Andzhig
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July 18, 2018, 08:50:52 AM Last edit: July 18, 2018, 04:35:56 PM by Andzhig |
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fast ... last 55 as I understand the author of the puzzle specially flashed the public key (threw some bitcoin and deducing). to see how it works baby step gigant step.
they all lie side by side (in its macrocosm)), The scanner would be with a random (127,7-16 signs randomisation) and a step up-down for a couple million.
56 49 42 127,************************* 127 127,27325883491766944644041359425 127,34166804622509516775608062744 63,583036446150909604124734642028 63,5 63,660348182749885381781496107578 63,668431836413219571113586425781 31,861576626618332619411688710898 31,75 31,787429311634468831471167504787 31,771796089393319562077522277832 15,90613502904471082688431238239 15,875 15,908679856821891007712110877037 15,926393464003922417759895324707 7,941484368221046585833988729064 7,9375 7,9644791460323176579549908638 7,966582541557727381587028503418
35 127,414638392627239227294921875 127 63,588673464953899383544921875 31,7922732196748256683349609375 15,90996809303760528564453125 7,938812442123889923095703125
28 127,151996135711669921875 127 63,58295440673828125 31,7968273162841796875 15,876374721527099609375 7,9462490081787109375
21 127,1361083984375 127 63,58837890625 31,82952880859375 15,9052734375 7,954345703125
14 127,359375 127
7 127,40625
you can try to search 7,9 she meets frequently for the next step 576460752303423488 - (((((((((7,94910898 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128) - 571957152676052992) * 128) next step 576460752303423488 * 128 = 73786976294838206464 - 576460752303423488 = 73210515542534782976 formula 73786976294838206464 - ((((((((((7,94910898 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128) * 128) - 73210515542534782976) * 128)
if you look at the beginning
0 1 2 1 3 4 2 7 8 3 8 16 4 21 32 5 49 64 6 76 128 7 224 256 8 467 512 9 514 1024 < 1018,15625 10 1155 2048 11 2683 4096 12 5216 8192 13 10544 16384 14 26867 32768 15 51510 65536 16 95823 131072 < 130324 < 748 17 198669 262144 18 357535 524288 19 863317 1048576 20 1811764 2097152 21 3007503 4194304 22 5598802 8388608 23 14428676 16777216 < 16664492 112724 (16777216-112724=16664492/128/128/128) 24 33185509 33554432 25 54538862 67108864 26 111949941 134217728 27 227634408 268435456
You can try to print the number first example take the second step 7,954345703125 * 128 = < 1018,15625 * 128 = < 130324 ; 131072-130324= < 748 a prime number to find 131072-748=130324/128/128 = 7,954345703125 formula 131072 - ((((((((7,954345703125 * 128) * 128) - 130048) * 128) = 95744 slightly askew because 95823/128=748,6171875 ; 131072 - 748,6171875 = 130323,3828125/128/128= 7,954308032989501953125 with this value 131072 - ((((((((7,954308032989501953125 * 128) * 128) - 130048) * 128) = 95823 here you can try 749
take the previous step 7,9462490081787109375 * 128 = 1017,119873046875 * 128 = < 130191,34375 on the second multiplication, the tail does not disappear * 128 = < 16664492 (etc with each puzzle...)
you can take a number from the first step or from the second (any) and choose a number for the formula, for example last thing 7,941484368221046585833988729064*128*128=130113,27988893362726230407133698 on the idea should be enough for the first 8 characters (meaning scanning). 131072 - 130113 = 959 and let's go 959,2 959,3 959,4.. 959,23 959,28... 959,50 959,59.. or 959,random... 960...
or all can be much simpler to take the number and multiply by 128, 749*128=95872 (95823), (880,656494140625) 881 * 128* 128 = 14434304 (14428676)... (958,72011106637273769592866301537) 959*128*128*128*128*128*128=4217726604148736 (4216495639600700)... what number to multiply 7 times to get 56.
or the program that the whole numbers searched for and multiplied by the comparator compared with the key.
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princebridge7
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July 19, 2018, 03:23:18 PM |
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I am incompetent to solve a problem like this, I know its trading at Bittrex and Binance.
but hopefully at the end ny code like this can be solved and I will congratulate the person who broke the code. yuhuuu
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BurtW
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July 19, 2018, 07:09:42 PM |
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Maybe if we learn a bit more from how the numbers were generated it could greatly optimize the program. We know exactly how the numbers were generated because the author of the puzzle came into this thread and told us. Read back and find it if you are interested.
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Our family was terrorized by Homeland Security. Read all about it here: http://www.jmwagner.com/ and http://www.burtw.com/ Any donations to help us recover from the $300,000 in legal fees and forced donations to the Federal Asset Forfeiture slush fund are greatly appreciated!
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itod
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^ Will code for Bitcoins
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July 20, 2018, 09:36:05 AM |
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Maybe if we learn a bit more from how the numbers were generated it could greatly optimize the program. We know exactly how the numbers were generated because the author of the puzzle came into this thread and told us. Read back and find it if you are interested. Where is the fun in knowing something? Isn't it much more interesting to throw around half-baked theories and draw maps where X marks the hidden treasure chest?
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dalvitka
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July 20, 2018, 10:09:35 AM |
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After considering a bunch of pvks found by the bots I noticed that many addresses were on the same transaction, after a tight check I saw what kind of pattern the sequence was. One thing I noticed perhaps this transaction was made by the Bitcoin developers. Some GPU bots would be best to violate it, as shorena has said. Is anyone out there?
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BurtW
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July 20, 2018, 12:08:55 PM |
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After considering a bunch of pvks found by the bots I noticed that many addresses were on the same transaction, after a tight check I saw what kind of pattern the sequence was. One thing I noticed perhaps this transaction was made by the Bitcoin developers. Some GPU bots would be best to violate it, as shorena has said. Is anyone out there?
Yes, ALL the Bitcoins in the puzzle transaction were placed there in a single transaction. The author of the puzzle transaction came into this thread and explained the whole thing. Yes, there is a well defined pattern to the puzzle transaction. All the private keys are random but each key uses an increasing bit length. Key one has a random one bit key, key two has a random two bit key, key three has a random three bit key, etc. All of this work trying to find out a pattern to the random private keys is a complete and total waste of time. "Fun" maybe, if you like to waste your time trying to find a pattern in random data. If you bothered to read the thread you would know all this and would not have to guess.
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Our family was terrorized by Homeland Security. Read all about it here: http://www.jmwagner.com/ and http://www.burtw.com/ Any donations to help us recover from the $300,000 in legal fees and forced donations to the Federal Asset Forfeiture slush fund are greatly appreciated!
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Andzhig
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July 20, 2018, 02:36:45 PM Last edit: July 23, 2018, 10:36:01 AM by Andzhig |
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Addresses are all compressed in the puzzle? if you like to waste your time trying to find a pattern in random data And you've been guessing for a few years now already all the methods have been tried all sorts, random programs generators... and without the slightest hint of luck. began to study "python" in pieces from Inet assembled a generator with a selectable range of randomization (until 1 step) and a hex output and a compressed key, It remains to teach how to compare the address lines generated with the puzzle addresses next or in the file and stop work. *** in the general gemoro there full with jumps, who understands to supplement the code, but for now you can duplicate and run the sites ... from bitcoin import * import random
while True: ran = random.randrange(36028797018963968,72057594037927936) myhex = "%064x" % ran myhex = myhex[:64] priv = myhex pub = privtopub(priv) pubkey1 = encode_pubkey(privtopub(priv), "bin_compressed") addr = pubtoaddr(pubkey1) n = addr if n.strip() == "17aPYR1m6pVAacXg1PTDDU7XafvK1dxvhi": print ("found!!!",addr,myhex) s1 = myhex s2 = addr
f=open(u"C:/a.txt","a") f.write(s1) f.write(s2) f.close() break else: print ("searching...",addr,myhex)
the heat went off http://meson.ad-l.ink/7Try5DcVV/image.png I have 20 scanners without problems for the PC to run at the same time, how many on amd ryzen interesting... from bitcoin import * import random
a = int (input("start scan range:")) b = int (input("end scan range:")) c = input ("address:")
while True: ran = random.randrange(a,b) myhex = "%064x" % ran myhex = myhex[:64] priv = myhex pub = privtopub(priv) pubkey1 = encode_pubkey(privtopub(priv), "bin_compressed") addr = pubtoaddr(pubkey1) n = addr if n.strip() == c: print ("found!!!",addr,myhex) s1 = myhex s2 = addr
f=open(u"C:/a.txt","a") f.write(s1) f.write(s2) f.close() break else: print ("searching...",addr,myhex)
python exists for android... need to somehow gpu to steal, numba... *** Key one has a random one bit key, key two has a random two bit key, key three has a random three bit key, etc. deterministic random? most likely generated by time in windows.
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BurtW
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July 23, 2018, 03:42:35 PM |
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... some code ...
The LBC project is currently running at 346.02 Mkeys/s and recently had a peak of about 521 Mkeys/s How many keys per second does your method check?
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Our family was terrorized by Homeland Security. Read all about it here: http://www.jmwagner.com/ and http://www.burtw.com/ Any donations to help us recover from the $300,000 in legal fees and forced donations to the Federal Asset Forfeiture slush fund are greatly appreciated!
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Andzhig
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July 23, 2018, 06:45:16 PM |
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Yes it is clear that compared to LBC this is a louse (but if desired and a louse a lion can gnaw) this is so for luck, suddenly there is a magic step for a random house. There are many options you can think of, and step through a number, sort only even, odd, take each 128,256,512 ... multiply them ... floating scan area, some magical jumps, etc. from bitcoin import * import random import math
while True: f = random.random() + 15.1 g = f b = 1152921504606846976 - ((((((((((g * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128) - 1143914305352105984) * 128) c = math.trunc(b) ran = c myhex = "%064x" % ran myhex = myhex[:64] priv = myhex pub = privtopub(priv) pubkey1 = encode_pubkey(privtopub(priv), "bin_compressed") addr = pubtoaddr(pubkey1) n = addr if n.strip() == "1HAX2n9Uruu9YDt4cqRgYcvtGvZj1rbUyt": print ("found!!!",addr,myhex) s1 = myhex s2 = addr
f=open(u"C:/a.txt","a") f.write(s1) f.write(s2) f.close() break else: print ("searching...",f,addr,myhex)
formula 1152921504606846976 - ((((((((((15.9 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128) - 1143914305352105984) * 128) after 15.9xxxxxxxxxxxxxxxxxxxxxxxxxxx a random number of 29, 30 numbers can be sausage immediately at all after 7 steps of the puzzle. 1152921504606846976 - ((((((((((15,9075849271 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128) - 1143914305352105984) * 128) 147573952589676412928 - (((((((((((15,9041635330 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128) - 146421031085069565952) * 128) 18889465931478580854784 - ((((((((((((15,9058575788 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128) - 18741891978888904441856) * 128) 2417851639229258349412352 - (((((((((((((15,9058575788 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128) - 2398962173297779768557568) * 128) 309485009821345068724781056 - ((((((((((((((15,9081997978 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128)* 128) - 307067158182115810375368704) * 128) 39614081257132168796771975168 - (((((((((((((((15,9081997978 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128) - 39304596247310823728047194112) * 128) 5070602400912917605986812821504 - ((((((((((((((((15,9095945490 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128) - 5030988319655785437190040846336) * 128) 649037107316853453566312041152512 - (((((((((((((((((15,9095945490 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128) - 643966504915940535960325228331008) * 128) 83076749736557242056487941267521536 - ((((((((((((((((((15,90 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128) - 82427712629240388602921629226369024) * 128) 10633823966279326983230456482242756608 - (((((((((((((((((((15,90 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128) - 10550747216542769741173968540975235072) * 128) 1361129467683753853853498429727072845824 - ((((((((((((((((((((15,90 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128) - 1350495643717474526870267973244830089216) * 128) 174224571863520493293247799005065324265472 - (((((((((((((((((((((15,90 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128) - 172863442395836739439394300575338251419648) * 128) 22300745198530623141535718272648361505980416 - ((((((((((((((((((((((15,90 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128) - 22126520626667102648242470473643296181714944) * 128) 2854495385411919762116571938898990272765493248 - (((((((((((((((((((((((15,90 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128) - 2832194640213389138975036220626341911259512832) * 128) 365375409332725729550921208179070754913983135744 - ((((((((((((((((((((((((15,90 * 128) * 128) * 128) * 128)* 128) * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128) - 362520913947313809788804636240171764641217642496) * 128)
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lolobit2
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July 24, 2018, 01:33:47 AM |
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Andzhig Пpивeтcтвyю ,интepecнa тeмa взлoмa бтк ,ecть нapaбoтки нaпиши пoчтy в личкy -oбcyдим
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holy_ship
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July 25, 2018, 03:23:10 AM |
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Python is not hipsterish enough! True mama's cryptokiddies choose PHP parser of directory.io And adding right magic constant to skip "unnecessary" pages is vital!
So, first you should look at you mom's Crystal Ball to find the magic number!
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holy_ship
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July 25, 2018, 03:26:05 AM |
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The LBC project[/url] is currently running at 346.02 Mkeys/s
Actually LBC is still checking the 2^55 range. So even pasting numbers in http://brain.evilbs.com/ by hand is faster than LBC
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Andzhig
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July 25, 2018, 02:20:01 PM |
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Andzhig Пpивeтcтвyю ,интepecнa тeмa взлoмa бтк ,ecть нapaбoтки нaпиши пoчтy в личкy -oбcyдим Thank you, from me a cracker like Harry Dunn plumber in the movie "Dumb & Dumber" when he came to the house of a woman. Specially for you there is an idea scan through a phrase ip addresses (sha256) but there is also not a small figure 4294967296. The LBC project[/url] is currently running at 346.02 Mkeys/s
Actually LBC is still checking the 2^55 range. So even pasting numbers in http://brain.evilbs.com/ by hand is faster than LBC You are your "fork" in several 1080, 1070 as yet apparently also did not catch wildfowl. From where to have already gone or left this venture? I'm your program .. 49 .., 57 .., 58 ..., 59 ..., 60..., scanned in scatter, uselessly, can he be between 66-72 (30045390491869460+36028797018963968=66074187510833428 < 72057594037927936) who knows, as in step 611140496167764+1125899906842624=1737040403010388 < 2058769515153876 < 2251799813685248.
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holy_ship
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July 26, 2018, 02:47:32 AM |
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phrase ip addresses (sha256) but there is also not a small figure 4294967296.
4294967296 keys to check is job for 80 seconds. OK, if they are not sequential, let it be - 1 hour. Andzhig, you should write your native language, because when you write in English I always get an impression that you have undertreated meningitis.
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Sample2
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July 26, 2018, 02:57:07 AM |
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looks really easy to crack
why would reward be so high
It is not easy to crack the bitcoin address. Bitcoin cryptography is using Elliptic Curve Cryptography (ECC) which it looks like has a pattern but it is not. It looks easy to crack but it is not. So, let them go a head and we see.
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ordeath
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July 26, 2018, 12:18:06 PM |
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This is one of the things that I really love about this mysterious world of Bitcoin and cryptocurrency, you can always find something interesting in it, althought I am not going to resolve this puzzle because I am a dummy
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Yahkinator
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July 27, 2018, 10:05:41 AM |
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Andzhig, you should write your native language, because when you write in English I always get an impression that you have undertreated meningitis.
lol. I'm glad I'm not the only one that was left just scratching my head. Hey Holy_ship, can you check on the thread about your ndv vanitygen build? I have a couple questions in there and I can't message you because I'm still a newbie on here.
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lolobit2
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July 28, 2018, 06:52:49 AM |
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ARULBERO help me please a private key of the my wallet lost
hi, I will help you to restore your wallet, write email in private messages
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ZafotheNinja
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July 29, 2018, 03:22:50 AM |
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For anyone still trying to find a pattern in cryptographicly secure random data (me), here is a chart. X=% in Space, Y=Puzzle Number. Only did up to 40 for now, I'll get around to the rest eventually [spoiler] [/spoiler]
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Amnuazka
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July 31, 2018, 12:11:21 AM |
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I found this : 0 01 011 0001 00101 001101 0110100 01010010 000100010 0100111110 01110011100 001000110110 0000001110001 00111000010001 001000011110010 0010101110010000 00001000111011001 000101010001011000 0101011111100100100 01111110111001010111 000010110111110101100 0111010000000010101010 01110111000111000110101 011101011110001100111111 0011110110001011000011000 01111010001111110100010000 010000111001010010101000010 0110111110010011110110011100 01101101111011101001100100100 001001010100011100011010111110 0000110100011110000101100111001 01100010011110011111111101011101 000111100110110101010011110011111 0010100000001010100010000100100101 00110000110101111100110100001000000 010000011110110000100101001010100000 0111011110000100010101111101110011000 01101100111111001100000110001001010000 001011011111101011001011011101101001110 0100010011101110100000000000111001010101 01001100110100011111001110010100001110100 11010010011111000110110101110110110000111 11110100100101001101001101110111101110100 10010101000110010011100010001110000000101 01011000100000000000000101110100010111110 11010110010111000011110110001010100100111 00101001100000100100111110110011011100010 It begun from no 15 to no 55 15 16
0 0 1 1 1 1 1 1 0 0 1 1 1 0 0
55 0 1 1 1 1 1 0 0 0 0 0 0 1 1 0 0 1 0 0 1 0 0 1 1 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 1 0 1 0 1 0 1 0 holy_ship , Andzhig, arulbero, or anyone.., can you analize the next code ( x ) for 56 ? x 0x 01x 011x 0001x 00101x 001101x 0110100x 01010010x 000100010x 0100111110x 01110011100x 001000110110x 0000001110001x 00111000010001x 001000011110010x 0010101110010000x 00001000111011001x 000101010001011000x 0101011111100100100x 01111110111001010111x 000010110111110101100x 0111010000000010101010x 01110111000111000110101x 011101011110001100111111x 0011110110001011000011000x 01111010001111110100010000x 010000111001010010101000010x 0110111110010011110110011100x 01101101111011101001100100100x 001001010100011100011010111110x 0000110100011110000101100111001x 01100010011110011111111101011101x 000111100110110101010011110011111x 0010100000001010100010000100100101x 00110000110101111100110100001000000x 010000011110110000100101001010100000x 0111011110000100010101111101110011000x 01101100111111001100000110001001010000x 001011011111101011001011011101101001110x 0100010011101110100000000000111001010101x 01001100110100011111001110010100001110100x 11010010011111000110110101110110110000111x 11110100100101001101001101110111101110100x 10010101000110010011100010001110000000101x 01011000100000000000000101110100010111110x 11010110010111000011110110001010100100111x 00101001100000100100111110110011011100010x
Thank you.
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