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Author Topic: Send ERC20 Tokens Without Paying Gas  (Read 91 times)
Craigmartin (OP)
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December 05, 2018, 09:47:37 AM
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Hi guys

I have 3 questions.
(1) How is it possible to send ERC20 Tokens without gas?
(2) If I want to send ERC20 Tokens from, lets say Account A with 0 Ethereum to Account B with Ethereum and have account B pay for the transaction gas, how do I do that?
(3) How is this guy in the examples doing it and is the gas being paid and by which account, the sender or receiver?

To me it looks like no gas is being paid, which is very strange.

I've tried googling answers to this but I'm getting the same answers "It's Not Possible you Noob""

Before you say it isn't possible like most people keep telling me, take a look at the following transactions, it is clearly happening, but how?

Example 1:(what I''m Taking About)
https://etherscan.io/tx/0x1dba1e5511d81a064f9423bea4af9a36826678221c3e539c882765773d33a73b
Gas Limit: 160000
Gas Used By Transaction:37263 (23.29%)
Gas Price:0 Ether (0 Ether)
Actual Tx Cost/Fee:0 Ether ($0.000000)


Example 2:(Normal Transaction)
https://etherscan.io/tx/0x84c19ddb593c5dc710310b65354cdbd7c24cb148bbcbb3a7eb4a5c9f9d22a5a9
Gas Limit: 250000
Gas Used By Transaction:36785 (14.71%)
Gas Price:0.000000004 Ether (4 Gwei)
Actual Tx Cost/Fee:0.00014714 Ether ($0.02)


More Examples of 0 Gas Price and Actual Tx Cost/Fee of 0

They're all different ERC20 tokens so it doesn't have to do with a specific tokens smart contract I'm assuming.

(1) https://etherscan.io/tx/0x815aa29ed5bb1af930f956763a5eb9756865847add90f9022643fdcf87f3a48c
(2) https://etherscan.io/tx/0x7a4370bc27251c85a70ec5bad47a1ddf30c5cfc4561765522050b0a9be49e1a6
(3) https://etherscan.io/tx/0x7f4eaef499ba069fb607300ad18cfcc86e27dc5ddd28c5b720c33126a66d7ea3
(4) https://etherscan.io/tx/0x1ad27aa3d07eb9c266109bc12e2a4cb856d5d240c47cd6d87cb9208f486fbc24
(5) https://etherscan.io/tx/0x2a3b6ec0f3653c20daf6c343f05e984c93131ef4e4e17909d5e548ce17611410
(6) https://etherscan.io/tx/0x6557ab42d1b39dc6e190a277299cc4634832f4520706332ae5bbebc9ed3f8db1

If someone can give a detailed explanation of how this is achieved I would really appreciate it.

Thanks in advance.

P.S. If its is a stupid and obvious answer then I'm sorry but I am kinda noob, Lol.
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