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Author Topic: Solve these 4 microbiology problems and get 0.2 coins  (Read 808 times)
tarzan2 (OP)
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May 12, 2015, 12:07:40 AM
Last edit: May 26, 2015, 12:16:50 AM by tarzan2
 #1

Like the title says.. solve 1 get 0.04 and 0.16 bounty will remain on the last 3.. solve 2 and get 0.08 and 0.12 bounty will remain... same idea for the third such that 0.08 remains on the final problem... solve the last one and get 0.08 btc for the final problem.. if you can solve all four and you obviously get the full 0.2 btc

good luck!

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polynesia
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May 12, 2015, 02:24:28 AM
 #2

There are 4 problems in all (page two has two problems).
So which are the three you want solved?
                   
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May 12, 2015, 03:28:08 AM
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Sorry your right again polynesia I hadn't even looked at it.. This is for a friend.. Just edited it to make more sense

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May 12, 2015, 03:47:19 AM
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this would be alot easier if we could copy n paste. since you put screenshots its alot of typing and switching back n forth between pages
tarzan2 (OP)
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May 12, 2015, 03:57:51 AM
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this would be alot easier if we could copy n paste. since you put screenshots its alot of typing and switching back n forth between pages


Here's PDF https://docs.google.com/file/d/0B6igYxGPIADheUo5NE5MekdaZ2E4cUVGRG9yRDFYVmZ5NDRj/edit?usp=docslist_api


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May 12, 2015, 06:29:43 AM
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HERE IS PART 1-

(a) - The yield coefficient stoichiometrically links substrate removal and

(ii) Biomass Synthesis
-----

(b) - During fermentation, electrons are transferred from * to *

(iv) Methane, Carbon Dioxide
-----

(c) - use of nitrate as the nitrogen source for cell synthesis is termed *a* reduction, whereas use of nitrate as the terminal electron acceptor is termed

*b* reduction.

*a* - assimilatory nitrate
*b* - Denitrification or Nitrate -------------- (https://www.boundless.com/microbiology/textbooks/boundless-microbiology-textbook/microbial-

metabolism-5/anaerobic-respiration-49/electron-acceptors-and-donors-in-anaerobic-respiration-313-8023/)
---

(d) - ** -metabolism of a substrate by an organism does not result in net energy production.......

** - anabolic-
------

(e) -  The *a* pathway is principally responsible for oxidative phosphorylation based energy generation in aerobic respiration, whereas the *b*

pathway is one of several routes for glycosis.

*a* - tricarboxylic acid (TCA)

*b* - embden meyerhof parnas (EMP)

------------------
PARTS STILL TO COME......

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May 12, 2015, 06:34:16 AM
 #7

PART 3


tarzan2 (OP)
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May 12, 2015, 06:37:22 AM
 #8

looking good toodamntired.. unfortunately, i think my friend is not awake to confirm right now.. since i know nothing about this stuff, would it be alright with you if we wait for him to look this over?

i can assure you i have no intention of not rewarding good work.. you can check my trust if you have doubts

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May 12, 2015, 07:02:27 AM
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Yeah, I am in no hurry. Still working on the composite chemical reaction and the chemical oxygen demand: biochemical oxygen demand stuff anyways... kind of vague when it asks for thee composite with no other info. There are several different reagents that can be used to oxidize amino acids... trying to give one composite answer is difficult without knowing the exact parameters of the testing.... Also, the image that shows the labels for the citric acid cycle... eh..... well, i can argue that every choice i made is correct, but 2 of them could go either way.....

We will see. Your friend knows what his professors are looking for exactly....

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May 12, 2015, 08:09:22 AM
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If this is not what the rofessor is looking for, I will scream.... Not exactly a traditional way to express a Composite Chemical Reaction, but it does cover all steps using a specific reagent:

PDF FILE:
https://docs.google.com/file/d/0B8JOtGf3V3grUUhuTTBDSVFOSjA/edit


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May 12, 2015, 08:13:37 AM
 #11

Okay, I am done... first question- completed, 2nd; i did half of it..... 3rd completed; 4th? good luck.... its 4am here... you wonder why my name is toodamntired? lol.....

Send me a PM and let me know if i win the prize....  Grin

tarzan2 (OP)
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May 12, 2015, 12:21:47 PM
 #12

Okay, I am done... first question- completed, 2nd; i did half of it..... 3rd completed; 4th? good luck.... its 4am here... you wonder why my name is toodamntired? lol.....

Send me a PM and let me know if i win the prize....  Grin

you sure did... I'll be sending you 0.1 btc for your work so far, and I'm going to raise bounty on the remaining 1 and a half problems to 0.2 total for just those remaining.. good luck people of the internet

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May 13, 2015, 11:30:01 PM
 #13

Here is #2, Part B:

"For an fS value of 0.4, compute the ratio of BOD:COD’ for Proline."

---------
Method:

Stoichiometric reaction with oxygen to yield CO2 (assume all C goes to CO2), H2O (assume all H goes to H2O), and NH3 (assume all N goes to NH3), using the following formula: COD = (C/FW)(RMO)(32)COD = (C/FW)(RMO)(32)

Proline C5H9NO2

COD is calculated assuming the following:

C = Concentration of oxidizable compound in the sample,
FW = Formula weight of the oxidizable compound in the sample,
RMO = Ratio of the # of moles of oxygen to # of moles of oxidizable compound in their reaction to CO2, water, and ammonia

AND Where

C= 0.4 ppm (Given)
FW= 115.13 (Reference from Wikipedia)
RMO=  17 (Calculated by dividing all moles by the lowest mole; Nitrogen as follows;)
C5H9NO2   5:1 + 9:1 + 1:1 + 2:1 + 17:1= 17

COD = (C/FW)(RMO)(32)
COD = (0.4/115)(17)(32)
COD = (.0035)(17)(32)
COD = (0.0595)(32)
COD = 1.904 mg/L

BOD is calculated assuming the following

All oxygen available would be consumed, so the total available oxygen is from 2 molecules. At 20 degrees Celsius, that is 7.6mg/L

BOD =  7.6

Using the above figures,
 
BOD:COD = 3.99 mg/L

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