example of dividing
./md 1 / 3 Result: aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa9d1c9e899ca306ad27fe1945de0242b81 (let it be 1/3)
10000 x 1/3:
./md 10000 x 0xaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa9d1c9e899ca306ad27fe1945de0242b81 Result: aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa9d1c9e899ca306ad27fe1945de0243886
1000*1/3 - 1/3=3333:
./md 0xaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa9d1c9e899ca306ad27fe1945de0243886 - 0xaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa9d1c9e899ca306ad27fe1945de0242b81 Result: d05
search range:
1/3 to 1/3*10000
0xaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa9d1c9e899ca306ad27fe1945de0242b81
:
0xaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa9d1c9e899ca306ad27fe1945de0243886
= 3333
3 times smale then 10000.You can play with ecctools for making your methods based on this example.
Use pubkeys from start privkeys and you get pubkey in range 3 time smaler too !!!
I looking for python programmer who know good simplest math operation in python for work on code for dividing pubksys.
ASAP.
YOU MAST KNOW HOW TO GET THIS RESULT, IF YOU CAN MESSAGE ME
YOUR TELEGRAMM FOR TALK:
Hello
Then I divide in modmath I get:
./modmath 0x60f4d11574f5deee49961d9609ac / 2
Result: 307a688aba7aef7724cb0ecb04d6
@COBRAS
you need this ( 0x60f4d11574f5deee49961d9609ac / 2 = 307a688aba7aef7724cb0ecb04d6) result run python2, its working
user@0d3aad1851b1:~/Downloads$ python2 1.py
0x307a688aba7aef7724cb0ecb04d6L
you need this ( 0x60f4d11574f5deee49961d9609ac /8 = 7fffffffffffffffffffffffffffffff5d577a91f1c6febc9bc6f8792bcde1d6) result , wrong
user@0d3aad1851b1:~/Downloads$ python2 1.py
0xc1e9a22ae9ebbddc932c3b2c135L
your need python from ./modmath
#its easy but some result wrong output print
edit: