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Author Topic: Passphrase wallet  (Read 257 times)
BlackHatCoiner
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September 13, 2021, 07:57:01 PM
 #21

However, you still need to calculate the checksum, so will need to input your entropy in to some software since you cannot do that by hand, and you will still need to turn the resulting 132 bit number in to a seed phrase, which is prone to error if you are doing it manually, and you will still need to import that seed phrase in to some wallet software to generate private keys and addresses.
You needed to do these before too. What you ensure is that your random number generator doesn't take part into the procedure of wallet's generation, which is kind of significant if you understand that there's no way to truly confirm it returns you random numbers. The other activities can be confirmed if someone wanted to rip you off.

Time to be completely pedantic, but actually it's around 1 in 2121, rather than 1 in 2128.
Yeah, I forgot to say this. I included the possibility for someone to have just generate their wallet without the checksum verification. Almost all wallets do that, but I included they could have done it manually.

Not that any of that matters. They are equally impossible.
Yep, they're very large numbers.



@Zedpastin, no one is ever going to steal your money by brute forcing.

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pooya87
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September 14, 2021, 04:31:50 AM
 #22

Time to be completely pedantic, but actually it's around 1 in 2121, rather than 1 in 2128.
I don't think that's right.
You are thinking in terms of "words" but you should be thinking in terms of the "entropy" itself.
In order to generate the same exact words you should generate the same exact entropy and that entropy (for 12 word mnemonic) is 128 bits so the odds are in fact 1 in 2128.

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o_e_l_e_o
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September 14, 2021, 12:03:47 PM
 #23

-snip-
Zedpastin wasn't talking about generating the same 12 words, which would obviously be 1 in 2128, but rather generating a seed phrase made up of the same word 12 times. Since there are 2048 words, then there are 2048 possible seed phrases which are made up of the same word 12 times. Only 1 in 16 of these will be valid (give or take) due to the checksum, so that leaves 128 out of 2128, which is the same as 1 in 2121.
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