solved: how to send optional arguments in PHP with jsonRPC

[winnetou]

Hello!

This is the code to get the balance of a bitcoin account called user1

Code:

  echo $bitcoin->getreceivedbylabel("user1");

I would like to add the optional parameter minconf=2 but I can not figure out how to do this.

Code:

  echo $bitcoin->getreceivedbylabel("user1 minconf=2");

.. is not working

Hope somebody can help me.

Thanks

[BCEmporium]

The proper way is:

  echo $bitcoin->getreceivedbylabel("user1",2);

[winnetou]

The proper way is:

  echo $bitcoin->getreceivedbylabel("user1",2);

thank you!

[Clark]

I am working in php, and I would like to skip an optional parameter.

Say I want to get 5 transactions, but I don't care about which account was involved.

I am using php with the jsonRPCClient.php module.

All of the following DO NOT WORK:

Code:

listtransactions(array(null, 5))
listtransactions(null, 5)
listtransactions(array('count'=>5))
listtransactions(0,5)
listtransactions(5)
listtransactions(false,5)

Any help in this area would be awesome.

[Clark]

I think this will work to select the last 25 transactions, regardless of account:

Code:

listtransactions('*',25)

[winnetou]

I think this will work to select the last 25 transactions, regardless of account:

Code:

listtransactions('*',25)

perfect! thank you very much

[terrytibbs]

The proper way is:

  echo $bitcoin->getreceivedbylabel("user1",2);

Why oh why would you use double-quotes there?!?!

[Remember remember the 5th of November]

The proper way is:

  echo $bitcoin->getreceivedbylabel("user1",2);

Why oh why would you use double-quotes there?!?!

Yup, we are not evaluating a variable. But, at least the wrote the integer without making it into string