Ich will mal gemein sein...
(sehe ich das richtig, dass dies die Funktion für die mathematische Errechnung der Coins ist?)
void GenerateBitcoins(bool fGenerate, CWallet* pwallet)
{
static boost::thread_group* minerThreads = NULL;
int nThreads = GetArg("-genproclimit", -1);
if (nThreads < 0)
nThreads = boost::thread::hardware_concurrency();
if (minerThreads != NULL)
{
minerThreads->interrupt_all();
delete minerThreads;
minerThreads = NULL;
}
if (nThreads == 0 || !fGenerate)
return;
minerThreads = new boost::thread_group();
for (int i = 0; i < nThreads; i++)
minerThreads->create_thread(boost::bind(&BitcoinMiner, pwallet));
}
// Amount compression:
// * If the amount is 0, output 0
// * first, divide the amount (in base units) by the largest power of 10 possible; call the exponent e (e is max 9)
// * if e<9, the last digit of the resulting number cannot be 0; store it as d, and drop it (divide by 10)
// * call the result n
// * output 1 + 10*(9*n + d - 1) + e
// * if e==9, we only know the resulting number is not zero, so output 1 + 10*(n - 1) + 9
// (this is decodable, as d is in [1-9] and e is in [0-9])
uint64 CTxOutCompressor::CompressAmount(uint64 n)
{
if (n == 0)
return 0;
int e = 0;
while (((n % 10) == 0) && e < 9) {
n /= 10;
e++;
}
if (e < 9) {
int d = (n % 10);
assert(d >= 1 && d <= 9);
n /= 10;
return 1 + (n*9 + d - 1)*10 + e;
} else {
return 1 + (n - 1)*10 + 9;
}
}
uint64 CTxOutCompressor::DecompressAmount(uint64 x)
{
// x = 0 OR x = 1+10*(9*n + d - 1) + e OR x = 1+10*(n - 1) + 9
if (x == 0)
return 0;
x--;
// x = 10*(9*n + d - 1) + e
int e = x % 10;
x /= 10;
uint64 n = 0;
if (e < 9) {
// x = 9*n + d - 1
int d = (x % 9) + 1;
x /= 9;
// x = n
n = x*10 + d;
} else {
n = x+1;
}
while (e) {
n *= 10;
e--;
}
return n;
}
