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Author Topic: [XPM]QQQ if XPM / BLOCK = ans was 999/dif^2 what is going to sustain mining?  (Read 797 times)
jubalix (OP)
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July 13, 2013, 05:02:57 PM
 #1

if block reward = XPM / BLOCK = ans was 999/dif^2 what is going to sustain mining?

= dif 30 = 1 XPM/5s



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mustyoshi
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July 13, 2013, 05:04:06 PM
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The fact that diff 30 is orders and orders of magnitude more difficult than diff 8

Meaning we probably won't get over diff 10 without GPU miners. Let alone diff 20 or 30.
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July 13, 2013, 05:05:44 PM
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if block reward = XPM / BLOCK = ans was 999/dif^2 what is going to sustain mining?

= dif 30 = 1 XPM/5s




A MUCH higher exchange rate and more optimized miners I'm guessing
jubalix (OP)
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July 13, 2013, 05:11:54 PM
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The fact that diff 30 is orders and orders of magnitude more difficult than diff 8

what is the diff = function (Huh?)

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mustyoshi
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July 13, 2013, 05:14:14 PM
 #5

The fact that diff 30 is orders and orders of magnitude more difficult than diff 8

what is the diff = function (Huh?)
The difficulty is the length of the prime chain that must be found.

Due to the distribution of primes going from 7 to 8 primes, I believe somebody said it was 230x as rare? So from 7 to 9 would be 52900x as hard. So from 7 to 30 = 230^23 = really big.
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July 13, 2013, 05:20:13 PM
 #6

We won't pass diff 12 for quite a while. But we'll hit 10 no problems.

The coin will either fail miserably or go up in price a large amount in the upcoming weeks because of the difficulty.
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