rddsd7


December 03, 2017, 07:10:59 AM 

Hey,
Anyone knows the crypto formula for generating BTC address?? is it base on date+time...??
Any possibility of repeating an address??








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aplistir


December 03, 2017, 10:47:40 AM 

Hey,
Anyone knows the crypto formula for generating BTC address?? is it base on date+time...??
Any possibility of repeating an address??
Yep. First you need to have a 256 bit random number, and then you convert it to an address. The random number is supposed to be fully random, so it is not based on anything. By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely. So you are better off playing lottery than trying to find an address collision

My Address: 121f7zb2U4g9iM4MiJTDhEzqeZGHzq5wLh



rddsd7


December 03, 2017, 03:20:39 PM 

Hey,
Anyone knows the crypto formula for generating BTC address?? is it base on date+time...??
Any possibility of repeating an address??
Yep. First you need to have a 256 bit random number, and then you convert it to an address. The random number is supposed to be fully random, so it is not based on anything. By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely. So you are better off playing lottery than trying to find an address collision Thanks. That implies a lot..




tromp


December 03, 2017, 03:50:07 PM 

By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely.
Assuming 10^7 addresses in use, the odds of address collision are 10^7/2^256, or roughly 10^70. Assuming a lottery with 10^8 odds of winning, the odds of winning a lottery 100 times in a row are 10^800. You're WAAAAAAAAAAAAYYYYYYYYYYYYYYYYYYYYYYYYYY off :(




rddsd7


December 04, 2017, 05:31:57 AM 

By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely.
Assuming 10^7 addresses in use, the odds of address collision are 10^7/2^256, or roughly 10^70. Assuming a lottery with 10^8 odds of winning, the odds of winning a lottery 100 times in a row are 10^800. You're WAAAAAAAAAAAAYYYYYYYYYYYYYYYYYYYYYYYYYY off :( Yeah.. I'm waaaaaaaaaaaayyyyyyyy off. but however there's a little possiblilty i guess.. so, i suggest if they would create the address by including the DATE+TIME, that would never repeat..




Dr.Z
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December 04, 2017, 07:40:57 AM 

Address = RIPEMD160(SHA256(Public Key))
The public key is calculated from the private key using elliptic curve multiplication, which is irreversible: K = k * G where k is the private key, G is a constant point called the generator point and K is the resulting public key.




BurtW
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December 05, 2017, 08:53:51 PM 

By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely.
Assuming 10^7 addresses in use, the odds of address collision are 10^7/2^256, or roughly 10^70. Assuming a lottery with 10^8 odds of winning, the odds of winning a lottery 100 times in a row are 10^800. You're WAAAAAAAAAAAAYYYYYYYYYYYYYYYYYYYYYYYYYY off :( His estimate of 100 lotteries is off by even more that that: the number of possible Bitcoin addresses is 2 ^{160}, not 2 ^{256}.

Our family was terrorized by Homeland Security. Read all about it here: http://www.jmwagner.com/ and http://www.burtw.com/ Any donations to help us recover from the $300,000 in legal fees and forced donations to the Federal Asset Forfeiture slush fund are greatly appreciated!



haltingprobability
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December 06, 2017, 02:44:18 AM 

By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely.
Assuming 10^7 addresses in use, the odds of address collision are 10^7/2^256, or roughly 10^70. Assuming a lottery with 10^8 odds of winning, the odds of winning a lottery 100 times in a row are 10^800. You're WAAAAAAAAAAAAYYYYYYYYYYYYYYYYYYYYYYYYYY off :( Last I checked, 0 = 0.




shrivelfire
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December 17, 2017, 07:58:47 PM 

You need to learn what are the possible addresses first. There are at least 256 types of addresses, and these are randomized.




BurtW
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December 17, 2017, 08:38:44 PM 

You need to learn what are the possible addresses first. There are at least 256 types of addresses, and these are randomized.
Noob knows not what they are talking about. There are 2 ^{160} possible Bitcoin addresses. There are 2 ^{256} possible public/private key pairs. So, there are approximately 2 ^{256} / 2 ^{160} = 2 ^{(256  160)} = 2 ^{96} public/private key pairs per Bitcoin address.

Our family was terrorized by Homeland Security. Read all about it here: http://www.jmwagner.com/ and http://www.burtw.com/ Any donations to help us recover from the $300,000 in legal fees and forced donations to the Federal Asset Forfeiture slush fund are greatly appreciated!



