So that is 9 coins all funded but one with 1BTC yes. There are only two 1 BTC coin, one of them is funded with 1 BTC the other is empty. Other coins are funded with their face value. Thanks! Is above is correct ^^ 1.5 BTC |
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So that is 9 coins all funded but one with 1 BTC  |
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whatever might be but looks so awesome  if you interest, you can pm me  hehe I'm but i cannot get any type of weapons imported or exported - it's illegal in my country  |
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here too Who won ? |
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so were all opened yet? is the price out ?  |
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That ain't no riffle - that's a BLUNDERBUSS!!! Jaaarg! whatever might be but looks so awesome |
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I want three spots as well. it's not daily when you get 3 spots good luck man! |
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hey! still any of these left to grab??
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Coin A : 1.8BTC
Coin D : 0.8BTC
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ain't that something Can't get it here though |
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 Had a surprise come in the mail today. # 27 set complete They look great! Did you got the stands below with it ? oor you bought them somewhere else? |
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i'll start it off with
0.1BTC
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The first 5 Casascius is just a estimation - i don't think they are that big worth 0.5 BTC lol i want one ticket so much but i gotta think about it! |
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Got my D1 and D3 Today
My first coins from Silver Wallets!
Pretty amazing
Thanks!
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Got them! Such beautiful  |
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Great
Will be know the prices of the raffle or will it be a mystery??
I'll prefer to know them
I'll release a list of all the prizes. Great! look forward to it! Also , i hope that since ticket cost will be high and it might take time to fill all tickets - so probably just register name and then when all filled - take payment ?? Just what i think Registering names wouldn't be a bad idea. I'm also trying to find other fair ways to generate numbers other than blockchain. At the moment I could do 25 prizes varying from 0.06 BTC to 4.0 BTC. But it wouldn't evenly distribute chances among block hashes. For example (Block hash ending in): 0-8 0 - entrant A - meaning 00, 10, 20, 30, 40, 50, 60, 70, 80 9-f 0 - entrant B - meaning 90, a0, b0, c0, d0, e0, f0 0-8 1 - entrant C 9-f 1 - entrant D This would generate 32 tickets with even probabilities of winning. To tell you i didn't understood it at all I'll use real blocks as an example: Say the raffle used block 413332 then 413333 and so on and so on. Block #413333, the hash ended in "4d" Block #413332 ended in "50" So if you picked "0-8 0" you would get the first prize. If you picked "0-8 d" you would get the second prize. The entry list looks like this: 0-8 0 - Person A
9-f 0 -
0-8 1 -
9-f 1 -
0-8 2 -
9-f 2 -
0-8 3 -
9-f 3 -
0-8 4 -
9-f 4 -
0-8 5 -
9-f 5 -
0-8 6 -
9-f 6 -
0-8 7 -
9-f 7 -
0-8 8 -
9-f 8 -
0-8 9 -
9-f 9 -
0-8 a -
9-f a -
0-8 b -
9-f b -
0-8 c -
9-f c -
0-8 d - Person B
9-f d -
0-8 e -
9-f e -
0-8 f -
9-f f -
Looks awesome!! Look forward to what the prices will be |
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BUMP |
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I could lower these coins sure and add more onto others in the Gold digger Series but them people would complain about that. So it is catch 22 really. I guess the people who will not buy the platinum will want these lowered. Remember for the Gold Digger Series there is a 5 BTC prize which needs to be paid for. So I am sorry but it is the final price.
What I can do is give a 0.02BTC reduction on postage if you buy both coins at the same time.
that is true but not everyone can buy the last platinum one and Really the Puzzles are FREAKING HARDBut i still want one  |
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