I'm BIP38 curious, please help me out!

[Decoded]

It took ~20 hours on three n1-highcpu-16 machines on Google Compute. Each one did ~50 passwords per second, 150 total.
It cost around $38 overall.

At this rate it would take up to 4 years to crack the Third password. At $38 for 20 hours it's clearly not worth it.

Here is a small password hint: If you divide the number of UPPERCASE letters by the number of lowercase letters you get an integer.

So that means:
0 UP 6 low: 0/6=0: integer
1 UP 5 low: 1/5: nope
2 UP 4 low: 2/4: nope
3 UP 3 low: 3/3=1: integer
4 UP 2 low: 4/2=2: integer
5 UP 1 low: 5/1=5: integer

Hints is not enough to find the password.It would very hard to find the password.I divided the number of UPPERCASE letters by the number of lowercase letters I got some numbers.I think password will be  UPPERCASE letters and lowercase letters with integers.Well I will try.

You honestly have no idea what this thread is about, and how the puzzle works. Youre just posting for money.

OP's saying that the amount of uppercase letters will be an integer * lowercase letter. That rules out 2 of 6 possibilities. It's a great help.

Here's a newbie question from yours truly -
Since ASICs are built for cryptography, would it be faster to crack the password with an ASIC (Because I can expect that the main thing that's taking this so long is the BIP38 encryption standard). Or are ASICs only built for hashing?

P.S. I also have a sweet $400 AWS credit. Should I use it on this? Don't know how to crack :-/

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[nealvanessa990]

It took ~20 hours on three n1-highcpu-16 machines on Google Compute. Each one did ~50 passwords per second, 150 total.
It cost around $38 overall.

At this rate it would take up to 4 years to crack the Third password. At $38 for 20 hours it's clearly not worth it.

Here is a small password hint: If you divide the number of UPPERCASE letters by the number of lowercase letters you get an integer.

So that means:
0 UP 6 low: 0/6=0: integer
1 UP 5 low: 1/5: nope
2 UP 4 low: 2/4: nope
3 UP 3 low: 3/3=1: integer
4 UP 2 low: 4/2=2: integer
5 UP 1 low: 5/1=5: integer

Hints is not enough to find the password.It would very hard to find the password.I divided the number of UPPERCASE letters by the number of lowercase letters I got some numbers.I think password will be  UPPERCASE letters and lowercase letters with integers.Well I will try.

You honestly have no idea what this thread is about, and how the puzzle works. Youre just posting for money.

OP's saying that the amount of uppercase letters will be an integer * lowercase letter. That rules out 2 of 6 possibilities. It's a great help.

Here's a newbie question from yours truly -
Since ASICs are built for cryptography, would it be faster to crack the password with an ASIC (Because I can expect that the main thing that's taking this so long is the BIP38 encryption standard). Or are ASICs only built for hashing?

P.S. I also have a sweet $400 AWS credit. Should I use it on this? Don't know how to crack :-/

Yes you are right he might be misunderstand OP.He really give a nice hint.here should be possibility of password:
5 Uppercase  and 1 lowercase,
4 Uppercase  and 2 lowercase,
3 Uppercase  and 3 lowercase,
0 Uppercase  and 6 lowercase
Interesting but Dont have idea how crack down.

[BilalHIMITE]

...
The fastest cracker we have, Dirbaio, can do 20 tries/second. He will take about about 31.34 years to find! No one will commit this much energy and time to crack the wallet with only 0.1BTC, and therefore the puzzle will not be solved... unless minimalB is going to provide some hints.

You mean : Within 31.34 years the password will be cracked.

For example if the password is : aaaaab             2 tries to solve.
                                             kjxusl              12,640,320 tries to solve.
                                             ZZZZZZ           19,770,609,664 tries to solve.

It works like this if you use normal Brute-force dictionaries.

But, if you use Rainbow Tables, it may take less (If they work with AES-256 because I can't find one yet).

Note: a 6-letter word (a-Z) dictionary will be : ( 52 ˆ 6 )  ×  8  =  158,164,877,312 Bytes

        52 : the number of possible characters.
        6 : word length
        8 : the size each word will take in bytes, 6 bytes for the 6 letters and 2 bytes for CR (Carriage Return) and LF (Line Feed)

About 147.31GB in Table.

Also, you can split your table, or generate a part of it, then us it to brute-force, then generate another part...

And also, you can use multiple computers with different tables to brute-force.
So, if a computer (probably a VPS) is solving 10 Passwords/Sec. You can use 10 computers with 100 Passwords / Sec.
It will only take : 19,770,609,644 / 100 Passwords / 60 Secs / 60 Mins / 24 Hours / 365.24 Days =
6 Years 3 Months 5 Days 12 Hours 16 Minutes 24 Seconds 54,864.36 microseconds

Not that much time, right?

[minimalB]

Not that much time, right?

Nope, just 7 more months to go : )

[Timelord2067]

I take it people are using an actual program for this project?

I tried to put six random digits into https://www.bitaddress.org/ and got the message:

The passphrase you entered is too short.

Warning: Choosing a strong passphrase is important to avoid brute force attempts to guess your passphrase and steal your bitcoins.

Was also wondering if its just six upper and or lower case letters?  Are there any digits and or characters?  And any non standard symbols? eg umlauts or similar?  Cyrillic/Arabic/Asian ?

[minimalB]

The passphrase you entered is too short.

Warning: Choosing a strong passphrase is important to avoid brute force attempts to guess your passphrase and steal your bitcoins.

That would be true for brainwallet. The challenge is not brainwallet based, it is BIP38 encrypted paper wallet. 6-character brainwallet would be brute forced in few seconds.

Was also wondering if its just six upper and or lower case letters?  Are there any digits and or characters?  And any non standard symbols? eg umlauts or similar?  Cyrillic/Arabic/Asian ?

Please read the first post for all the password related details.

[raymond541]

I take it people are using an actual program for this project?

I tried to put six random digits into https://www.bitaddress.org/ and got the message:

The passphrase you entered is too short.

Warning: Choosing a strong passphrase is important to avoid brute force attempts to guess your passphrase and steal your bitcoins.

Was also wondering if its just six upper and or lower case letters?  Are there any digits and or characters?  And any non standard symbols? eg umlauts or similar?  Cyrillic/Arabic/Asian ?

He give a hint divide the number of UPPERCASE letters by the number of lowercase letters you get an integer.so you can try with integer.someone mentioned how many integer have this password create a table of password with the hint.I wish you could find the password.I dont have much knowledge how to crack.

Here is a small password hint: If you divide the number of UPPERCASE letters by the number of lowercase letters you get an integer.

[ArcCsch]

With the current difficulty and rewards, how much entropy is necessary to make cracking a wallet for 1BTC as rewarding as mining LiteCoin, Etherium or DOGE (they all use scrypt, or do they?)?
 On a slightly unrelated topic, how does scrypt differ from scrypt-jane and how do they differ from my scheme in:
https://bitcointalk.org/index.php?topic=1638955.msg16988889#msg16988889

The password should have more than that, but this is a good benchmark.

[minimalB]

After 2 years I've decided to stop the experiment.
The password to unlock 3rd wallet with 1BTC prize was "zLwMiR".

I'd like to thank everyone for  participating in this challenge.
I'd also like to thank BIP38 developers for creating a truly great PW system!

[7788bitcoin]

Thanks for the challenge! I did some guessing and the left hand side characters "qwaszx" were used as the first character... Unfortunately I started with CAP for these and have not even completed... This prove that even with hints, it might still take too long (too much cost) to crack a BIP38 encrypted address.

[mattermaster]

Hi, can anyone help me to find private keys using correct password?  Actually i tried these passwords on  https://brainwalletx.github.io  but it does not display correct btc address. For example: if i input grAce for secound wallet , the output btc address is shown different. Why?  
I checked in both compressed and uncompressed, output is not matching these btc addresses.


I have many unused passwords with some balances but i face similar issue with them!

Can anyone help where i have to put these passwords in order to see correct wallet and private keys?

[minimalB]

Hi, can anyone help me to find private keys using correct password?  Actually i tried these passwords on https://brainwalletx.github.io  but it does not display correct btc address.

"Wallet Details" tab at https://bitaddress.org should do the trick : )