Another coordinates for 120 puzzle

[COBRAS]

Original coordinates of public key:

(93499419120076195219278579763555015417347613618260420189054155605804414805552, 19494200143356336257404688340550956357466777176798681646526975620299854296492)

=


alternative:

(93499419120076195219278579763555015417347613618260420189054155605804414805552 : 96297889093959859166166296668136951495803207488841882392930608387608980375171 : 1)

*

fffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364140

=

(93499419120076195219278579763555015417347613618260420189054155605804414805552, 19494200143356336257404688340550956357466777176798681646526975620299854296492)

Compressed addresses are the same and belong to 17s2b9ksz5y7abUm92cHwG8jEPCzK3dLnT


Interesting, Yes ?

Qeschion - who can find privkey for point:

(93499419120076195219278579763555015417347613618260420189054155605804414805552 : 96297889093959859166166296668136951495803207488841882392930608387608980375171 : 1)

?

[1715497210]

1715497210

[1715497210]

1715497210

[1715497210]

1715497210

[1715497210]

1715497210

[1715497210]

1715497210

[vjudeu]

Compressed addresses are the same and belong to 17s2b9ksz5y7abUm92cHwG8jEPCzK3dLnT

No, you just calculated it in a wrong way. Some example:

Code:

importpubkey "02ceb6cbbcdbdf5ef7150682150f4ce2c6f4807b349827dcdbdd1f2efa885a2630" "firstkey" false
null
getaddressesbylabel "firstkey"
{
  "17s2b9ksz5y7abUm92cHwG8jEPCzK3dLnT": {
    "purpose": "receive"
  },
  "3CiPke5gtEYNpGhcdUbemvxdDKH3hWe6xt": {
    "purpose": "receive"
  },
  "bc1qfdrwzzj5rthvd03l43cfcft0kldxjvywxqax37": {
    "purpose": "receive"
  }
}

importpubkey "03ceb6cbbcdbdf5ef7150682150f4ce2c6f4807b349827dcdbdd1f2efa885a2630" "secondkey" false
null
getaddressesbylabel "secondkey"
{
  "1NgoEzuMrPDkadgBgmRQEfsDsK9oWhiEXH": {
    "purpose": "receive"
  },
  "38xKLmVWq37FYPh7wyWYzVRAcvLkTVgVfa": {
    "purpose": "receive"
  },
  "bc1qahshdh9ftqt7ayycxzq65zzg7c47vgd3sfwu99": {
    "purpose": "receive"
  }
}

[COBRAS]

Compressed addresses are the same and belong to 17s2b9ksz5y7abUm92cHwG8jEPCzK3dLnT

No, you just calculated it in a wrong way. Some example:

Code:

importpubkey "02ceb6cbbcdbdf5ef7150682150f4ce2c6f4807b349827dcdbdd1f2efa885a2630" "firstkey" false
null
getaddressesbylabel "firstkey"
{
  "17s2b9ksz5y7abUm92cHwG8jEPCzK3dLnT": {
    "purpose": "receive"
  },
  "3CiPke5gtEYNpGhcdUbemvxdDKH3hWe6xt": {
    "purpose": "receive"
  },
  "bc1qfdrwzzj5rthvd03l43cfcft0kldxjvywxqax37": {
    "purpose": "receive"
  }
}

importpubkey "03ceb6cbbcdbdf5ef7150682150f4ce2c6f4807b349827dcdbdd1f2efa885a2630" "secondkey" false
null
getaddressesbylabel "secondkey"
{
  "1NgoEzuMrPDkadgBgmRQEfsDsK9oWhiEXH": {
    "purpose": "receive"
  },
  "38xKLmVWq37FYPh7wyWYzVRAcvLkTVgVfa": {
    "purpose": "receive"
  },
  "bc1qahshdh9ftqt7ayycxzq65zzg7c47vgd3sfwu99": {
    "purpose": "receive"
  }
}

02ceb6cbbcdbdf5ef7150682150f4ce2c6f4807b349827dcdbdd1f2efa885a2630 = 17s2b9ksz5y7abUm92cHwG8jEPCzK3dLnT !!!

[vjudeu]

who can find privkey for point

Anyone who can find privkey for the first point. Calculating "fffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364141-puzzle120privKey" will do the trick, it's just one subtraction away.

02ceb6cbbcdbdf5ef7150682150f4ce2c6f4807b349827dcdbdd1f2efa885a2630 = 17s2b9ksz5y7abUm92cHwG8jEPCzK3dLnT

Of course, but your second point will have 03 prefix.

Edit: 19494200143356336257404688340550956357466777176798681646526975620299854296492 = ending with two (even) = 02 prefix
96297889093959859166166296668136951495803207488841882392930608387608980375171 = ending with one (odd) = 03 prefix

[COBRAS]

who can find privkey for point

Anyone who can find privkey for the first point. Calculating "fffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364141-puzzle120privKey" will do the trick, it's just one subtraction away.

02ceb6cbbcdbdf5ef7150682150f4ce2c6f4807b349827dcdbdd1f2efa885a2630 = 17s2b9ksz5y7abUm92cHwG8jEPCzK3dLnT

Of course, but your second point will have 03 prefix.

Edit: 19494200143356336257404688340550956357466777176798681646526975620299854296492 = ending with two (even) = 02 prefix
96297889093959859166166296668136951495803207488841882392930608387608980375171 = ending with one (odd) = 03 prefix

Maybe privkey of second point is smale then privkey of first pont.... No one thant try find and think about. Twe have 1 privkey at apper range of n, so, maybe there is a another key what will be smaller because upper range.

Any Ideas how to find privkey of point 1, using available information about second point and scalar ?

And we have a information about public key from scalar 0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364140 === 1JPbzbsAx1HyaDQoLMapWGoqf9pD5uha5m

Any positive ideas ?

[vjudeu]

Maybe privkey of second point is smale then privkey of first pont

If the creator of the puzzle is honest, then it is not. But there is no range proof, so we can only guess.

[COBRAS]

Maybe privkey of second point is smale then privkey of first pont

If the creator of the puzzle is honest, then it is not. But there is no range proof, so we can only guess.

This is anoter 2   point, now we  multiply to mach small scalar and get 120 puzle

(0xa22a23afde5da08ef95a102722b864597a04dd97bb618257e5bf0b972c6283df ,  0x8efe7ff38efc1799c51dfc7498081379acede5576b6717f155bdf8938d73d04b)

* Privkey:  107361793816595537 Privkey.HEX: 02 0x17d6cfb8ee30c51 =



(93499419120076195219278579763555015417347613618260420189054155605804414805552, 19494200143356336257404688340550956357466777176798681646526975620299854296492) - 17s2b9ksz5y7abUm92cHwG8jEPCzK3dLnT 120 BIT

Now second point looks like easy for brute Yes? Can someone find privkey for this point ?

[batareyka]

FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

93499419120076195219278579763555015417347613618260420189054155605804414805552
96297889093959859166166296668136951495803207488841882392930608387608980375171

03ceb6cbbcdbdf5ef7150682150f4ce2c6f4807b349827dcdbdd1f2efa885a2630

[COBRAS]

FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

93499419120076195219278579763555015417347613618260420189054155605804414805552
96297889093959859166166296668136951495803207488841882392930608387608980375171

03ceb6cbbcdbdf5ef7150682150f4ce2c6f4807b349827dcdbdd1f2efa885a2630

What is it ?

[batareyka]

Hello . This is the returned half of the private key.
Example.
If private key 1111111111
its public key 02e8f99fcdab7e2f5b37acfe8627c8d5d49b65c4c166c1bfe95f9d73386753a0ec

Its returned half FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25D9DE1475252
public key 03e8f99fcdab7e2f5b37acfe8627c8d5d49b65c4c166c1bfe95f9d73386753a0ec
If we add two private keys together we get 10000000000--
Actually and here
93499419120076195219278579763555015417347613618260420189054155605804414805552, 19494200143356336257404688340550956357466777176798681646526975620299854296492

93499419120076195219278579763555015417347613618260420189054155605804414805552: 96297889093959859166166296668136951495803207488841882392930608387608980375171

If you add them we get a private key.
100000000000000000000000000000000.



Of course, not everything is so simple.
Inverted half.
It is necessary to make some mathematical operations, but take my word for it.

[COBRAS]

Hello . This is the returned half of the private key.
Example.
If private key 1111111111
its public key 02e8f99fcdab7e2f5b37acfe8627c8d5d49b65c4c166c1bfe95f9d73386753a0ec

Its returned half FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25D9DE1475252
public key 03e8f99fcdab7e2f5b37acfe8627c8d5d49b65c4c166c1bfe95f9d73386753a0ec
If we add two private keys together we get 10000000000--
Actually and here
93499419120076195219278579763555015417347613618260420189054155605804414805552, 19494200143356336257404688340550956357466777176798681646526975620299854296492

93499419120076195219278579763555015417347613618260420189054155605804414805552: 96297889093959859166166296668136951495803207488841882392930608387608980375171

If you add them we get a private key.
100000000000000000000000000000000.

  I need go to smoke some sigaretes. INTERESTING

Big Thx Man 

[COBRAS]

Hello . This is the returned half of the private key.
Example.
If private key 1111111111
its public key 02e8f99fcdab7e2f5b37acfe8627c8d5d49b65c4c166c1bfe95f9d73386753a0ec

Its returned half FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25D9DE1475252
public key 03e8f99fcdab7e2f5b37acfe8627c8d5d49b65c4c166c1bfe95f9d73386753a0ec
If we add two private keys together we get 10000000000--
Actually and here
93499419120076195219278579763555015417347613618260420189054155605804414805552, 19494200143356336257404688340550956357466777176798681646526975620299854296492

93499419120076195219278579763555015417347613618260420189054155605804414805552: 96297889093959859166166296668136951495803207488841882392930608387608980375171

If you add them we get a private key.
100000000000000000000000000000000.



Of course, not everything is so simple.
Inverted half.
It is necessary to make some mathematical operations, but take my word for it.

Sory Bro, but then I multiply   100000000000000000000000000000000 to fffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364140 resut is not

120 puzzle, so, 100000000000000000000000000000000  is not private key for any of

93499419120076195219278579763555015417347613618260420189054155605804414805552, 19494200143356336257404688340550956357466777176798681646526975620299854296492

93499419120076195219278579763555015417347613618260420189054155605804414805552: 96297889093959859166166296668136951495803207488841882392930608387608980375171

yes ?

and then I add

93499419120076195219278579763555015417347613618260420189054155605804414805552, 19494200143356336257404688340550956357466777176798681646526975620299854296492

to

93499419120076195219278579763555015417347613618260420189054155605804414805552: 96297889093959859166166296668136951495803207488841882392930608387608980375171

result = 0

 

[wedom]

...
(93499419120076195219278579763555015417347613618260420189054155605804414805552 : 96297889093959859166166296668136951495803207488841882392930608387608980375171 : 1)
*
fffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364140
=
(93499419120076195219278579763555015417347613618260420189054155605804414805552, 19494200143356336257404688340550956357466777176798681646526975620299854296492)
...

fffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364140 = N-1
A * (N-1) = -A

...
and then I add
93499419120076195219278579763555015417347613618260420189054155605804414805552, 19494200143356336257404688340550956357466777176798681646526975620299854296492
to
93499419120076195219278579763555015417347613618260420189054155605804414805552: 96297889093959859166166296668136951495803207488841882392930608387608980375171
result = 0
...

A + (-A) = 0

[_Counselor]

Elliptic curve symmetry. Such a magic. Wow!

[a.a]

Hello . This is the returned half of the private key.
Example.
If private key 1111111111
its public key 02e8f99fcdab7e2f5b37acfe8627c8d5d49b65c4c166c1bfe95f9d73386753a0ec

Its returned half FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25D9DE1475252
public key 03e8f99fcdab7e2f5b37acfe8627c8d5d49b65c4c166c1bfe95f9d73386753a0ec
If we add two private keys together we get 10000000000--
Actually and here
93499419120076195219278579763555015417347613618260420189054155605804414805552, 19494200143356336257404688340550956357466777176798681646526975620299854296492

93499419120076195219278579763555015417347613618260420189054155605804414805552: 96297889093959859166166296668136951495803207488841882392930608387608980375171
If you add them we get a private key.
100000000000000000000000000000000.



Of course, not everything is so simple.
Inverted half.
It is necessary to make some mathematical operations, but take my word for it.

https://privatekeys.pw/key/0000000000000000000000000000000000000000000000000000001111111111
Public Key:
C 02e8f99fcdab7e2f5b37acfe8627c8d5d49b65c4c166c1bfe95f9d73386753a0ec

https://privatekeys.pw/key/FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25D9DE1475252
Public Key:
C 03cbd44d2c58745225ca7a4abb9bfacac2007c29556f8780655a2159280fcbbb5f

So the public key differs from the value you gave.

How do you get the corresponding key?

[POD5]

0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364141 - 0x1111111111 = 0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e7bbf253030

Pubkey = 03E8F99FCDAB7E2F5B37ACFE8627C8D5D49B65C4C166C1BFE95F9D73386753A0EC