37^4, of getting 21 four times in a row=1,874,161 odds.
Yep. Of course the sequence 2(Black), 25(Red), 21(Red), 34(Red) also that 1:1,874,161 odds, so you actually had 2 extremely rare sequences occur consecutively. Choose ANY sequence of 4 numbers between 0 and 36 and there is a 1 in 1,874,161 chance that the sequence will occur. This means that EVERY 4 number sequence you see is just as rare as the particular sequence of 21, 21, 21, 21 that you are focusing on.
Just occurred about 60 secs ago. I was like to myself,
if 4 numbers same came up I would post it on bitcointalk.org
and though I would be playing millions of times before this occurred.
I was joking about it, and a min later it happened holy shit
A sequence of 4 identical numbers isn't quite as rare since there are 37 different ways for it to happen. If I've got my math right, the odds of seeing a sequence of 4 identical numbers is 1 in 50,653. If you had already seen two or three of those 21's when you thought to yourself that you'd post on bitcointalk if it reached four, then the odds become much better that you'd get the remaining one or two 21's needed (1 in 36, or 1 in 1,296).
If I tossed 1 bitcoin on 21 4 times in a row. That be, 1>36>1296>46,656 Bitcoins.
I would have over $400,000. Though I would of long bankrupted the site.
Damn I should of tossed everything on 21 red 4 times xD
Yep, just like you'd have gotten the same results if you had tossed one bitcoin on 2, and then moved of it to 25, and from there to 21, finally moving the total to 34. And if you'd have done that you'd have gotten your 46,656 coins 4 spins sooner.
