Bitcoin Forum
April 26, 2024, 07:56:54 PM *
News: Latest Bitcoin Core release: 27.0 [Torrent]
 
   Home   Help Search Login Register More  
Pages: [1]
  Print  
Author Topic: Shuffled Mnemonic  (Read 843 times)
otaviobps (OP)
Newbie
*
Offline Offline

Activity: 4
Merit: 0


View Profile
June 08, 2017, 05:17:23 PM
 #1

Hey everyone.

I have all 12 words, but they are shuffled. Does somebody know how can I brute force them to find the correct order? I know one of the firsts addresses if it helps.

I'm no coder at all, so I don't know how to code or create programs.

Thanks!
1714161414
Hero Member
*
Offline Offline

Posts: 1714161414

View Profile Personal Message (Offline)

Ignore
1714161414
Reply with quote  #2

1714161414
Report to moderator
1714161414
Hero Member
*
Offline Offline

Posts: 1714161414

View Profile Personal Message (Offline)

Ignore
1714161414
Reply with quote  #2

1714161414
Report to moderator
1714161414
Hero Member
*
Offline Offline

Posts: 1714161414

View Profile Personal Message (Offline)

Ignore
1714161414
Reply with quote  #2

1714161414
Report to moderator
"In a nutshell, the network works like a distributed timestamp server, stamping the first transaction to spend a coin. It takes advantage of the nature of information being easy to spread but hard to stifle." -- Satoshi
Advertised sites are not endorsed by the Bitcoin Forum. They may be unsafe, untrustworthy, or illegal in your jurisdiction.
1714161414
Hero Member
*
Offline Offline

Posts: 1714161414

View Profile Personal Message (Offline)

Ignore
1714161414
Reply with quote  #2

1714161414
Report to moderator
1714161414
Hero Member
*
Offline Offline

Posts: 1714161414

View Profile Personal Message (Offline)

Ignore
1714161414
Reply with quote  #2

1714161414
Report to moderator
calkob
Hero Member
*****
Offline Offline

Activity: 1092
Merit: 520


View Profile
June 08, 2017, 06:42:27 PM
 #2

Your looking bitcoin dave,  https://walletrecoveryservices.com/

goodluck

heres a coindesk article about him. http://www.coindesk.com/meet-man-will-hack-long-lost-bitcoin-wallet-money/
otaviobps (OP)
Newbie
*
Offline Offline

Activity: 4
Merit: 0


View Profile
June 08, 2017, 08:03:13 PM
 #3

Thanks!
adaseb
Legendary
*
Offline Offline

Activity: 3738
Merit: 1708



View Profile
June 08, 2017, 09:05:08 PM
 #4

Hey everyone.

I have all 12 words, but they are shuffled. Does somebody know how can I brute force them to find the correct order? I know one of the firsts addresses if it helps.

I'm no coder at all, so I don't know how to code or create programs.

Thanks!

Just do it one by one, only 144 possible scenarios.

.BEST..CHANGE.███████████████
██
██
██
██
██
██
██
██
██
██
██
██
██
██
██
██
██
██
██
██
██
██
██
██
███████████████
..BUY/ SELL CRYPTO..
DannyHamilton
Legendary
*
Offline Offline

Activity: 3374
Merit: 4606



View Profile
June 09, 2017, 12:22:43 AM
 #5

Just do it one by one, only 144 possible scenarios.

Are you sure about that?

  • There are 12 possibilities for the first word
  • You have to try each of the 11 other words with each of the choices that you make for the first word
That's 12 X 11 = 132

For each of those 132 possibilities, there are 10 remaining words to try.

That's 132 X 10 = 1320

For each of those 1320 different sets of 3 words, there are 9 remaining words to try.

That's 132 X 9 = 11880

For each of those 11880 different sets of 4 words, there are 8 remaining words to try.

That's 11880 X 8 = 95040

For each of those 95040 different sets of 5 words, there are 7 remaining words to try.

That's 95040 X 7 = 665280

For each of those 665280 different sets of 6 words, there are 6 remaining words to try.

That's 665280 X 6 = 3991680

For each of those 3991680 different sets of 7 words, there are 5 remaining words to try.

That's 3991680 X 5 = 19958400

For each of those 19958400 different sets of 8 words, there are 4 remaining words to try.

That's 19958400 X 4 = 79833600

For each of those 79833600 different sets of 9 words, there are 3 remaining words to try.

That's 79833600 X 3 = 239500800

For each of those 239500800 different sets of 10 words, there are 2 remaining words to try.

That's 239500800 X 2 = 479001600

For each of those 479001600 different sets of 11 words, there is only 1 remaining word. Since there aren't multiple options, that remaining word doesn't increase the number of possibilities.

That's nearly 480 million possibilities.  (A bit more than 144).

Just doing it one-by-one by hand, might take a bit of time.
jeroenn13
Hero Member
*****
Offline Offline

Activity: 644
Merit: 500



View Profile
June 09, 2017, 12:25:17 AM
 #6

8916100400000 is the number of possibilities, no? Is it not 12 ^ 12?

..bustadice..         ▄▄████████████▄▄
     ▄▄████████▀▀▀▀████████▄▄
   ▄███████████    ███████████▄
  █████    ████▄▄▄▄████    █████
 ██████    ████████▀▀██    ██████
██████████████████   █████████████
█████████████████▌  ▐█████████████
███    ██████████   ███████    ███
███    ████████▀   ▐███████    ███
██████████████      ██████████████
██████████████      ██████████████
 ██████████████▄▄▄▄██████████████
  ▀████████████████████████████▀
                     ▄▄███████▄▄
                  ▄███████████████▄
   ███████████  ▄████▀▀       ▀▀████▄
               ████▀      ██     ▀████
 ███████████  ████        ██       ████
             ████         ██        ████
███████████  ████     ▄▄▄▄██        ████
             ████     ▀▀▀▀▀▀        ████
 ███████████  ████                 ████
               ████▄             ▄████
   ███████████  ▀████▄▄       ▄▄████▀
                  ▀███████████████▀
                     ▀▀███████▀▀
           ▄██▄
           ████
            ██
            ▀▀
 ▄██████████████████████▄
██████▀▀██████████▀▀██████
█████    ████████    █████
█████▄  ▄████████▄  ▄█████
██████████████████████████
██████████████████████████
    ▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄
    ▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀
       ████████████
......Play......
cr1776
Legendary
*
Offline Offline

Activity: 4018
Merit: 1299


View Profile
June 09, 2017, 12:32:57 AM
 #7

8916100400000 is the number of possibilities, no? Is it not 12 ^ 12?

No, 12!  (12 factorial)
Or as Danny pointed out:
479,001,600
DannyHamilton
Legendary
*
Offline Offline

Activity: 3374
Merit: 4606



View Profile
June 09, 2017, 01:27:14 AM
 #8

Or as Danny pointed out:
479,001,600

I can't think of any way to make it more clear to understand than I already have.
dillpicklechips
Hero Member
*****
Offline Offline

Activity: 994
Merit: 507


View Profile
June 09, 2017, 02:05:51 AM
 #9

8916100400000 is the number of possibilities, no? Is it not 12 ^ 12?

Its permutation because it has an order. The formula is n!/(n-r)! which (n-r)! is not shown because it is understandable that it is one because n and r are same in value hence if subtracted would result to 0! or 1.

8916100400000 is the number of possibilities, no? Is it not 12 ^ 12?

No, 12!  (12 factorial)
Or as Danny pointed out:
479,001,600

Your equation 12^12, I don't know where you get it but the right one has been pointed out. Danny's explanation is much easier to understand if you want to.

Combination on the other hand doesn't care for arrangement or order and the formula is (n!)/(r!(n-r)!).
Pages: [1]
  Print  
 
Jump to:  

Powered by MySQL Powered by PHP Powered by SMF 1.1.19 | SMF © 2006-2009, Simple Machines Valid XHTML 1.0! Valid CSS!