Laskoo (OP)
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August 15, 2019, 03:48:31 AM |
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Hello all!
I have a math problem which I struggle to solve. Any help is much appreciated so thank you in advance!
Let's assume we want to play lottery and 6 numbers are drawn.
I know that the odds of guessing 6 out of 6 in the exact order (order is important) = 1/1000000.
What are the odds of guessing:
5 of 6 = ?
4 of 6 = ?
3 of 6 = ?
2 of 6 = ?
1 of 6 = ?
Note: order is important.
Thank you!
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mrvuit
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August 15, 2019, 06:14:19 AM |
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Hello all!
I have a math problem which I struggle to solve. Any help is much appreciated so thank you in advance!
Let's assume we want to play lottery and 6 numbers are drawn.
I know that the odds of guessing 6 out of 6 in the exact order (order is important) = 1/1000000.
What are the odds of guessing:
5 of 6 = ?
4 of 6 = ?
3 of 6 = ?
2 of 6 = ?
1 of 6 = ?
Note: order is important.
Thank you!
So 6 of 6 is 1/1000000 = 0.0001% (min 000000 -> max 999999) 5 of 6 = 1/100000 = 0.001% (00000->99999) 4 of 6 = 1/10000 = 0.01% (0000->9999) 3 of 6 = 1/1000 = 0.1% (000->999) 2 of 6 = 1/100 = 1% (00->99) 1 of 6 = 1/10 = 10% (0->9 | 1/6 numbers are correct) Maybe I'm wrong, I'm not too good at math.
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Laskoo (OP)
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August 16, 2019, 07:13:17 PM |
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Hello all!
I have a math problem which I struggle to solve. Any help is much appreciated so thank you in advance!
Let's assume we want to play lottery and 6 numbers are drawn.
I know that the odds of guessing 6 out of 6 in the exact order (order is important) = 1/1000000.
What are the odds of guessing:
5 of 6 = ?
4 of 6 = ?
3 of 6 = ?
2 of 6 = ?
1 of 6 = ?
Note: order is important.
Thank you!
So 6 of 6 is 1/1000000 = 0.0001% (min 000000 -> max 999999) 5 of 6 = 1/100000 = 0.001% (00000->99999) 4 of 6 = 1/10000 = 0.01% (0000->9999) 3 of 6 = 1/1000 = 0.1% (000->999) 2 of 6 = 1/100 = 1% (00->99) 1 of 6 = 1/10 = 10% (0->9 | 1/6 numbers are correct) Maybe I'm wrong, I'm not too good at math. Thanks for your answer! I'm afraid you are wrong since 5 of 6 = 6 possibilities in 1000000. But I don't know the rest...
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Kiqeqijywa123
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August 16, 2019, 11:53:52 PM |
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This task is really very interesting
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Mavefyn0
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August 17, 2019, 03:24:29 AM |
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I know the answer to this problem but I don't want to write it, let others think. We passed this task in the 7th grade
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Laskoo (OP)
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August 17, 2019, 05:23:31 PM |
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I know the answer to this problem but I don't want to write it, let others think. We passed this task in the 7th grade
Good idea! Maybe you can share it on PM? If you want of course. Thanks anyway!
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Ankol99
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August 20, 2019, 05:46:59 PM |
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Hi, it's simple 1 of 6 = 1/6 2 of 6 = 1/6*1/6 = 1/36 3 of 6 = 1/6*1/6*1/6 = 1/216 .....
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Laskoo (OP)
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August 21, 2019, 08:47:34 AM |
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Hi, it's simple 1 of 6 = 1/6 2 of 6 = 1/6*1/6 = 1/36 3 of 6 = 1/6*1/6*1/6 = 1/216 .....
Got it, thank you!
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Patentico
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August 21, 2019, 12:33:35 PM Last edit: August 21, 2019, 01:03:29 PM by Patentico |
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n = number of possible drawn numbers, k = number of drawn numbers in winning combination x = matching drawn numbers C(k,x) = k!/(x!*(k-x)!)
considering the numbers are drawn from separate drums: P(x) = (1/n)^x * (1-1/n)^(k-x) * C(k,x)
k=6, if n=10
P(6) = 1 / 10^6 P(5) = 9 * 6 / 10^6 p(4) = 9^2 * 15 / 10^6 p(3) = 9^3 * 20 / 10^6 p(2) = 9^4 * 15 / 10^6 p(1) = 9^5 * 6 / 10^6 p(0) = 9^6 / 10^6
Match Combinations Odds Match 6 1 1 in 1,000,000 Match 5 54 1 in 18,518.52 Match 4 1,215 1 in 823.05 Match 3 14,580 1 in 68.59 Match 2 98,415 1 in 10.16 Match 1 354,294 1 in 2.82 Match 0 531,441 1 in 1.88
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Ankol99
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August 21, 2019, 06:23:43 PM |
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fulse match 0 1 in 1.88 ))
n = number of possible drawn numbers k = number of drawn numbers in winning combination
if numbers can be repeated
1 of 10 1/10 1 in 10 2 of 10 1/10*1/10 1 in 100 3 of 10 1/10*1/10*1/10 1 in 1000 ...
if the numbers cannot be repeated
1 of 10 1/10 1 in 10 2 of 10 1/10*1/9 1 in 90 3 of 10 1/10*1/9*1/8 1 in 720 4 of 10 1/10*1/9*1/8*1/7 1 in 5040 ...
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Laskoo (OP)
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August 22, 2019, 05:38:21 AM |
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Thank you for the answers guys!
@Patentico I think you are wrong because matching 5 in 6 there are only 6 combination.
@Ankol99 there are only 6 numbers, that can be repeated so applying your formula would be:
1 of 6 = 1/6 = 1 in 6 = 16.666666666% 2 of 6 = 1/6*1/6 = 1 in 36 = 2.777777777% 3 of 6 = 1/6*1/6*1/6 = 1 in 216 = 0.462962962% .........
This is the solution I am looking for, thanks again.
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Patentico
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August 22, 2019, 08:08:21 AM |
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You can check different combinations on this site: https://www.lotterypost.com/odds You forget to take into account the probability of failure: 9 in 10 chance If you want x out of 6 successes then there must be 6-x failures plus there are C(6,x) ways to arrange these combinations of success & failures Note: order is important.
P(x) = (1/10)^x * (9/10)^(6-x) * C(6,x)
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Patentico
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August 22, 2019, 09:09:22 AM |
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@Patentico I think you are wrong because matching 5 in 6 there are only 6 combination.
There are 9 different cobinations of getting the 6th number wrong also, so there are 6*9 = 54 different combinations!
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Vod
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Licking my boob since 1970
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August 22, 2019, 12:08:17 PM |
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I know that the odds of guessing 6 out of 6 in the exact order (order is important) = 1/1000000.
In exact order? That means there can only be one right number each time. Each guess has one less chance (unless you can reuse numbers, which you did not specify) Let's say you have 10 possible numbers First ball you have a 1/10 chance Second ball you have a 1/9 chance 3 = 1/8 4 = 1/7 5 = 1/6 6 = 1/5 That is 1 in 10*9*8*7*6*5 or 1 in 152,100 for just ten balls.
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bivaetjetakoe
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August 22, 2019, 04:09:14 PM |
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This puzzle is very difficult, I will not be able to solve it
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Laskoo (OP)
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August 23, 2019, 06:07:42 AM |
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I know that the odds of guessing 6 out of 6 in the exact order (order is important) = 1/1000000.
In exact order? That means there can only be one right number each time. Each guess has one less chance (unless you can reuse numbers, which you did not specify) Let's say you have 10 possible numbers First ball you have a 1/10 chance Second ball you have a 1/9 chance 3 = 1/8 4 = 1/7 5 = 1/6 6 = 1/5 That is 1 in 10*9*8*7*6*5 or 1 in 152,100 for just ten balls. Yes, sorry I forgot to specify that the numbers are reused and yes, you must guess them in the exact order. For example: - you pick a ticket with these numbers: 5 6 5 8 8 1. - the numbers drawn by the lottery are 1 5 7 8 2 1. You guessed 2 numbers, the 4th and the 6th. I want to know what are the odd for this to happen. (also for hitting 3,4,5 and 6 numbers). Thanks!
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