1BitcoinEaterAddressDontSend

[walkerrrr]

But as it is fucking hard! (besides vanitigen not working full-length address)

I have already seen another all upper case vanitygen address in a sig on this forum so I think this must not be correct (at least with the current version).

That's my address   1QBDLYTDFHHZAABYSKGKPWKLSXZWCCJQBX

The problem is not length, it's how specific of an address you are looking for.  There are about 58³³ possible address, so if you want to find a very specific one (such as 1BitcoinEaterAddressDontSend..), then you have a 1/58³³ chance of finding it on each guess (infeasible*).  However, my address was not a search for a single address, it was any address of all capital letters.  There are about 26³³ such addresses.  So the chances of finding one such address on each guess is 26³³/58³³ = (26/58)³³.  That is actually in the realm of feasibility -- it is about 1/300billion

*  1/58³³ = 1/15599970876632771988160814054146447252125923204784443097088

why 58 ?
i think it's 62, 26 * 2 + 10 = 62

[BurtW]

Because it is not 62, it is 58:

https://en.bitcoin.it/wiki/Base58Check_encoding

'0' 'O' 'I' and 'l' are not used, 62 - 4 = 58.

So, in fact, his equation is in error.  We only use 24 of the captital letters so 24³³/58³³ = (24/58)³³.

I am surprised no one else (including me) caught that the first time around.

It was interesting to read my OP in this old thread.  Man, all I can say is what a noob I was back then

[walkerrrr]

Because it is not 62, it is 58:

https://en.bitcoin.it/wiki/Base58Check_encoding

'0' 'O' 'I' and 'l' are not used, 62 - 4 = 58.

So, in fact, his equation is in error.  We only use 24 of the captital letters so 24³³/58³³ = (24/58)³³.

I am surprised no one else (including me) caught that the first time around.

It was interesting to read my OP in this old thread.  Man, all I can say is what a noob I was back then

Thank you for your answer!

In bitcoin address, there are 4 bytes error checking code, so i think the formula shoud be (24/58)²⁹, am i right?

[jackjack]

Because it is not 62, it is 58:

https://en.bitcoin.it/wiki/Base58Check_encoding

'0' 'O' 'I' and 'l' are not used, 62 - 4 = 58.

So, in fact, his equation is in error.  We only use 24 of the captital letters so 24³³/58³³ = (24/58)³³.

I am surprised no one else (including me) caught that the first time around.

It was interesting to read my OP in this old thread.  Man, all I can say is what a noob I was back then

Thank you for your answer!

In bitcoin address, there are 4 bytes error checking code, so i think the formula shoud be (24/58)²⁹, am i right?

1 byte != 1 base58-digit

4 bytes = 256⁴ ~ 4 billions
and
58⁵ < 4 billions < 58⁶

So the signature is actually 6 base58-digits

[BurtW]

Because it is not 62, it is 58:

https://en.bitcoin.it/wiki/Base58Check_encoding

'0' 'O' 'I' and 'l' are not used, 62 - 4 = 58.

So, in fact, his equation is in error.  We only use 24 of the captital letters so 24³³/58³³ = (24/58)³³.

I am surprised no one else (including me) caught that the first time around.

It was interesting to read my OP in this old thread.  Man, all I can say is what a noob I was back then

Thank you for your answer!

In bitcoin address, there are 4 bytes error checking code, so i think the formula shoud be (24/58)²⁹, am i right?

Notice that 1QBDLYTDFHHZAABYSKGKPWKLSXZWCCJQBX contains 33 captial letters, this include all the letters used for the error checking code.  Since all 33 characters are captials the estimate we are looking for is:

24³³/58³³ = (24/58)³³