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Author Topic: What are the chances to get a 13+ losing streak?  (Read 1359 times)
Superhitech
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August 13, 2016, 06:55:35 PM
 #41

Hi guys, does anyone here knows what are the mathematical chances to get a 13+ losing streak playing dice with 50% chances of winning? Or how you can calculate it?

The probability of a losing streak of 13 at 50% win chance is 0.5^13 = 0.00012207031 or 0.012207031% or once every 8192 rolls.

I didn't realize the odds were that low, funny that it happens to me often  Sad

Hi guys, does anyone here knows what are the mathematical chances to get a 13+ losing streak playing dice with 50% chances of winning? Or how you can calculate it?
I don't know how you calculate it but based on my experience, there is a higher odds of getting a loosing streak if you have a higher bet. Most I have encountered is 12 red streak.

I think this is more of a psychological thing; I've also found that it seems like when you bet higher, you lose more. However, the sites are provably fair; they can't do this. It's all in the mind, as we tend to care more about our bet when the amount we bet is higher.

Either way, OP, if you were trying to find the odds to try and make a profit off dice, I'd advise against it, as the house always wins in the long run.
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