Deleted

[coindancer]

what about the names? everybody seems to agree the it is the last name. why not the first letter of the first name?

[1714912714]

1714912714

[Adriandmen]

what about the names? everybody seems to agree the it is the last name. why not the first letter of the first name?

For the Steve Jobs case, it was the last name, since the letter S can't be after the 5 in a private key. So we assumed that we need the last name of the other names.

[coindancer]

what about the names? everybody seems to agree the it is the last name. why not the first letter of the first name?

For the Steve Jobs case, it was the last name, since the letter S can't be after the 5 in a private key. So we assumed that we need the last name of the other names.

sorry if this is a bit OT, but with S and 5 (also I and l i guess and maybe some other combinations) it is only possible to have one of those?
so if i have a 5 no S is possible afterwards and if i have an S no 5 is possible? do i get it right? maybe this can also help us to narrow it down.

[Coding Enthusiast]

##
 

let me explain about the Upper/Lower cases of my choice.
i say these colors of each picture should mean something too, and they don't look random to me (otherwise what is the point of similar colors ). so this is my key:
i choose a color and find a box that i am sure about the upper/lower state so i say the rest should be the same too for example since the box #1 is J all the same color should be Upper too.

color index : U=Upper L=Lower : reason index
0 : L : every other color has some reason to be U so i go with L on this color.
1 : U : 1
2 : U : 34
5 : U : 29&41&44
8 : U : 31
i think i will stick to this theory for now, but i may try your suggestions later too.
also the gist was updated. will run the code in the morning

[Strongkored]

Did you not even read my updated post??

I went to the trouble of getting wallet signed by Jan as was requested in this thread before:

^^^

"OK GUISE  Grin

Update from Jan.

Wallet message has been signed:

Bitcointalk

G3ZTaz0Vehwhur68icyeN34wpDfFKcqIucY4zrvG2/T7QJFsdD6IS4QQTCPoJnHZ0u/F9vZIr1E76bO37wgJVSI="

Sorry friends, I missed your posts on that part. Since I yesterday just read in part, there is someone who asks signed message from the address. More thank you for answering my questions. And still looking for ways to solve this puzzle. hehe

[xhomerx10]

##
 

let me explain about the Upper/Lower cases of my choice.
i say these colors of each picture should mean something too, and they don't look random to me (otherwise what is the point of similar colors ). so this is my key:
i choose a color and find a box that i am sure about the upper/lower state so i say the rest should be the same too for example since the box #1 is J all the same color should be Upper too.

color index : U=Upper L=Lower : reason index
0 : L : every other color has some reason to be U so i go with L on this color.
1 : U : 1
2 : U : 34
5 : U : 29&41&44
8 : U : 31
i think i will stick to this theory for now, but i may try your suggestions later too.
also the gist was updated. will run the code in the morning

 Interesting idea.  I hadn't considered the colours to mean anything.

[coindancer]

##
 

let me explain about the Upper/Lower cases of my choice.
i say these colors of each picture should mean something too, and they don't look random to me (otherwise what is the point of similar colors ). so this is my key:
i choose a color and find a box that i am sure about the upper/lower state so i say the rest should be the same too for example since the box #1 is J all the same color should be Upper too.

color index : U=Upper L=Lower : reason index
0 : L : every other color has some reason to be U so i go with L on this color.
1 : U : 1
2 : U : 34
5 : U : 29&41&44
8 : U : 31
i think i will stick to this theory for now, but i may try your suggestions later too.
also the gist was updated. will run the code in the morning

 Interesting idea.  I hadn't considered the colours to mean anything.

there are to many different but kind of the same ones for my liking to deduct a rule. so i am kind of skeptical. also you could make a point of the color the pics and symbols are drawn with.

[coindancer]

what about the names? everybody seems to agree the it is the last name. why not the first letter of the first name?

For the Steve Jobs case, it was the last name, since the letter S can't be after the 5 in a private key. So we assumed that we need the last name of the other names.

sorry if this is a bit OT, but with S and 5 (also I and l i guess and maybe some other combinations) it is only possible to have one of those?
so if i have a 5 no S is possible afterwards and if i have an S no 5 is possible? do i get it right? maybe this can also help us to narrow it down.

and it would be nice to hear something about this. or at least where i can read up on the matter thx

[xhomerx10]

what about the names? everybody seems to agree the it is the last name. why not the first letter of the first name?

For the Steve Jobs case, it was the last name, since the letter S can't be after the 5 in a private key. So we assumed that we need the last name of the other names.

sorry if this is a bit OT, but with S and 5 (also I and l i guess and maybe some other combinations) it is only possible to have one of those?
so if i have a 5 no S is possible afterwards and if i have an S no 5 is possible? do i get it right? maybe this can also help us to narrow it down.

and it would be nice to hear something about this. or at least where i can read up on the matter thx

 Okay I'll tell you what I know.  A private key in WIF (Wallet Import Format) is 51 characters in base58.  For Bitcoin mainnet, the WIF private key will always begin with a 5.  Why?
Because
 1. Take the ECDSA private key which can be any unsigned integer from 0x1 to 0xFFFF FFFF FFFF FFFF FFFF FFFF FFFF FFFE BAAE DCE6 AF48 A03B BFD2 5E8C D036 4140
 2. and you place the network identifier (0x80 for bitcoin mainnet) in front. (by the way, 0x simply means hexadecimal format).
 3. You take this result and perform a SHA256 hash on it.
 4. Take the result of that and perform another SHA256 hash on it.
 5. Take the last 4 bytes of the previous result (used as a checksum) and add it to the end of the number in step 2
 6. and finally convert that hexadecimal number to base58 and you have the WIF private key.

Here is the lowest possible address with the network identifier and checksum added:
800000000000000000000000000000000000000000000000000000000000000001A85AA87E
and here is the largest:
80FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364140F511BD7A

 As you can see, the range of values is limited by the use of the network identifier which is why when converted to base58, the result will begin with 5 and be limited to H, J or K for the second character.

Read about it here and here.

Now I expect some puzzle solution suggestions from you very soon!



 

[Chris!]

what about the names? everybody seems to agree the it is the last name. why not the first letter of the first name?

For the Steve Jobs case, it was the last name, since the letter S can't be after the 5 in a private key. So we assumed that we need the last name of the other names.

sorry if this is a bit OT, but with S and 5 (also I and l i guess and maybe some other combinations) it is only possible to have one of those?
so if i have a 5 no S is possible afterwards and if i have an S no 5 is possible? do i get it right? maybe this can also help us to narrow it down.

and it would be nice to hear something about this. or at least where i can read up on the matter thx

 Okay I'll tell you what I know.  A private key in WIF (Wallet Import Format) is 51 characters in base58.  For Bitcoin mainnet, the WIF private key will always begin with a 5.  Why?
Because
 1. Take the ECDSA private key which can be any unsigned integer from 0x1 to 0xFFFF FFFF FFFF FFFF FFFF FFFF FFFF FFFE BAAE DCE6 AF48 A03B BFD2 5E8C D036 4140
 2. and you place the network identifier (0x80 for bitcoin mainnet) in front. (by the way, 0x simply means hexadecimal format).
 3. You take this result and perform a SHA256 hash on it.
 4. Take the result of that and perform another SHA256 hash on it.
 5. Take the last 4 bytes of the previous result (used as a checksum) and add it to the end of the number in step 2
 6. and finally convert that hexadecimal number to base58 and you have the WIF private key.

Here is the lowest possible address with the network identifier and checksum added:
800000000000000000000000000000000000000000000000000000000000000001A85AA87E
and here is the largest:
80FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364140F511BD7A

 As you can see, the range of values is limited by the use of the network identifier which is why when converted to base58, the result will begin with 5 and be limited to H, J or K for the second character.

Read about it here and here.

Now I expect some puzzle solution suggestions from you very soon!



 

Ya, um... That 's what I was going to say 

Sadly I've been lurking on this thread for quite a while and I have to say I'm impressed with the answers you're all finding. This is WAY over my head haha so good luck!

[Tasssty]

Pretty much allot of work even for 0.5 BTC, just the last page is filled with clues, Good luck to those trying to decipher this thing.

[Herbert2020]

Pretty much allot of work even for 0.5 BTC, just the last page is filled with clues, Good luck to those trying to decipher this thing.

it is not just about the prize you get, although i say $290 is a pretty good prize. but it is mostly about the game and solving it. you can call it a treasure hunt.

although what bothers me about this, is the fact that i am not so sure if this is a good puzzle with only one possible solution.

for example you can already see many people straggling about the answers like that plane picture many say "jet" others say "F16" "mig" or it can simply be "Plane" "Airplane" or "Fighter-plane-thingy" this last part was a brain fart!

[xhomerx10]

Pretty much allot of work even for 0.5 BTC, just the last page is filled with clues, Good luck to those trying to decipher this thing.

it is not just about the prize you get, although i say $290 is a pretty good prize. but it is mostly about the game and solving it. you can call it a treasure hunt.

although what bothers me about this, is the fact that i am not so sure if this is a good puzzle with only one possible solution.

for example you can already see many people straggling about the answers like that plane picture many say "jet" others say "F16" "mig" or it can simply be "Plane" "Airplane" or "Fighter-plane-thingy"

 I am certain that the plane image can only be 3 letters.

[Coding Enthusiast]

i think i have worked more on my code and the interface than i have ever worked on the puzzle itself

#master of xaml

but to be fair, i learned a lot in the process about base58 and also conversion to hex, also about multiplying TimeSpan so i am happy.

[xhomerx10]

i think i have worked more on my code and the interface than i have ever worked on the puzzle itself

#master of xaml

but to be fair, i learned a lot in the process about base58 and also conversion to hex, also about multiplying TimeSpan so i am happy.

 I'm only asking since I made this mistake.  Did you test your program with a valid private key in WIF?

[Coding Enthusiast]

I'm only asking since I made this mistake.  Did you test your program with a valid private key in WIF?

lol, imagine if my code was wrong all this time, i have ran the code for almost 70-100 million (each time 11 mil-5mil)

but no i doubled checked it now and it was ok.
i went through This to create my code and after busting my ass to get it to work i found this written in c# with a nice NuGet package

i tested with the private key on wiki page and a couple from directory[dot]io and today i made a new Electrum wallet to double check it with compressed private keys too. all successful.

[coindancer]

what about the names? everybody seems to agree the it is the last name. why not the first letter of the first name?

For the Steve Jobs case, it was the last name, since the letter S can't be after the 5 in a private key. So we assumed that we need the last name of the other names.

sorry if this is a bit OT, but with S and 5 (also I and l i guess and maybe some other combinations) it is only possible to have one of those?
so if i have a 5 no S is possible afterwards and if i have an S no 5 is possible? do i get it right? maybe this can also help us to narrow it down.

and it would be nice to hear something about this. or at least where i can read up on the matter thx

 Okay I'll tell you what I know.  A private key in WIF (Wallet Import Format) is 51 characters in base58.  For Bitcoin mainnet, the WIF private key will always begin with a 5.  Why?
Because
 1. Take the ECDSA private key which can be any unsigned integer from 0x1 to 0xFFFF FFFF FFFF FFFF FFFF FFFF FFFF FFFE BAAE DCE6 AF48 A03B BFD2 5E8C D036 4140
 2. and you place the network identifier (0x80 for bitcoin mainnet) in front. (by the way, 0x simply means hexadecimal format).
 3. You take this result and perform a SHA256 hash on it.
 4. Take the result of that and perform another SHA256 hash on it.
 5. Take the last 4 bytes of the previous result (used as a checksum) and add it to the end of the number in step 2
 6. and finally convert that hexadecimal number to base58 and you have the WIF private key.

Here is the lowest possible address with the network identifier and checksum added:
800000000000000000000000000000000000000000000000000000000000000001A85AA87E
and here is the largest:
80FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364140F511BD7A

 As you can see, the range of values is limited by the use of the network identifier which is why when converted to base58, the result will begin with 5 and be limited to H, J or K for the second character.

Read about it here and here.

Now I expect some puzzle solution suggestions from you very soon!

thank you
and here i a hint from me. 25 could also be Celluloid instead of film. hope this helps

[xhomerx10]

I'm only asking since I made this mistake.  Did you test your program with a valid private key in WIF?

lol, imagine if my code was wrong all this time, i have ran the code for almost 70-100 million (each time 11 mil-5mil)

but no i doubled checked it now and it was ok.
i went through This to create my code and after busting my ass to get it to work i found this written in c# with a nice NuGet package

i tested with the private key on wiki page and a couple from directory[dot]io and today i made a new Electrum wallet to double check it with compressed private keys too. all successful.

 Yes I can imagine... I ran through almost 300 million without realizing my program wasn't valid. 
Thanks for the information.  I'm going to check out the c program.

[xhomerx10]

what about the names? everybody seems to agree the it is the last name. why not the first letter of the first name?

For the Steve Jobs case, it was the last name, since the letter S can't be after the 5 in a private key. So we assumed that we need the last name of the other names.

sorry if this is a bit OT, but with S and 5 (also I and l i guess and maybe some other combinations) it is only possible to have one of those?
so if i have a 5 no S is possible afterwards and if i have an S no 5 is possible? do i get it right? maybe this can also help us to narrow it down.

and it would be nice to hear something about this. or at least where i can read up on the matter thx

 Okay I'll tell you what I know.  A private key in WIF (Wallet Import Format) is 51 characters in base58.  For Bitcoin mainnet, the WIF private key will always begin with a 5.  Why?
Because
 1. Take the ECDSA private key which can be any unsigned integer from 0x1 to 0xFFFF FFFF FFFF FFFF FFFF FFFF FFFF FFFE BAAE DCE6 AF48 A03B BFD2 5E8C D036 4140
 2. and you place the network identifier (0x80 for bitcoin mainnet) in front. (by the way, 0x simply means hexadecimal format).
 3. You take this result and perform a SHA256 hash on it.
 4. Take the result of that and perform another SHA256 hash on it.
 5. Take the last 4 bytes of the previous result (used as a checksum) and add it to the end of the number in step 2
 6. and finally convert that hexadecimal number to base58 and you have the WIF private key.

Here is the lowest possible address with the network identifier and checksum added:
800000000000000000000000000000000000000000000000000000000000000001A85AA87E
and here is the largest:
80FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364140F511BD7A

 As you can see, the range of values is limited by the use of the network identifier which is why when converted to base58, the result will begin with 5 and be limited to H, J or K for the second character.

Read about it here and here.

Now I expect some puzzle solution suggestions from you very soon!

thank you
and here i a hint from me. 25 could also be Celluloid instead of film. hope this helps

 Celluoid?  I hadn't thought of that.  Thanks!  As soon as I'm home (if the puzzle hasn't been solved) I'll add that possibility.

[Coding Enthusiast]

since this was not yet redeemed i worked on some new theories that i share here

the following are the hex codes of the colors and addition of the background color with the image color:

index	|	backgroud color	|	image color	|	blend
0	|	b5dec9	|	ee437d	|	d291a3
1	|	d2e9d5	|	463562	|	8c8F9c
2	|	0d2630	|	9ad6dc	|	547e86
5	|	9ad6dc	|	0d242e	|	547D85
8	|	eb407c	|	f38b94	|	EF6688

it may be totally random but it also may give someone some cool idea!

i will update the Gist soon after this post.
finally found that game for index 42:
http://www.miniclip.com/games/bubble-trouble/en/

30 can also be picture of a long whistle
https://www.google.com/search?q=long+whistle
https://www.google.com/search?q=rape+whistle+necklace