Math riddle my 8th grader needs help with?

[MicroGuy]

My son was asked to use the number 4 in a math problem 16 times so that the result equals 5000.

So far the closest we've gotten is 5004.

The problem can only contains 4's.

[Lutpin]

I've put my math team on it, they did 8th grade twice IIRC, so naturally they should have an advantage.

[whywefight]

I've put my math team on it, they did 8th grade twice IIRC, so naturally they should have an advantage.

fu lutpin

hey op, may i ask how did you get to 5004?

[MicroGuy]

I've put my math team on it, they did 8th grade twice IIRC, so naturally they should have an advantage.

Thank you!

I've put my math team on it, they did 8th grade twice IIRC, so naturally they should have an advantage.

fu lutpin

hey op, may i ask how did you get to 5004?

4444 + 444 + 44 + 44 + (4 x 4) + 4 + 4 + 4 = 5004    

[Lutpin]

4444 + 444 + 44 + 44 + (4 x 4) + 4 + 4 +4 = 5004

4444 + 444 + 44 + 44 + 44 - 4 - ( 4 x 4 ) = 5000

[whywefight]

4444 + 444 + 44 + 44 + (4 x 4) + 4 + 4 +4 = 5004

4444 + 444 + 44 + 44 + 44 - 4 - ( 4 x 4 ) = 5000

pffffffffffffffffffffffffffffff.............

[MicroGuy]

4444 + 444 + 44 + 44 + (4 x 4) + 4 + 4 +4 = 5004

4444 + 444 + 44 + 44 + 44 - 4 - ( 4 x 4 ) = 5000

My son is very happy. He got to stay up late AND has the solution! Thank you.     

[Foxpup]

4444 + 444 + 44 + 44 + (4 x 4) + 4 + 4 +4 = 5004

4444 + 444 + 44 + 44 + 44 - 4 - ( 4 x 4 ) = 5000

That's cheating. He said using only the number 4, not the numeral 4. Here's what I came up with:

((4/4) + (4/4) + (4/4) + 4 + 4(4+4)) x 4 x 4 x (4+4) + 4 + 4 =
(1 + 1 + 1 + 4 + 4(8)) x 16 x 8 + 8 =
(7 + 32) x 128 + 8 =
39 x 128 + 8 =
4992 + 8 =
5000