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Author Topic: [Super-Raffle] 8x Kialara Labyrinth w/ Silver Balls! 50/50 to win - #457649!  (Read 2836 times)
Hhampuz (OP)
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March 10, 2017, 06:57:57 PM
Last edit: March 17, 2017, 08:26:33 AM by Hhampuz
 #1

Welcome to the raffle for 8x Kialara Labyrinths with Silverballs

These stunning pieces of art captures the essence of Physical Bitcoins by mixing innovation with mesmerizing design

So here's how we'll do it:

16 spots, classic raffle. There will be 8 prizes. Once this is filled we will Select eight blocks and whoever has the correct character at the end of those blocks will win the prizes.

The prize: All winners will get one (1) Kialara Labyrinth with silverballs, random number.



Price per ticket: 0.08BTC.

Pay to this address only: 1MmmqwoeZWeoSXGaxNkwvUKNz4i7K3U4VA

Max spots: None.

Shipping: International insured and tracked shipping is included in the ticket price.

0 - isoneguy
1 - nathansenn
2 - nathansenn
3 - ezeminer
4 - BitcoinPenny
5 - BitcoinPenny
6 - Because of Bitcoin
7 - ezeminer
8 - zekoroger
9 - TheNewAnon
a - chronicsky
b - BitcoinPenny
c - comit
d - BitcoinPenny
e - actmyname
f - Maicol729



One ticket can keep on winning so with a minimal chance someone who picks up one ticket can win the entire lot! There will be 8 blocks drawn, no more, no less.

Please pay asap and include the txID with your post so we can get the show on the road.

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Hhampuz (OP)
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March 10, 2017, 06:58:12 PM
Last edit: March 17, 2017, 12:05:20 PM by Hhampuz
 #2

The following blocks will determine the winners;

Block #457649 - "c" - comit - Congratz!
Block #457650 - "2" - nathansenn - Congratz!
Block #457651 - "3" - ezeminer - Congratz!
Block #457652 - "1" - nathansenn  - Congratz!
Block #457653 - "2" - nathansenn  - Congratz!
Block #457654 - "e" - actmyname  - Congratz!
Block #457655 - "7" - ezeminer  - Congratz!
Block #457656 - "2" - nathansenn  - Congratz!

Hhampuz (OP)
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March 11, 2017, 09:43:47 AM
 #3

Get your ticket now before these will be pulled from the market!

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March 11, 2017, 11:28:36 AM
 #4

I'll take slot 9. Will pay when the raffle is full.
Hhampuz (OP)
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March 11, 2017, 11:49:16 AM
 #5

I'll take slot 9. Will pay when the raffle is full.

Excellent sir!

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March 11, 2017, 01:02:26 PM
 #6

If a spot is still available by early next week, then I'll absolutely take one. (But I expect all sixteen spots will be taken long before then with such a fantastic deal as this! Shocked)

Regards,
Chris

BitcoinPenny.com | "When it comes to bitcoin swag, we make perfect CENTS!"
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March 11, 2017, 03:17:20 PM
 #7

Can I reserve a spot as well? The letter e if possible. Thanks.

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March 11, 2017, 05:36:58 PM
 #8

If it's alright, I'll reserve spot 7 and pay when raffle is almost full.

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March 11, 2017, 06:35:44 PM
 #9

WOW 8 Kialara Labyrinth in one raffle. Good idea and good luck to the rafflers.  Smiley
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March 11, 2017, 07:01:50 PM
 #10

i like the new rule one ticket can keep on winning would be sick if one ticket won them all lol
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March 11, 2017, 07:15:36 PM
 #11

i like the new rule one ticket can keep on winning would be sick if one ticket won them all lol
There's a chance...

A 0.00000000023283064365386962890625% chance, but still a chance.

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March 11, 2017, 08:21:49 PM
 #12

i like the new rule one ticket can keep on winning would be sick if one ticket won them all lol
There's a chance...

A 0.00000000023283064365386962890625% chance, but still a chance.

0.000000023283064365386962890625% chance - you forgot to multiply by 100 Wink

That's 1 in 4,294,967,296 by the way - over half the world's population.

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March 11, 2017, 08:56:17 PM
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 I'll reserve spot 8 and pay when raffle is almost full.
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March 12, 2017, 09:05:03 AM
 #14

Please, Reserve Spot #6. Will pay ticket when raffle will be soon rolled.

Goodluck Everyone  Smiley
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March 12, 2017, 11:00:34 AM
Last edit: March 16, 2017, 02:52:59 PM by isoneguy
 #15

spot 0

edit: 8bdc786eefe62de93f2a0d1b45bdb0af173d40639ad8b8fc2876276c8fbc1031

here we go
Maicol792
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March 12, 2017, 06:01:49 PM
 #16

Please, Reserve Spot #F. Will pay ticket when raffle will be soon rolled.

Goodluck Everyone  Cool
Hhampuz (OP)
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March 12, 2017, 06:32:12 PM
 #17

That leaves us with 9 spots left!

Take a chance and join now to win up to 8 kialara labyrinths!

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March 13, 2017, 04:46:15 AM
 #18

i like the new rule one ticket can keep on winning would be sick if one ticket won them all lol
There's a chance...

A 0.00000000023283064365386962890625% chance, but still a chance.

0.000000023283064365386962890625% chance - you forgot to multiply by 100 Wink

That's 1 in 4,294,967,296 by the way - over half the world's population.

That's rough but I don't need 8 and can live with winning 7 - what would my odds be?   Grin

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March 13, 2017, 05:38:52 AM
Last edit: March 15, 2017, 05:30:37 AM by ezeminer
 #19


i like the new rule one ticket can keep on winning would be sick if one ticket won them all lol
There's a chance...

A 0.00000000023283064365386962890625% chance, but still a chance.

0.000000023283064365386962890625% chance - you forgot to multiply by 100 Wink

That's 1 in 4,294,967,296 by the way - over half the world's population.

That's rough but I don't need 8 and can live with winning 7 - what would my odds be?   Grin
Also posting my TxID for this raffle:
81cd7e7490df582c7a576a9003266abec26eec6f17999aa0dbba2b3f8e182b8f


Edit: My numbers were wrong and actmyname corrected me with the correct information and algorithm for calculating raffles.

m^-(n-1) * (w-n)/m
m = number of slots
w = number of winners
n = number of prizes a single person wins

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March 13, 2017, 11:35:55 PM
 #20

Chance at 7:
0.00000037252902984619140625%

Chance at 6:
0.0000059604644775390625%

Chance at 5:
0.000095367431640625%

Chance at 4:
0.00152587890625%

Chance at 3:
0.0244140625%

Chance at 2:
0.390625%


So yeah, there's a chance.

Also posting my TxID for this raffle:
81cd7e7490df582c7a576a9003266abec26eec6f17999aa0dbba2b3f8e182b8f


Hey, how did you do your calculations? You simply multiplied by 16 starting from 8, right? It doesn't necessarily work like that - seen when you apply the same to the 0.390625% chance, where you have a 6.25% of landing a prize [overall]. Obviously, it's a 1/16 for winning a prize per round. I would think that two, for example, would not be a 0.39% chance, but rather a 1/16 * 7/16 chance - which has a likelihood of 2.734375% - about every 1 in 37.

And for reaching n prizes, it would simply be 1/16^(n-1) * (9-n)/16, no?

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