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Here if you would: 1AWHtDujWif6A2P23heXDZ2KJkSGoADMpZ
Thank you
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Hmmmm, I wasn't able to replicate this result. What version of stegbreak are you using, I could only use 4.0, couldn't get 6.0 to build for the life of me. Apparently stegdetect is known for false positives, telling you there's a jphide message even if there is not, if you turn sensitivity high enough.
I'm using stegbreak 0.4. I also think its a false positive caused by upping the sensitivity to around 1.4 The only thing that confused me was, that stegbreak didn't output any file on that.. i'd have expected some gibberish file to come out of a false positive |
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I used stegdetect and it did think there was a jphide message hiding in there, with the sensitivity turned up high enough. However, I've tried over 300,000 passwords with stegbreak, including every odd word or phrase mentioned in any of the threads here. Nothing so far. I'd be surprised if this was a brute force cracking problem, anyhow.
Here are my results from that: OSpEZtA.jpg : jsteg(Ca/Q) Processed 1 files, found 1 embeddings. Time: 92459 seconds: Cracks: 450945859 so stegdetect claims that Ca/Q was a valid password, but no file was output |
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If you rotate the picture, some of the white squares look like flowers at the end of the vines.
The vine + flower look like Ipomoea Alba, also known as Moonflower
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Read through this thread to find out how to get into the Let's Talk Bitcoin secret forum - there's more information there.
Has access for new players been turned off? The token page says "token already sent", but the token is not coming through edit+: of course it came just after posting this  |
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I just got a QR code to recognize from the pigeon part of the picture. I can get it to recognize a QR code multiple times but the identified data is different each time. Could be that there is something there, but its not fully cleaned out yet, or its just a fluke. here's what I did: import sys, re, binascii, string, Image
img = Image.open('OSpEZtA.jpg')
width, _ = img.size
for i, px in enumerate(img.getdata()):
if px[0] % 2 != 0:
y = i / width
x = i % width
img.putpixel((x, y), (0, 0, 0, 0))
if px[1] % 2 != 0:
y = i / width
x = i % width
img.putpixel((x, y), (0, 0, 0, 0))
if px[2] % 2 != 0:
y = i / width
x = i % width
img.putpixel((x, y), (0, 0, 0, 0))
img.save('pic.png')
I then opened the picture in Irfan view, decreased the color depth to 2, and tried my phones QRDroid on the different parts of the picture the first time the value was: : 18795394 the second time the value was: 15034831 third time: 18270434 the image is here: https://i.imgur.com/eGli3ta.png |
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I think I have either gone down the wrong path, or the path drastically changes from here, and I'm not sure how to continue. here is what I did with the flames: http://riddlehelper.blogspot.fi/2011/04/baconian-cipher.htmlsecond version, that uses a unique combination for each letter top top topbottom right right right left
yryyr rryrr ryyyr ryr|gg gbgbg bggbg bbgbb g|bggg bbgbg gxxbg bgbbb bgggg bbbgb b|yyyr yryry yxxry rryrr ryyry rryyy y|yrrr yryyy yrr|bg gbgbb bbbbg| gbbbb bgbbg gbggg gbgbb gbgg|y yyyry rrryrrryyyrrrryyyy
babba aabaa abbba aba|bb babab abbab aabaa b|abbb aabab baaab abaaa abbbb aaaba a|bbba babab baaab aabaa abbab aabbb b|baaa babbb baa|ab babaa aaaab| baaaa abaab babbb babaa babb
w e o l v n e | x f r i p c |o v r e n h | y x r| u b | q j x u
example: we love coinhub xfr very xpr
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I think I have around half of the flames decoded now, at least its giving me a bitcoin related phrase.
If I am on the correct trail, it is using bacon encoding for the flames
ps, does anyone love coinhub?
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I might be grasping at straws here, but if i use RGBY as the bit encoding scheme on the outer flames, starting from top and going clock wize (ignoring flames that don't have blue or green inside them) i get the following when converted from bin to hex: 5C 53 CA C3 CC A5 33 CA 3C 3C CA 5A 33 33 AC 55 5A AA 33 3A A3 3A C3 CC 53 C5 A0
this in ANSI coding is: http://imgur.com/0Zl1BlvAnd when your brain is looking for patterns at 3am you could convince yourself that it reads something along the lines of, "see its easy, use <something>" |
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