with 5. and we know that ROT5 is only on alphabetical chars! so then you know it start with 5. So only this option (51 chars) is left...

[jorgelugra]

So what is the relation with rot26 ? how we will know that and relate it

[tuyra]

IT S SOLVED. https://blockchain.info/address/1hackxBzktVKWn1FnkSBFoWQC1tWL9nFa

winner please post here. so you get the place in Hall of Fame + 500.000 QoraCoins.

can you post the solution? now the wallet its empty so we can check it

LEVEL 1: the secret code is hided in the second JS-function. You MUST SCROLL DOWN.
LEVEL 2: The URL passes variable to PHP. You must change the variable "68934a3e9455fa72420237eb05902327" which is md5("false") and make it md5("true") = "b326b5062b2f0e69046810717534cb09". in example: http://www.md5-hash.com/md5-text-encrypt
LEVEL3: "<!--%67%6F%6F%64%6A%6F%62%0A%09%09%09-->" is hided in sourcecode. This is URL encoded string. You make the url-decoding: http://meyerweb.com/eric/tools/dencoder/ and it give you: "goodjob"

LEVEL 4: this is again a md5 hash of the value true. 1 can also be true. so md5(1) = "c4ca4238a0b923820dcc509a6f75849b"

LEVEL 5: The key is hided IN the photo. You open the photo in ANY texteditor or with cat/nano/vi/vim and you see on the end of the file:
"5OEDrG8yU1ortreRJXeyVed24BDOatCGvok8PQDthB9M5wVBvChn". so we now from level 1 the hint ROT5. This mean ROT5(originalkey) ="5OEDrG8yU1ortreRJXeyVed24BDOatCGvok8PQDthB9M5wVBvCh". the "n" is one character too much because private keys associated with uncompressed public keys are 51 characters and always start with the number 5 on mainnet.
so you only do it reverse ROT26-ROT5 = ROT21: i.e with: http://planetcalc.com/1434/ and you get real privkey: "5JZYmB8tP1jmomzMESztQzy24WYJvoXBqjf8KLYocW9H5rQWqXc"

how should we know to delete the "n" letter at the end of key? also i deleted it and tried with rot5, but didn't. because you say rot21 know. where rot26 comes from?

also; "Private keys associated with compressed public keys are 52 characters and start with a capital L or K on mainnet (c on testnet)" i

private keys associated with uncompressed public keys are 51 characters and ALWAYS start with 5. and we know that ROT5 is only on alphabetical chars! so then you know it start with 5. So only this option (51 chars) is left...

how should we know to delete the "n" letter at the end of key? also i deleted it and tried with rot5, but didn't. because you say rot21 know. where rot26 comes from?

also; "Private keys associated with compressed public keys are 52 characters and start with a capital L or K on mainnet (c on testnet)" i

what about  rot26 ?

[ca333]

So what is the relation with rot26 ? how we will know that and relate it

rot26 is total number of possible shift.. and ROT5 is the hint in level 1. and it say back to the roots (revert it).

ROT5(originalkey) = key in photo. i also say often you must DECRYPT it. so its logical that is encrypted format....
so when you revert you have ONLY THIS OPTION: ROT26-ROT5 = ROT 21.

and it even have internetsites with it make it automatically (http://planetcalc.com/1434/).
#edit: so only google for caesar cipher bring you to the solution....
 
so ALSO WHEN YOU NOT SURE YOU CAN TRY IT BOTH. ROT5(key) or ROT21(key) when original key is encoded with ROT5


#EDIT: in IT we start COUNT ON ZERO. so ROT0 is also possible. we have maximum 26 shifts WITH ROT0..
so ROT 25 is max. i count 26 FOR POSSIBLY SHIFTS.

[jorgelugra]

So what is the relation with rot26 ? how we will know that and relate it

rot26 is total number of possible shift. So 26 chars of alphabetica. and ROT5 is the hint in level 1. and it say back to the roots (revert it).

ROT5(originalkey) = key in photo. i also say often you must DECRYPT it. so its logical that is encrypted format....
so when you revert you have ONLY THIS OPTION: ROT26-ROT5 = ROT 21.

and it even have internetsites with it make it automatically (http://planetcalc.com/1434/).
#edit: so only google for caesar cipher bring you to the solution....
 
so ALSO WHEN YOU NOT SURE YOU CAN TRY IT BOTH. ROT5(key) or ROT21(key) when original key is encoded with ROT5

ah that is the problem, your alphabet have 26 chars lol, well i did my best

[costgranda]

So what is the relation with rot26 ? how we will know that and relate it

rot26 is total number of possible shift. So 26 chars of alphabetica. and ROT5 is the hint in level 1. and it say back to the roots (revert it).

ROT5(originalkey) = key in photo. i also say often you must DECRYPT it. so its logical that is encrypted format....
so when you revert you have ONLY THIS OPTION: ROT26-ROT5 = ROT 21.

and it even have internetsites with it make it automatically (http://planetcalc.com/1434/).
#edit: so only google for caesar cipher bring you to the solution....
 
so ALSO WHEN YOU NOT SURE YOU CAN TRY IT BOTH. ROT5(key) or ROT21(key) when original key is encoded with ROT5

ah that is the problem, your alphabet have 26 chars lol, well i did my best

lol i was stuck there too, thanks for the game ca333 so you will post a hackaton every 2 weeks? that is not much time?

[ca333]

So what is the relation with rot26 ? how we will know that and relate it

rot26 is total number of possible shift. So 26 chars of alphabetica. and ROT5 is the hint in level 1. and it say back to the roots (revert it).

ROT5(originalkey) = key in photo. i also say often you must DECRYPT it. so its logical that is encrypted format....
so when you revert you have ONLY THIS OPTION: ROT26-ROT5 = ROT 21.

and it even have internetsites with it make it automatically (http://planetcalc.com/1434/).
#edit: so only google for caesar cipher bring you to the solution....
 
so ALSO WHEN YOU NOT SURE YOU CAN TRY IT BOTH. ROT5(key) or ROT21(key) when original key is encoded with ROT5

ah that is the problem, your alphabet have 26 chars lol, well i did my best

no sorry i make wrong explanation. i mean not alphabetical signs. i mean its maximal shifts is 26 from latin. so ZERO (ROT0) is also option when shift = ZERO.

so in the example we have. the ROT0(keyFromPhoto) you must make a ROT21(keyFromPhoto) for DECODE. because we have a ROT5 from ORIGINAL KEY.

EXAMPLE: I say ROT5 is hint. Now you take the CODE FROM IMAGE AND EVERY ALPHABETICAL SIGN YOU GO BACK 5 positions. So example:
5OEDrG8yU1ortreRJXeyVed24BDOatCGvok8PQDthB9M5wVBvCh
5JZYmB8tP1jmomzMESztQzy24WYJvoXBqjf8KLYocW9H5rQWqXc

[ca333]

lol i was stuck there too, thanks for the game ca333 so you will post a hackaton every 2 weeks? that is not much time?

thank you i am happy you like it!

i make a new hackathon NEXT weekend. so i have one sponsor for one more hackathon. And in 2 weeks i make a bigger hackathon with bigger price and little more difficult.

i let the hackathon online. so when you want play again you can always.


and when you have general questions you can ask me here: https://bitcointalk.org/index.php?topic=993678
or in IRC: #satoshihack

THANK YOU ALL AGAIN FOR COME IN THE HACKATHON!

[jlga]

congratulations to the winner, i have tried and i was stuck on the level 4

[DougB62]

congratulations to the winner, i have tried and i was stuck on the level 4

Yeah - I was stuck @ lvl4 also. But it was tremendous fun, and I'm looking forward to the next one! 

[luciann]

so did anyone got a chance to solve the site?

[fast2fix]

so did anyone got a chance to solve the site?

yes injust solved it successfully and won the prize 0.1 btc. i would participate in the coming competition, when is the next competition/hackathon?

[ndnh]

From next time, OP should request a signed message from the winner to confirm that he is really the winner, before sending the Qora.

Just a little advice. Don't know if you already did it.

[ca333]

so did anyone got a chance to solve the site?

yes injust solved it successfully and won the prize 0.1 btc. i would participate in the coming competition, when is the next competition/hackathon?

you can see the next competition countdown on www.satoshihack.com.
its coming weekend.

From next time, OP should request a signed message from the winner to confirm that he is really the winner, before sending the Qora.

Just a little advice. Don't know if you already did it.

no still not sent. but its the confirmed winner. He sended me also PMs.

[Injust]

-----BEGIN BITCOIN SIGNED MESSAGE-----
I, Injust of Bitcoin Forum, verify that I am the winner of the 1st SatoshiHack hackathon.
I also would like to collect the 500k QORA, which should be sent to QgWfhvQJuYSGXTEq5g7zrr5SWZgFSt5cGw.
-----BEGIN SIGNATURE-----
15eiAnGmwGVKSGjSKowcDw7N6CmhG7jfoo
HNncjff3u8GK8yxLuPx7c02Yqys4yWtKgXhP7jHv/QaLb7DzWifWAc9isEI9hp3seOmvyW65lXBrhKzxBtOre2c=
-----END BITCOIN SIGNED MESSAGE-----

[ndnh]

-----BEGIN BITCOIN SIGNED MESSAGE-----
I, Injust of Bitcoin Forum, verify that I am the winner of the 1st SatoshiHack hackathon.
I also would like to collect the 500k QORA, which should be sent to QgWfhvQJuYSGXTEq5g7zrr5SWZgFSt5cGw.
-----BEGIN SIGNATURE-----
15eiAnGmwGVKSGjSKowcDw7N6CmhG7jfoo
HNncjff3u8GK8yxLuPx7c02Yqys4yWtKgXhP7jHv/QaLb7DzWifWAc9isEI9hp3seOmvyW65lXBrhKzxBtOre2c=
-----END BITCOIN SIGNED MESSAGE-----

lol, Congratz again

[wizzardTim]

Contratz to the winner!!!


Also many thanx to OP for providing this interesting and beautiful challenge! Keep it up!