I need a tool for my project ... 3 BTC BOUNTY

[bytcoin]

I need a tool that solves this

p = 115792089237316195423570985008687907852837564279074904382605163141518161494337
a =
b =

w = GF(p)

w (((a / b)))
w (((b / a)))

w= 12447032699845648078645791161909514142990644957498005805208944683777961822095
w= 66620152837833785920928131416087065201280002472666144035333386572317622196480





If you can develop any tool that does this ... I will send you 3 BTC

[bytcoin]

I need a tool that finds the a and b value correctly

[bradock]

pm me your skype/telegram and put bounty in escrow.

[bytcoin]

pm me your skype/telegram and put bounty in escrow.

I answered you in PM
I'm waiting for you to prove that you have the tool

[Initscri]

pm me your skype/telegram and put bounty in escrow.

I answered you in PM
I'm waiting for you to prove that you have the tool

I think what he means is to put the money into a legitimate escrow, showing proof of funds. Directing the escrow to release the funds to the person who can provide you the functional tool and proving they did so.

You can do this publicly, and may gauge a better response.

[pooya87]

as far as i can tell your problem is not solvable. you have 1 equation with 2 unknown variables and in order to solve it you'll need another equation with the same 2 unknown variables. in simple terms (meaning simple arithmetic instead of modular on group) it is like wanting to solve x+y=10 (answer is: x=0, y=10 or x=1, y=9, and so on).

so for every "w1=a/b" and "w2=b/a" there can be multiple "a" and "b" values that can return the same result.
i can post a bunch of a's and b's with the same w1 and w2 results if you like.

ps: here is an example solution to your a and b and you can send my 3 BTC here: bc1q3aqjl7c8jc65vafdk9yc535yn2uvy49nxesd0s

Code:

a = 71567582482005396045706132302672619983252670291749153589321209247172649255534
b = 110101476471620722453482014247311557188089332708600935691798908256279685902522

[Btcspot]

 Hi, like pooya says it like your trying to solve the whole answer without knowing some variable. I think this might be what you need.
 Open browser here : https://defuse.ca/big-number-calculator.htm  or  https://www.emathhelp.net/calculators/algebra-2/solve-for-x-calculator/?f=a%2Fb*200%3Dx&real=on
                              

  A Big calculator that can solve large numbers. This is probably best your going to help answer the equation. If it helps send the 3 btc or you can split it 1.5 for me. My address : 13ogmvro1bzG7i1rqYCxs67KzK7k1fEhqQ

[pooya87]

Hi, like pooya says it like your trying to solve the whole answer without knowing some variable. I think this might be what you need.
 Open browser here :  https://defuse.ca/big-number-calculator.htm
                              https://keisan.casio.com/calculator

these are "normal" calculators that can only be used to compute "regular" arithmetic which is nearly useless here since you need modular arithmetic. specifically since you'll need to compute modular multiplicative inverses here, doing it by hand using "normal" calculators is going to be a nightmare!

[bytcoin]

I would like to thank everyone!
I received many PM ... And many suggestions from another topic.

THANKS
Especially from these people

@arulbero
@pooya87
@MixMAx123
@bradock
@MagicByt3

[bytcoin]

I want to be fair!
I needed a tool ... I got it through the telegram.
I liked the suggestions and help I received here on the forum

[bytcoin]

How to close this topic?

[examplens]

How to close this topic?

you have at the bottom left of the page "lock topic" link

[bradock]

as far as i can tell your problem is not solvable. you have 1 equation with 2 unknown variables and in order to solve it you'll need another equation with the same 2 unknown variables. in simple terms (meaning simple arithmetic instead of modular on group) it is like wanting to solve x+y=10 (answer is: x=0, y=10 or x=1, y=9, and so on).

so for every "w1=a/b" and "w2=b/a" there can be multiple "a" and "b" values that can return the same result.
i can post a bunch of a's and b's with the same w1 and w2 results if you like.

ps: here is an example solution to your a and b and you can send my 3 BTC here: bc1q3aqjl7c8jc65vafdk9yc535yn2uvy49nxesd0s

Code:

a = 71567582482005396045706132302672619983252670291749153589321209247172649255534
b = 110101476471620722453482014247311557188089332708600935691798908256279685902522

you wrong
this one the correct one
a = 76470300715912249562689990107401687364194232406198996658976353330269918489458
b = 64658408237276871767689061520961436408509493287485285377611016482361694763299

i dont know how to put pic here
http://prntscr.com/r3a85f

Code:

a = 76470300715912249562689990107401687364194232406198996658976353330269918489458
b = 64658408237276871767689061520961436408509493287485285377611016482361694763299

[pooya87]

you wrong
this one the correct one

you missed the point which was there is no correct "one". there are lots and lots of correct values that can give you the same exact results and there is no way to know which one was the one used.

since you claim you've received a solution through telegram, i'm wondering whether i am missing something or your solution is not working. if it does could you tell me what my a and b are with the following w1 and w2? it should be trivial if you have a working solution.

Code:

w1= 105373383711439474724359190780715920060817177495562500300186059478755772947454
w2 = 32602989975105451131244310962783059412483309815896176126375329270748375628877

here is SHA256 hash of ab (a concatenated with b) as string so that you can know i am not going to change a and b

Code:

d00633ecf039761cda2ec1b4b4a777e79abf40ad5fde7dede16833e281326b0d

[Vod]

I want to be fair!
I needed a tool ... I got it through the telegram.
I liked the suggestions and help I received here on the forum

Did you send the 3btc?

[bradock]

I want to be fair!
I needed a tool ... I got it through the telegram.
I liked the suggestions and help I received here on the forum

Did you send the 3btc?

he never

[kusanagi01]

he will never send 3BTC, why? because he didn't have it at all. let me explain to all of you the situation. I think that man knows about the puzzle of 100wallet BTC. I think all of you know about it. He thinks that if he can find a code that can solve he's equation then he can solve any wallet. and then get more than 30BTC and send to you the 3BTC. we have two problems here or issues. the first is the code will never ever solve an equation with an infinity of solution. he just dreaming that he find a vulnerability in ECDSA 
the second problem is let imagine you create the code for him (its impossible but let's imagine) he need time to run that code , it's like Pollard Kangaroo that needs months to solve the difficulty up to 100bit. So it's just don't waste your time.

equation with 2 variables has infinity solutions , you have to brute-force all of those solutions, may you need 33year to done

[Zemomtum]

Hope you have sent the 3BTC to the telegram support group, it will be good if you can send the transaction hash here. You are dreaming to solve the impossible. Good luck

[iluvbitcoins]

he will never send 3BTC, why? because he didn't have it at all. let me explain to all of you the situation. I think that man knows about the puzzle of 100wallet BTC. I think all of you know about it. He thinks that if he can find a code that can solve he's equation then he can solve any wallet. and then get more than 30BTC and send to you the 3BTC. we have two problems here or issues. the first is the code will never ever solve an equation with an infinity of solution. he just dreaming that he find a vulnerability in ECDSA  
the second problem is let imagine you create the code for him (its impossible but let's imagine) he need time to run that code , it's like Pollard Kangaroo that needs months to solve the difficulty up to 100bit. So it's just don't waste your time.

equation with 2 variables has infinity solutions , you have to brute-force all of those solutions, may you need 33year to done

Lol. Cheap fuck  
He could of offered at least 10 if the reward is 30 xD