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Bitcoin / Bitcoin Discussion / Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

on: April 16, 2023, 10:22:28 AM

Quote from: saatoshi_rising on April 27, 2017, 06:41:08 AM Quote from: sabbybibi on March 13, 2017, 04:17:30 PM This puzzle is very strange. If it's for measuring the world's brute forcing capacity, 161-256 are just a waste (RIPEMD160 entropy is filled by 160, and by all of P2PKH Bitcoin). The puzzle creator could improve the puzzle's utility without bringing in any extra funds from outside - just spend 161-256 across to the unsolved portion 51-160, and roughly treble the puzzle's content density. If on the other hand there's a pattern to find... well... that's awfully open-ended... can we have a hint or two? I am the creator. You are quite right, 161-256 are silly. I honestly just did not think of this. What is especially embarrassing, is this did not occur to me once, in two years. By way of excuse, I was not really thinking much about the puzzle at all. I will make up for two years of stupidity. I will spend from 161-256 to the unsolved parts, as you suggest. In addition, I intend to add further funds. My aim is to boost the density by a factor of 10, from 0.001length(key) to 0.01length(key). Probably in the next few weeks. At any rate, when I next have an extended period of quiet and calm, to construct the new transaction carefully. A few words about the puzzle. There is no pattern. It is just consecutive keys from a deterministic wallet (masked with leading 000...0001 to set difficulty). It is simply a crude measuring instrument, of the cracking strength of the community. Finally, I wish to express appreciation of the efforts of all developers of new cracking tools and technology. The "large bitcoin collider" is especially innovative and interesting! The value of unsolving puzzles goes up 10X today😇

Economy / Speculation / Re: I do believe that Bitcoin will be more scarce than gold

on: August 02, 2022, 01:21:55 PM

Bitcoin and Gold is different

Bitcoin / Bitcoin Discussion / Re: If Satoshi is not dead, what is he doing?

on: August 02, 2022, 07:23:52 AM

Why he still hiding?

Local / Bahasa Indonesia (Indonesian) / Re: Indodax jebol atau Human Error ?

on: November 26, 2018, 03:53:28 AM

Hanya sekedar menambahkan. Untuk keamanan, simpan bitcoin di wallet pribadi dan amankan PK Tidak menyimpan btc di wallet market(indodax).

Bitcoin / Bitcoin Discussion / Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

on: November 23, 2018, 03:35:09 AM

Quote from: saatoshi_rising on April 27, 2017, 06:41:08 AM Quote from: sabbybibi on March 13, 2017, 04:17:30 PM This puzzle is very strange. If it's for measuring the world's brute forcing capacity, 161-256 are just a waste (RIPEMD160 entropy is filled by 160, and by all of P2PKH Bitcoin). The puzzle creator could improve the puzzle's utility without bringing in any extra funds from outside - just spend 161-256 across to the unsolved portion 51-160, and roughly treble the puzzle's content density. If on the other hand there's a pattern to find... well... that's awfully open-ended... can we have a hint or two? I am the creator. You are quite right, 161-256 are silly. I honestly just did not think of this. What is especially embarrassing, is this did not occur to me once, in two years. By way of excuse, I was not really thinking much about the puzzle at all. I will make up for two years of stupidity. I will spend from 161-256 to the unsolved parts, as you suggest. In addition, I intend to add further funds. My aim is to boost the density by a factor of 10, from 0.001length(key) to 0.01length(key). Probably in the next few weeks. At any rate, when I next have an extended period of quiet and calm, to construct the new transaction carefully. A few words about the puzzle. There is no pattern. It is just consecutive keys from a deterministic wallet (masked with leading 000...0001 to set difficulty). It is simply a crude measuring instrument, of the cracking strength of the community. Finally, I wish to express appreciation of the efforts of all developers of new cracking tools and technology. The "large bitcoin collider" is especially innovative and interesting! The pattern is 12 or 24 mnemonic ?

Bitcoin / Project Development / Re: Faster and Autonomous Large Bitcoin Collider upgrade

on: September 16, 2018, 09:48:03 PM

Congratulations! Can someone show me the pk no 161 - 256 ? Thx @holy_ship @Andzhig @Arulbero @BurtW

Bitcoin / Bitcoin Discussion / Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

on: September 16, 2018, 09:07:23 PM

Congratulation! Next : 57 2^56 ~ 2^57

Bitcoin / Bitcoin Discussion / Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

on: August 04, 2018, 12:13:08 PM

Quote from: Andzhig on August 02, 2018, 02:38:05 PM This he saw the ladder without fractional (seemingly). Some stalactites.. 36028797018963968 30045390491869460 9974455244496708‬ 6763683971478124‬ 4216495639600700‬ 18014398509481984 15022695245934730‬ 4987227622248354‬ 3381841985739062‬ 2108247819800350‬ 9007199254740992 1 7511347622967365‬ 1 2493613811124177‬ 1 1690920992869531‬ 1054123909900175‬ 4503599627370496 3755673811483682‬ 1246806905562088 ‬1 845460496434765‬ 1 527061954950087‬ 2251799813685248 1 1877836905741841‬ 623403452781044‬ 422730248217382‬ 1 263530977475043‬ 1125899906842624 938918452870920‬ 311701726390522‬ 1 211365124108691‬ 131765488737521‬ 562949953421312 469459226435460‬ 1 155850863195261‬ 1 105682562054345‬ 65882744368760‬ 281474976710656 234729613217730‬ 77925431597630‬ 52841281027172‬ 32941372184380‬ 140737488355328 1 117364806608865‬ 1 38962715798815‬ 26420640513586‬ 16470686092190‬ 70368744177664 58682403304432‬ 1 19481357899407‬ 1 13210320256793‬ 1 8235343046095‬ 35184372088832 29341201652216‬ 1 9740678949703‬ 6605160128396‬ 1 4117671523047‬ 17592186044416 14670600826108‬ 1 4870339474851‬ 3302580064198‬ 1 2058835761523‬ 8796093022208 7335300413054‬ 1 2435169737425‬ 1 1651290032099‬ 1 1029417880761‬ 4398046511104 1 3667650206527‬ 1217584868712‬ 1 825645016049‬ 514708940380‬ 2199023255552 1 1833825103263‬ 608792434356‬ 412822508024‬ 257354470190‬ 1099511627776 1 916912551631‬ 304396217178‬ 206411254012‬ 1 128677235095 ‬ 549755813888 1 458456275815‬ 1 152198108589‬ 103205627006‬ 1 64338617547‬ 274877906944 1 229228137907‬ 76099054294‬ 1 51602813503‬ 1 32169308773‬ 137438953472 1 114614068953‬ 1 38049527147‬ 1 25801406751‬ 16084654386‬ 68719476736 57307034476‬ 1 19024763573‬ 1 12900703375‬ 1 8042327193‬ 34359738368 28653517238‬ 9512381786‬ 1 6450351687‬ 4021163596‬ 17179869184 1 14326758619‬ 1 4756190893‬ 1 3225175843‬ 2010581798‬ 8589934592 1 7163379309‬ 2378095446‬ 1 1612587921‬ 1 1005290899‬ 4294967296 3581689654‬ 1 1189047723‬ 806293960‬ 1 502645449‬ 2147483648 1 1790844827‬ 1 594523861‬ 403146980‬ 251322724‬ 1073741824 1 895422413‬ 297261930‬ 201573490‬ 125661362‬ 536870912 447711206‬ 1 148630965‬ 1 100786745‬ 1 62830681‬ 268435456 1 223855603‬ 74315482‬ 50393372‬ 31415340‬ 134217728 1 111927801‬ 1 37157741‬ 25196686‬ 15707670‬ 67108864 55963900‬ 18578870‬ 1 12598343‬ 1 7853835‬ 33554432 27981950‬ 1 9289435‬ 1 6299171‬ 1 3926917‬ 16777216 1 13990975‬ 1 4644717‬ 1 3149585‬ 1963458‬ 8388608 1 6995487 2322358‬ 1 1574792‬ 1 981729‬ 4194304 1 3497743 1 1161179‬ 787396‬ 490864‬ 2097152 1 1748871 1 580589‬ 393698‬ 245432‬ 1048576 1 874435 290294‬ 1 196849‬ 122716‬ 524288 1 437217 1 145147‬ 98424‬ 61358‬ 262144 218608 1 72573‬ 49212‬ 1 30679‬ 131072 109304 36286‬ 24606‬ 1 15339‬ 65536 54652 1 18143‬ 1 12303‬ 1 7669‬ 32768 27326 1 9071‬ 1 6151‬ 3834‬ 16384 1 13663 1 4535‬ 1 3075‬ 1 1917‬ 8192 1 6831 1 2267‬ 1 1537‬ 958‬ 4096 1 3415 1 1133‬ 768‬ 1 479‬ 2048 1 1707 566‬ 384‬ 1 239‬ 1024 1 853 1 283‬ 192‬ 1 119‬ 512 426 1 141‬ 96‬ 1 59‬ 256 1 213 70‬ 48‬ 1 29‬ 128 106 1 35‬ 24 14‬ 64 1 53 1 17‬ 12 1 7‬ 32 26 8 ‬ 6 1 3‬ 16 1 13 4 1 3 1‬ 8 6 2 1 4 1 3 1 2 1 1 at some steps added 1. In the python 3 it will look like Quote a1 = 1 a2 = a1 * 2 +1 a3 = a2 * 2 a4 = a3 * 2 +1 a5 = a4 * 2 a6 = a5 * 2 +1 a7 = a6 * 2 a8 = a7 * 2 +1 a9 = a8 * 2 a10 = a9 * 2 +1 a11 = a10 * 2 +1 a12 = a11 * 2 +1 a13 = a12 * 2 +1 a14 = a13 * 2 +1 a15 = a14 * 2 a16 = a15 * 2 a17 = a16 * 2 a18 = a17 * 2 a19 = a18 * 2 +1 a20 = a19 * 2 +1 a21 = a20 * 2 +1 a22 = a21 * 2 +1 a23 = a22 * 2 +1 a24 = a23 * 2 +1 a25 = a24 * 2 a26 = a25 * 2 a27 = a26 * 2 +1 a28 = a27 * 2 +1 a29 = a28 * 2 a30 = a29 * 2 +1 a31 = a30 * 2 +1 a32 = a31 * 2 a33 = a32 * 2 +1 a34 = a33 * 2 +1 a35 = a34 * 2 a36 = a35 * 2 a37 = a36 * 2 +1 a38 = a37 * 2 +1 a39 = a38 * 2 +1 a40 = a39 * 2 +1 a41 = a40 * 2 +1 a42 = a41 * 2 +1 a43 = a42 * 2 a44 = a43 * 2 a45 = a44 * 2 a46 = a45 * 2 a47 = a46 * 2 +1 a48 = a47 * 2 a49 = a48 * 2 a50 = a49 * 2 a51 = a50 * 2 +1 a52 = a51 * 2 a53 = a52 * 2 +1 a54 = a53 * 2 a55 = a54 * 2 print(a31,a55) where a31 possible address (+ 200000000 or +500000000 not to smear) for scanning by Holy fork (1790844827 * 2 24 times = 30045390485061632 against 30045390491869460 the right. Accordingly, placing correctly the pros can successfully jump. Quote from bitcoin import * a1 = 1 a2 = a1 * 2 +1 a3 = a2 * 2 a4 = a3 * 2 a5 = a4 * 2 +1 a6 = a5 * 2 +1 a7 = a6 * 2 a8 = a7 * 2 +1 a9 = a8 * 2 a10 = a9 * 2 a11 = a10 * 2 +1 a12 = a11 * 2 +1 a13 = a12 * 2 a14 = a13 * 2 a15 = a14 * 2 a16 = a15 * 2 +1 a17 = a16 * 2 +1 a18 = a17 * 2 +1 a19 = a18 * 2 +1 a20 = a19 * 2 a21 = a20 * 2 a22 = a21 * 2 a23 = a22 * 2 +1 a24 = a23 * 2 +1 a25 = a24 * 2 a26 = a25 * 2 +1 a27 = a26 * 2 +1 a28 = a27 * 2 +1 a29 = a28 * 2 +1 a30 = a29 * 2 a31 = a30 * 2 a32 = a31 * 2 +1 # fork scan point 2>24 a33 = a32 2 a34 = a33 * 2 a35 = a34 * 2 a36 = a35 * 2 a37 = a36 * 2 a38 = a37 * 2 a39 = a38 * 2 a40 = a39 * 2 a41 = a40 * 2 a42 = a41 * 2 a43 = a42 * 2 a44 = a43 * 2 a45 = a44 * 2 a46 = a45 * 2 a47 = a46 * 2 a48 = a47 * 2 a49 = a48 * 2 a50 = a49 * 2 a51 = a50 * 2 a52 = a51 * 2 a53 = a52 * 2 a54 = a53 * 2 a55 = a54 * 2 a56 = a55 * 2 scan = a32222222222222222222222222+200000000 ran = scan myhex = "%064x" % ran myhex = myhex[:64] priv = myhex pub = privtopub(priv) pubkey1 = encode_pubkey(privtopub(priv), "bin_compressed") addr = pubtoaddr(pubkey1) print(a32,scan,a56,addr,myhex) Or manually do not put up pluses Quote import secrets from bitcoin import * b1 = secrets.choice([0,1]) b2 = secrets.choice([0,1]) b3 = secrets.choice([0,1]) b4 = secrets.choice([0,1]) b5 = secrets.choice([0,1]) b6 = secrets.choice([0,1]) b7 = secrets.choice([0,1]) b8 = secrets.choice([0,1]) b9 = secrets.choice([0,1]) b10 = secrets.choice([0,1]) b11 = secrets.choice([0,1]) b12 = secrets.choice([0,1]) b13 = secrets.choice([0,1]) b14 = secrets.choice([0,1]) b15 = secrets.choice([0,1]) b16 = secrets.choice([0,1]) b17 = secrets.choice([0,1]) b18 = secrets.choice([0,1]) b19 = secrets.choice([0,1]) b20 = secrets.choice([0,1]) b21 = secrets.choice([0,1]) b22 = secrets.choice([0,1]) b23 = secrets.choice([0,1]) b24 = secrets.choice([0,1]) b25 = secrets.choice([0,1]) b26 = secrets.choice([0,1]) b27 = secrets.choice([0,1]) b28 = secrets.choice([0,1]) b29 = secrets.choice([0,1]) b30 = secrets.choice([0,1]) b31 = secrets.choice([0,1]) a1 = 1 a2 = a1 * 2 +b1 a3 = a2 * 2 +b2 a4 = a3 * 2 +b3 a5 = a4 * 2 +b4 a6 = a5 * 2 +b5 a7 = a6 * 2 +b6 a8 = a7 * 2 +b7 a9 = a8 * 2 +b8 a10 = a9 * 2 +b9 a11 = a10 * 2 +b10 a12 = a11 * 2 +b11 a13 = a12 * 2 +b12 a14 = a13 * 2 +b13 a15 = a14 * 2 +b14 a16 = a15 * 2 +b15 a17 = a16 * 2 +b16 a18 = a17 * 2 +b17 a19 = a18 * 2 +b18 a20 = a19 * 2 +b19 a21 = a20 * 2 +b20 a22 = a21 * 2 +b21 a23 = a22 * 2 +b22 a24 = a23 * 2 +b23 a25 = a24 * 2 +b24 a26 = a25 * 2 +b25 a27 = a26 * 2 +b26 a28 = a27 * 2 +b27 a29 = a28 * 2 +b28 a30 = a29 * 2 +b29 a31 = a30 * 2 +b30 a32 = a31 * 2 +b31 # fork scan point 2>24 scanpoint = a32222222222222222222222222+200000000 ran = scanpoint myhex = "%064x" % ran myhex = myhex[:64] priv = myhex pub = privtopub(priv) pubkey1 = encode_pubkey(privtopub(priv), "bin_compressed") addr = pubtoaddr(pubkey1) print(a32,scanpoint,b1,b2,b3,b4,b5,b6,b7,b8,b9,b10,b11,b12,b13,b14,b15,b16,b17,b18,b19,b20,b21,b22,b23,b24,b25,b26,b27,b28,b29,b30,b31,addr,priv) can make autostart fork adding (fork folder and cmd file itself lie on c:\) to loop or duplicate the repetition of the code, to whom it is more convenient, you can run several forks slightly correcting a couple of characters Quote import subprocess import time oy = """cd "C:\forkfolder1" """ ey = "\nstart /min oclvanitygen.exe -D 1:0 -C -f addresses.txt -o found.txt " f=open("C:/testpy1.cmd","w") f.write (oy) f.write (ey) f.write (priv) # adds the start address of the scan f.close() subprocess.Popen([r"C:/testpy1.cmd"]) time.sleep(60.0) # seconds before the scanner is closed subprocess.call("taskkill /IM oclvanitygen.exe") or for luck 56 Quote from bitcoin import import secrets while True: b1 = secrets.choice([0,1]) b2 = secrets.choice([0,1]) b3 = secrets.choice([0,1]) b4 = secrets.choice([0,1]) b5 = secrets.choice([0,1]) b6 = secrets.choice([0,1]) b7 = secrets.choice([0,1]) b8 = secrets.choice([0,1]) b9 = secrets.choice([0,1]) b10 = secrets.choice([0,1]) b11 = secrets.choice([0,1]) b12 = secrets.choice([0,1]) b13 = secrets.choice([0,1]) b14 = secrets.choice([0,1]) b15 = secrets.choice([0,1]) b16 = secrets.choice([0,1]) b17 = secrets.choice([0,1]) b18 = secrets.choice([0,1]) b19 = secrets.choice([0,1]) b20 = secrets.choice([0,1]) b21 = secrets.choice([0,1]) b22 = secrets.choice([0,1]) b23 = secrets.choice([0,1]) b24 = secrets.choice([0,1]) b25 = secrets.choice([0,1]) b26 = secrets.choice([0,1]) b27 = secrets.choice([0,1]) b28 = secrets.choice([0,1]) b29 = secrets.choice([0,1]) b30 = secrets.choice([0,1]) b31 = secrets.choice([0,1]) b32 = secrets.choice([0,1]) b33 = secrets.choice([0,1]) b34 = secrets.choice([0,1]) b35 = secrets.choice([0,1]) b36 = secrets.choice([0,1]) b37 = secrets.choice([0,1]) b38 = secrets.choice([0,1]) b39 = secrets.choice([0,1]) b40 = secrets.choice([0,1]) b41 = secrets.choice([0,1]) b42 = secrets.choice([0,1]) b43 = secrets.choice([0,1]) b44 = secrets.choice([0,1]) b45 = secrets.choice([0,1]) b46 = secrets.choice([0,1]) b47 = secrets.choice([0,1]) b48 = secrets.choice([0,1]) b49 = secrets.choice([0,1]) b50 = secrets.choice([0,1]) b51 = secrets.choice([0,1]) b52 = secrets.choice([0,1]) b53 = secrets.choice([0,1]) b54 = secrets.choice([0,1]) b55 = secrets.choice([0,1]) a1 = 1 a2 = a1 * 2 +b1 a3 = a2 * 2 +b2 a4 = a3 * 2 +b3 a5 = a4 * 2 +b4 a6 = a5 * 2 +b5 a7 = a6 * 2 +b6 a8 = a7 * 2 +b7 a9 = a8 * 2 +b8 a10 = a9 * 2 +b9 a11 = a10 * 2 +b10 a12 = a11 * 2 +b11 a13 = a12 * 2 +b12 a14 = a13 * 2 +b13 a15 = a14 * 2 +b14 a16 = a15 * 2 +b15 a17 = a16 * 2 +b16 a18 = a17 * 2 +b17 a19 = a18 * 2 +b18 a20 = a19 * 2 +b19 a21 = a20 * 2 +b20 a22 = a21 * 2 +b21 a23 = a22 * 2 +b22 a24 = a23 * 2 +b23 a25 = a24 * 2 +b24 a26 = a25 * 2 +b25 a27 = a26 * 2 +b26 a28 = a27 * 2 +b27 a29 = a28 * 2 +b28 a30 = a29 * 2 +b29 a31 = a30 * 2 +b30 a32 = a31 * 2 +b31 # fork scan point 2>24 a33 = a32 2 +b32 a34 = a33 * 2 +b33 a35 = a34 * 2 +b34 a36 = a35 * 2 +b35 a37 = a36 * 2 +b36 a38 = a37 * 2 +b37 a39 = a38 * 2 +b38 a40 = a39 * 2 +b39 a41 = a40 * 2 +b40 a42 = a41 * 2 +b41 a43 = a42 * 2 +b42 a44 = a43 * 2 +b43 a45 = a44 * 2 +b44 a46 = a45 * 2 +b45 a47 = a46 * 2 +b46 a48 = a47 * 2 +b47 a49 = a48 * 2 +b48 a50 = a49 * 2 +b49 a51 = a50 * 2 +b50 a52 = a51 * 2 +b51 a53 = a52 * 2 +b52 a54 = a53 * 2 +b53 a55 = a54 * 2 +b54 a56 = a55 * 2 +b55 ran = a56 myhex = "%064x" % ran myhex = myhex[:64] priv = myhex pub = privtopub(priv) pubkey1 = encode_pubkey(privtopub(priv), "bin_compressed") addr = pubtoaddr(pubkey1) if addr == "17aPYR1m6pVAacXg1PTDDU7XafvK1dxvhi": print ("found!!!",ran,addr,myhex) s1 = myhex s2 = addr f=open(u"C:/a.txt","a") f.write(s1) f.write(s2) f.close() break else: print ("searching...",ran,addr,myhex) YOU ARE VERY GREAT!!! I don't understand the language of the program because I'm not a programmer. Until now, I have not used any application on my computer other than Microsoft Excel 2003, because of my limitations This is very interesting.

Bitcoin / Bitcoin Discussion / Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

on: August 04, 2018, 11:56:54 AM

Quote from: ZafotheNinja on August 02, 2018, 12:39:34 PM Quote from: Amnuazka on July 31, 2018, 12:11:21 AM I found this : -snip- holy_ship , Andzhig, arulbero, or anyone.., can you analize the next code ( x ) for 56 ? -snip- Thank you. Thanks, you successfully made a wall of text. Please actually find a pattern instead of asking everyone else to. Even if the next number could be said for certain, it would not solve for the entire string, therefore the difficulty of finding the private key for the next puzzle would be only marginally reduced. Keep trying, but know that holy_ship, Andzhig, arulbero, or anyone else on this thread has probably already seen the binary version on the previous private keys, and have yet to find any pattern other than the first 0 at the beginning of each. Thank you

Bitcoin / Bitcoin Discussion / Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

on: July 31, 2018, 12:11:21 AM

I found this : 0 01 011 0001 00101 001101 0110100 01010010 000100010 0100111110 01110011100 001000110110 0000001110001 00111000010001 001000011110010 0010101110010000 00001000111011001 000101010001011000 0101011111100100100 01111110111001010111 000010110111110101100 0111010000000010101010 01110111000111000110101 011101011110001100111111 0011110110001011000011000 01111010001111110100010000 010000111001010010101000010 0110111110010011110110011100 01101101111011101001100100100 001001010100011100011010111110 0000110100011110000101100111001 01100010011110011111111101011101 000111100110110101010011110011111 0010100000001010100010000100100101 00110000110101111100110100001000000 010000011110110000100101001010100000 0111011110000100010101111101110011000 01101100111111001100000110001001010000 001011011111101011001011011101101001110 0100010011101110100000000000111001010101 01001100110100011111001110010100001110100 11010010011111000110110101110110110000111 11110100100101001101001101110111101110100 10010101000110010011100010001110000000101 01011000100000000000000101110100010111110 11010110010111000011110110001010100100111 00101001100000100100111110110011011100010 It begun from no 15 to no 55 15 16 0 0 1 1 1 1 1 1 0 0 1 1 1 0 0 55 0 1 1 1 1 1 0 0 0 0 0 0 1 1 0 0 1 0 0 1 0 0 1 1 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 1 0 1 0 1 0 1 0 holy_ship , Andzhig, arulbero, or anyone.., can you analize the next code ( x ) for 56 ? x 0x 01x 011x 0001x 00101x 001101x 0110100x 01010010x 000100010x 0100111110x 01110011100x 001000110110x 0000001110001x 00111000010001x 001000011110010x 0010101110010000x 00001000111011001x 000101010001011000x 0101011111100100100x 01111110111001010111x 000010110111110101100x 0111010000000010101010x 01110111000111000110101x 011101011110001100111111x 0011110110001011000011000x 01111010001111110100010000x 010000111001010010101000010x 0110111110010011110110011100x 01101101111011101001100100100x 001001010100011100011010111110x 0000110100011110000101100111001x 01100010011110011111111101011101x 000111100110110101010011110011111x 0010100000001010100010000100100101x 00110000110101111100110100001000000x 010000011110110000100101001010100000x 0111011110000100010101111101110011000x 01101100111111001100000110001001010000x 001011011111101011001011011101101001110x 0100010011101110100000000000111001010101x 01001100110100011111001110010100001110100x 11010010011111000110110101110110110000111x 11110100100101001101001101110111101110100x 10010101000110010011100010001110000000101x 01011000100000000000000101110100010111110x 11010110010111000011110110001010100100111x 00101001100000100100111110110011011100010x Thank you.

Bitcoin / Bitcoin Discussion / Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

on: July 06, 2018, 12:51:45 AM

Thank you. Yes, I mean to install this: https://github.com/ndv/vanitygen I found this "pattern" in my old spec computer, with a little formula: 1 0 0,00 3 0 1,33 7 0 2,43 8 0 3,00 21 0 4,24 49 0 5,35 76 1 6,16 224 2 7,43 467 4 8,45 514 4 9,00 1155 9 10,11 2683 21 11,24 5216 41 12,21 10544 82 13,22 26867 210 14,39 51510 402 15,36 95823 749 16,32 198669 1555 17,34 357535 2793 18,27 863317 6745 19,39 1811764 14154 20,42 3007503 23496 21,30 5598802 43741 22,25 14428676 112724 23,42 33185509 259262 24,49 54538862 426085 25,38 111949941 874609 26,40 227634408 1778394 27,41 400708894 3130538 28,33 1033162084 8071579 29,48 2102388551 16424911 30,49 3093472814 24167756 31,31 7137437912 55761234 32,40 14133072157 110414626 33,39 20112871792 157131811 34,15 42387769980 331154453 35,19 100251560595 783215317 36,31 146971536592 1148215130 37,06 323724968937 2529101320 38,15 1003651412950 7841026664 39,45 1458252205147 11392595353 40,25 2895374552463 22620113691 41,24 7409811047825 57889148811 42,41 15404761757071 120349701227 43,43 19996463086597 156222367864 44,12 51408670348612 401630237099 45,32 119666659114170 934895774329 46,41 191206974700443 1493804489847 47,26 409118905032525 3196241445567 48,31 611140496167764 4774535126311 49,08 2058769515153870 16084136837140 50,45 4216495639600700 32941372184381 51,47 6763683971478120 52841281027173 52,33 9974455244496710 77925431597631 53,10 30045390491869400 234729613217730 54,40 So the next code = between 55,00 and 55,49 I've never done a scan / search since I do not know what program I should install for that process. I found post puzzle 32 btc by accident 2 months ago, but I'm sure this is not a coincidence! 2 months I try to find the appropriate pattern, from dozens of patterns that I found there are only a few that do not deviate from no 1-55

Bitcoin / Bitcoin Discussion / Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

on: July 04, 2018, 11:08:07 PM

If I install vanitygen, what should computer hardware spec ? Please someone explain me step by step. Thank you.

Bitcoin / Bitcoin Discussion / Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

on: July 04, 2018, 11:27:16 AM

Quote from: Andzhig on June 20, 2018, 10:33:49 AM Well and how he from a transaction the public key received? sent a bit bitcoin to the address? What prevents him from doing the same thing with 56? I gave him an approximate search space. puzzle step difference 2^difference 44 15404761757071 120349701227 > 62460552416 8796093022208 8733632469792 45 19996463086597 156222367864 > 35872666637 17592186044416 17556313377779 46 51408670348612 401630237098 > 245407869234 35184372088832 34938964219598 47 119666659114170 934895774329 > 533265537231 70368744177664 69835478640433 48 191206974700443 1493804489847 > 558908715518 140737488355328 140178579639810 49 409118905032525 3196241445566 > 1702436955719 281474976710656 279772539754937 50 611140496167764 4774535126310 > 1578293680744 562949953421312 561371659740568 51 2058769515153876 16084136837139 > 11309601710829 1125899906842624 1114590305131795 52 4216495639600700 32941372184380 > 16857235347241 2251799813685248 2234942578338007 53 6763683971478124 52841281027172 > 19899908842792 4503599627370496 4483699718527704 54 9974455244496708 77925431597630 > 25084150570458 9007199254740992 8982115104170534 55 30045390491869460 234729613217730 > 156804181620100 18014398509481984 17857594327861884 > 36028797018963968 358************* This is what I mean formula "358"

Bitcoin / Bitcoin Discussion / Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

on: July 04, 2018, 06:47:50 AM

The key is from no 36054468590243300 to 71207575465730500 . And when simplified there are a few: 36054468590243300 36354922495162000 36655376400080700 36955830304999400 37256284209918100 37556738114836800 37857192019755400 38157645924674100 38458099829592800 38758553734511500 39059007639430200 39359461544348900 39659915449267600 39960369354186300 40260823259105000 40561277164023700 40861731068942400 41162184973861100 41462638878779800 41763092783698500 42063546688617200 42364000593535800 42664454498454500 42964908403373200 43265362308291900 43565816213210600 43866270118129300 44166724023048000 44467177927966700 44767631832885400 45068085737804100 45368539642722800 45668993547641500 45969447452560200 46269901357478900 46570355262397600 46870809167316300 47171263072235000 47471716977153700 47772170882072400 48072624786991000 48373078691909700 48673532596828400 48973986501747100 49274440406665800 49574894311584500 49875348216503200 50175802121421900 50476256026340600 50776709931259300 51077163836178000 51377617741096700 51678071646015400 51978525550934100 52278979455852800 52579433360771400 52879887265690100 53180341170608800 53480795075527500 53781248980446200 54081702885364900 54382156790283600 54682610695202300 54983064600121000 55283518505039700 55583972409958400 55884426314877100 56184880219795800 56485334124714500 56785788029633200 57086241934551900 57386695839470600 57687149744389200 57987603649307900 58288057554226600 58588511459145300 58888965364064000 59189419268982700 59489873173901400 59790327078820100 60090780983738800 60391234888657500 60691688793576200 60992142698494900 61292596603413600 61593050508332300 61893504413251000 62193958318169700 62494412223088400 62794866128007000 63095320032925700 63395773937844400 63696227842763100 63996681747681800 64297135652600500 64597589557519200 64898043462437900 65198497367356600 65498951272275300 65799405177194000 66099859082112700 66400312987031400 66700766891950100 67001220796868800 67301674701787500 67602128606706200 67902582511624800 68203036416543500 68503490321462200 68803944226380900 69104398131299600 69404852036218300 69705305941137000 70005759846055700 70306213750974400 70606667655893100 70907121560811800 71207575465730500 BOLD= when simplified by 358 formula (although I do not like this formula because from the beginning did not form a pattern) I have confirmed this, and can show from wallet 1 to 55

Bitcoin / Bitcoin Discussion / Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

on: July 04, 2018, 12:18:52 AM

I am newbi in bitcins, but i pay attention to journey puzzle 32 (112) btc. I found a little pattern, but i dont know what i do to process it. Can someone discuss with me? pm

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