Bitcoin puzzle transaction ~32 BTC prize to who solves it

[Andzhig]

fast ... last 55 as I understand the author of the puzzle specially flashed the public key (threw some bitcoin and deducing). to see how it works baby step gigant step.

they all lie side by side (in its macrocosm)), The scanner would be with a random (127,7-16 signs randomisation) and a step up-down for a couple million.

                 56                                                                  49                                                          42                                    
127,*************************   127     127,27325883491766944644041359425  127,34166804622509516775608062744  
63,583036446150909604124734642028  63,5    63,660348182749885381781496107578    63,668431836413219571113586425781  
31,861576626618332619411688710898  31,75   31,787429311634468831471167504787   31,771796089393319562077522277832
15,90613502904471082688431238239   15,875  15,908679856821891007712110877037   15,926393464003922417759895324707
7,941484368221046585833988729064   7,9375  7,9644791460323176579549908638        7,966582541557727381587028503418

                35
127,414638392627239227294921875  127
63,588673464953899383544921875  
31,7922732196748256683349609375
15,90996809303760528564453125  
7,938812442123889923095703125  

  
                28
127,151996135711669921875           127
63,58295440673828125    
31,7968273162841796875  
15,876374721527099609375
7,9462490081787109375  

 
                21
127,1361083984375                         127
63,58837890625
31,82952880859375
15,9052734375
7,954345703125
 

                14
127,359375                                     127      

                 7
127,40625

you can try to search 7,9 she meets frequently for the next step 576460752303423488 - (((((((((7,94910898 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)  - 571957152676052992) * 128)
next step 576460752303423488 * 128 = 73786976294838206464 - 576460752303423488 = 73210515542534782976 formula 73786976294838206464 - ((((((((((7,94910898 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128) * 128)  - 73210515542534782976) * 128)

if you look at the beginning

0               1           2          
1               3           4          
2               7           8            
3               8          16        
4              21          32          
5              49          64          
6              76         128          
7             224         256          
8             467         512            
9             514        1024 < 1018,15625
10           1155       2048
11           2683       4096
12           5216       8192
13           10544    16384  
14           26867    32768
15           51510    65536
16           95823   131072 < 130324 < 748
17          198669   262144  
18          357535   524288
19          863317  1048576
20         1811764  2097152
21         3007503  4194304
22         5598802  8388608
23        14428676 16777216  < 16664492 112724 (16777216-112724=16664492/128/128/128)
24        33185509 33554432  
25        54538862 67108864  
26       111949941 134217728    
27       227634408 268435456

You can try to print the number first example take the second step 7,954345703125 * 128 = < 1018,15625 * 128 = < 130324 ; 131072-130324= < 748 a prime number to find 131072-748=130324/128/128 = 7,954345703125 formula 131072 - ((((((((7,954345703125  * 128) * 128)  - 130048) * 128) = 95744 slightly askew because 95823/128=748,6171875 ; 131072 - 748,6171875 = 130323,3828125/128/128= 7,954308032989501953125 with this value 131072 - ((((((((7,954308032989501953125  * 128) * 128)  - 130048) * 128) = 95823  here you can try 749

take the previous step 7,9462490081787109375 * 128 = 1017,119873046875 * 128 = < 130191,34375 on the second multiplication, the tail does not disappear * 128 = < 16664492 (etc with each puzzle...)

you can take a number from the first step or from the second (any) and choose a number for the formula, for example last thing 7,941484368221046585833988729064*128*128=130113,27988893362726230407133698 on the idea should be enough for the first 8 characters (meaning scanning). 131072 - 130113 = 959 and let's go 959,2 959,3 959,4.. 959,23 959,28... 959,50 959,59.. or 959,random... 960...  

or all can be much simpler to take the number and multiply by 128,  749*128=95872 (95823), (880,656494140625) 881 * 128* 128 = 14434304 (14428676)... (958,72011106637273769592866301537) 959*128*128*128*128*128*128=4217726604148736 (4216495639600700)... what number to multiply 7 times to get 56.

or the program that the whole numbers searched for and multiplied by the comparator compared with the key.

[1714927015]

1714927015

[1714927015]

1714927015

[princebridge7]

I am incompetent to solve a problem like this, I know its trading at Bittrex and Binance.

but hopefully at the end ny code like this can be solved and I will congratulate the person who broke the code. yuhuuu

[BurtW]

Maybe if we learn a bit more from how the numbers were generated it could greatly optimize the program.

We know exactly how the numbers were generated because the author of the puzzle came into this thread and told us.

Read back and find it if you are interested.

[itod]

Maybe if we learn a bit more from how the numbers were generated it could greatly optimize the program.

We know exactly how the numbers were generated because the author of the puzzle came into this thread and told us.

Read back and find it if you are interested.

Where is the fun in knowing something? Isn't it much more interesting to throw around half-baked theories and draw maps where X marks the hidden treasure chest?

[dalvitka]

After considering a bunch of pvks found by the bots I noticed that many addresses were on the same transaction, after a tight check I saw what kind of pattern the sequence was. One thing I noticed perhaps this transaction was made by the Bitcoin developers. Some GPU bots would be best to violate it, as shorena has said. Is anyone out there?

[BurtW]

After considering a bunch of pvks found by the bots I noticed that many addresses were on the same transaction, after a tight check I saw what kind of pattern the sequence was. One thing I noticed perhaps this transaction was made by the Bitcoin developers. Some GPU bots would be best to violate it, as shorena has said. Is anyone out there?

Yes, ALL the Bitcoins in the puzzle transaction were placed there in a single transaction.  The author of the puzzle transaction came into this thread and explained the whole thing.  Yes, there is a well defined pattern to the puzzle transaction.  All the private keys are random but each key uses an increasing bit length.  Key one has a random one bit key, key two has a random two bit key, key three has a random three bit key, etc.  All of this work trying to find out a pattern to the random private keys is a complete and total waste of time.  "Fun" maybe, if you like to waste your time trying to find a pattern in random data.  If you bothered to read the thread you would know all this and would not have to guess.

[Andzhig]

Addresses are all compressed in the puzzle?

if you like to waste your time trying to find a pattern in random data

And you've been guessing for a few years now already all the methods have been tried all sorts, random programs generators... and without the slightest hint of luck. began to study "python" in pieces from Inet assembled a generator with a selectable range of randomization (until 1 step) and a hex output and a compressed key, It remains to teach how to compare the address lines generated with the puzzle addresses next or in the file and stop work.

***

in the general gemoro there full with jumps, who understands to supplement the code, but for now you can duplicate and run the sites ...

from bitcoin import *
import random

while True:
    ran = random.randrange(36028797018963968,72057594037927936)
    myhex = "%064x" % ran
    myhex = myhex[:64]
    priv = myhex
    pub = privtopub(priv)
    pubkey1 = encode_pubkey(privtopub(priv), "bin_compressed")
    addr = pubtoaddr(pubkey1)
    n = addr
    if n.strip() == "17aPYR1m6pVAacXg1PTDDU7XafvK1dxvhi":
        print ("found!!!",addr,myhex)
        s1 = myhex
        s2 = addr

        f=open(u"C:/a.txt","a")
        f.write(s1)
        f.write(s2)      
        f.close()
        break
    else:
        print ("searching...",addr,myhex)

the heat went off http://meson.ad-l.ink/7Try5DcVV/image.png I have 20 scanners without problems for the PC to run at the same time, how many on amd ryzen  interesting...

from bitcoin import *
import random

a = int (input("start scan range:"))
b = int (input("end scan range:"))
c = input ("address:")

while True:
    ran = random.randrange(a,b)
    myhex = "%064x" % ran
    myhex = myhex[:64]
    priv = myhex
    pub = privtopub(priv)
    pubkey1 = encode_pubkey(privtopub(priv), "bin_compressed")
    addr = pubtoaddr(pubkey1)
    n = addr
    if n.strip() == c:
        print ("found!!!",addr,myhex)
        s1 = myhex
        s2 = addr

        f=open(u"C:/a.txt","a")
        f.write(s1)
        f.write(s2)       
        f.close()
        break
    else:
        print ("searching...",addr,myhex)

python exists for android... need to somehow gpu to steal, numba...

***

Key one has a random one bit key, key two has a random two bit key, key three has a random three bit key, etc.

deterministic random? most likely generated by time in windows.

[BurtW]

 ... some code ...

The LBC project is currently running at 346.02 Mkeys/s and recently had a peak of about 521 Mkeys/s

How many keys per second does your method check?

[Andzhig]

Yes it is clear that compared to LBC this is a louse (but if desired and a louse a lion can gnaw) this is so for luck, suddenly there is a magic step for a random house. There are many options you can think of, and step through a number, sort only even, odd, take each 128,256,512 ... multiply them ... floating scan area, some magical jumps, etc.

from bitcoin import *
import random
import math

while True:
    f = random.random() + 15.1
    g = f
    b = 1152921504606846976 - ((((((((((g * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)  - 1143914305352105984) * 128)
    c = math.trunc(b)
    ran = c
    myhex = "%064x" % ran
    myhex = myhex[:64]
    priv = myhex
    pub = privtopub(priv)
    pubkey1 = encode_pubkey(privtopub(priv), "bin_compressed")
    addr = pubtoaddr(pubkey1)
    n = addr
    if n.strip() == "1HAX2n9Uruu9YDt4cqRgYcvtGvZj1rbUyt":
        print ("found!!!",addr,myhex)
        s1 = myhex
        s2 = addr

        f=open(u"C:/a.txt","a")
        f.write(s1)
        f.write(s2)       
        f.close()
        break
    else:
        print ("searching...",f,addr,myhex)

formula 1152921504606846976 - ((((((((((15.9 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)  - 1143914305352105984) * 128)

after 15.9xxxxxxxxxxxxxxxxxxxxxxxxxxx a random number of 29, 30 numbers can be sausage immediately at all after 7 steps of the puzzle.

1152921504606846976 - ((((((((((15,9075849271 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)  - 1143914305352105984) * 128)
147573952589676412928 - (((((((((((15,9041635330 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)  - 146421031085069565952) * 128)
18889465931478580854784 - ((((((((((((15,9058575788 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)  - 18741891978888904441856) * 128)
2417851639229258349412352 - (((((((((((((15,9058575788 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)  - 2398962173297779768557568) * 128)
309485009821345068724781056 - ((((((((((((((15,9081997978 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)* 128)  - 307067158182115810375368704) * 128)
39614081257132168796771975168 - (((((((((((((((15,9081997978 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)  - 39304596247310823728047194112) * 128)
5070602400912917605986812821504 - ((((((((((((((((15,9095945490 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)  - 5030988319655785437190040846336) * 128)
649037107316853453566312041152512 - (((((((((((((((((15,9095945490 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)  - 643966504915940535960325228331008) * 128)
83076749736557242056487941267521536 - ((((((((((((((((((15,90 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)  - 82427712629240388602921629226369024) * 128)
10633823966279326983230456482242756608 - (((((((((((((((((((15,90 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)  - 10550747216542769741173968540975235072) * 128)
1361129467683753853853498429727072845824 - ((((((((((((((((((((15,90 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)  - 1350495643717474526870267973244830089216) * 128)
174224571863520493293247799005065324265472 - (((((((((((((((((((((15,90 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)  - 172863442395836739439394300575338251419648) * 128)
22300745198530623141535718272648361505980416 - ((((((((((((((((((((((15,90 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)  - 22126520626667102648242470473643296181714944) * 128)
2854495385411919762116571938898990272765493248 - (((((((((((((((((((((((15,90 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)  - 2832194640213389138975036220626341911259512832) * 128)
365375409332725729550921208179070754913983135744 - ((((((((((((((((((((((((15,90 * 128) * 128)  * 128) * 128)* 128)  * 128) * 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)* 128)  - 362520913947313809788804636240171764641217642496) * 128)

[lolobit2]

Andzhig

Пpивeтcтвyю ,интepecнa тeмa взлoмa бтк ,ecть нapaбoтки
нaпиши пoчтy в личкy -oбcyдим

[holy_ship]

Python is not hipsterish enough!
True mama's cryptokiddies choose PHP parser of directory.io
And adding right magic constant to skip "unnecessary" pages is vital!

So, first you should look at you mom's Crystal Ball to find the magic number!

[holy_ship]

The LBC project[/url] is currently running at 346.02 Mkeys/s

Actually LBC is still checking the 2^55 range. So even pasting numbers in http://brain.evilbs.com/ by hand is faster than LBC 

[Andzhig]

Andzhig

Пpивeтcтвyю ,интepecнa тeмa взлoмa бтк ,ecть нapaбoтки
нaпиши пoчтy в личкy -oбcyдим

Thank you, from me a cracker like Harry Dunn plumber in the movie "Dumb & Dumber" when he came to the house of a woman. Specially for you there is an idea scan through a phrase ip addresses (sha256) but there is also not a small figure 4294967296.

The LBC project[/url] is currently running at 346.02 Mkeys/s

Actually LBC is still checking the 2^55 range. So even pasting numbers in http://brain.evilbs.com/ by hand is faster than LBC 

You are your "fork" in several 1080, 1070 as yet apparently also did not catch wildfowl. From where to have already gone or left this venture? I'm your program .. 49 .., 57 .., 58 ..., 59 ..., 60..., scanned in scatter, uselessly, can he be between 66-72 (30045390491869460+36028797018963968=66074187510833428 < 72057594037927936) who knows, as in step 611140496167764+1125899906842624=1737040403010388 < 2058769515153876 < 2251799813685248.

[holy_ship]

phrase ip addresses (sha256) but there is also not a small figure 4294967296.

4294967296 keys to check is job for 80 seconds. OK, if they are not sequential, let it be - 1 hour. 

Andzhig, you should write your native language, because when you write in English I always get an impression that you have undertreated meningitis.

[Sample2]

looks really easy to crack

why would reward be so high

It is not easy to crack the bitcoin address. Bitcoin cryptography is using Elliptic Curve Cryptography (ECC) which it looks like has a pattern but it is not. It looks easy to crack but it is not. So, let them go a head and we see.

[ordeath]

Hi guys,
In continuation to this thread: https://bitcointalk.org/index.php?topic=1305887.0
While playing around with my bot, I found out this mysterious transaction:
https://blockchain.info/tx/08389f34c98c606322740c0be6a7125d9860bb8d5cb182c02f98461e5fa6cd15
those 32.896 BTC were sent to multiple addresses, all the private keys of those addresses seem to be generated by some kind of formula.
For example:
EDIT: If you find the solution feel free to leave a tip 1DPUhjHvd2K4ZkycVHEJiN6wba79j5V1u3

This is one of the things that I really love about this mysterious world of Bitcoin and cryptocurrency, you can always find something interesting in it, althought I am not going to resolve this puzzle because I am a dummy

[Yahkinator]

Andzhig, you should write your native language, because when you write in English I always get an impression that you have undertreated meningitis.

lol.  I'm glad I'm not the only one that was left just scratching my head.

Hey Holy_ship, can you check on the thread about your ndv vanitygen build?  I have a couple questions in there and I can't message you because I'm still a newbie on here. 

[lolobit2]

ARULBERO help me please a private key of the my wallet lost

hi, I will help you to restore your wallet, write email in private messages

[ZafotheNinja]

For anyone still trying to find a pattern in cryptographicly secure random data (me), here is a chart. X=% in Space, Y=Puzzle Number. Only did up to 40 for now, I'll get around to the rest eventually 

[spoiler][/spoiler]

[Amnuazka]

I found this :

0
01
011
0001
00101
001101
0110100
01010010
000100010
0100111110
01110011100
001000110110
0000001110001
00111000010001
001000011110010
0010101110010000
00001000111011001
000101010001011000
0101011111100100100
01111110111001010111
000010110111110101100
0111010000000010101010
01110111000111000110101
011101011110001100111111
0011110110001011000011000
01111010001111110100010000
010000111001010010101000010
0110111110010011110110011100
01101101111011101001100100100
001001010100011100011010111110
0000110100011110000101100111001
01100010011110011111111101011101
000111100110110101010011110011111
0010100000001010100010000100100101
00110000110101111100110100001000000
010000011110110000100101001010100000
0111011110000100010101111101110011000
01101100111111001100000110001001010000
001011011111101011001011011101101001110
0100010011101110100000000000111001010101
01001100110100011111001110010100001110100
11010010011111000110110101110110110000111
11110100100101001101001101110111101110100
10010101000110010011100010001110000000101
01011000100000000000000101110100010111110
11010110010111000011110110001010100100111
00101001100000100100111110110011011100010

It begun from no 15 to no 55
15   16

       0
0     1
1     1
1     1
1     0
0     1
1     1
0     0

55

0
1
1
1
1
1
0
0
0
0
0
0
1
1
0
0
1
0
0
1
0
0
1
1
0
0
0
0
0
0
1
1
1
1
0
0
0
0
0
1
0
1
0
1
0
1
0

holy_ship , Andzhig, arulbero, or anyone.., can you analize the next code ( x ) for 56 ?

x
0x
01x
011x
0001x
00101x
001101x
0110100x
01010010x
000100010x
0100111110x
01110011100x
001000110110x
0000001110001x
00111000010001x
001000011110010x
0010101110010000x
00001000111011001x
000101010001011000x
0101011111100100100x
01111110111001010111x
000010110111110101100x
0111010000000010101010x
01110111000111000110101x
011101011110001100111111x
0011110110001011000011000x
01111010001111110100010000x
010000111001010010101000010x
0110111110010011110110011100x
01101101111011101001100100100x
001001010100011100011010111110x
0000110100011110000101100111001x
01100010011110011111111101011101x
000111100110110101010011110011111x
0010100000001010100010000100100101x
00110000110101111100110100001000000x
010000011110110000100101001010100000x
0111011110000100010101111101110011000x
01101100111111001100000110001001010000x
001011011111101011001011011101101001110x
0100010011101110100000000000111001010101x
01001100110100011111001110010100001110100x
11010010011111000110110101110110110000111x
11110100100101001101001101110111101110100x
10010101000110010011100010001110000000101x
01011000100000000000000101110100010111110x
11010110010111000011110110001010100100111x
00101001100000100100111110110011011100010x

Thank you.