Here is suggestion for a Dice tournament.
There will be an entry fee for the tournament. The players that sign up play in a league against each other. Football style with groups where everyone plays against everyone. Home and away fixtures.
Let's say you get 4 groups with 4 players per group. That's a total of 16 players.
After all group matches are over, the 2 best ranked players from each group proceed to the knockout stage.
8 players participate in the knockout battles. That's the 1/4 finals. The winners advance to 1/2 finals and Finals in the end.
Each knockout game will have 2 battles per fixture.
Rules:
- A match consists of X dice rolls. 5 or 10 for example.
- Each roll has a fixed bet. You can't bet more or less.
- The winner of the match is the player who predicted the most overs/unders and with the lower overall win chance parentage average. So to win against your opponent, you need to have predicted more overs/unders than them and placed winning wagers on lower win chances on average. (I will provide examples below).
- There will be a maximum win chance where you can't wager above that. For example, no bets over a 65% or 70% win chance per bet. There is no lower limit. Bet on a 2% win chance if you want.
- Rewards can be paid out only to the finalists where the winner gets more obviously. Or everyone who qualifies for the knockout stages could also get a reward.
- The winner of each match gets 3 points, the loser gets 0. In case they draw, (same amount of correctly predicted overs/unders with the same average win chance percentage) they each get 1 point.
- There are no points in the knockout matches. The aim is to record more wins in 2 matches with the lower total win chance percentage.
- The two players with the most gathered points at the end of the group matches advance to the knockout stages. If they finish with the same amount of points, the winner is the one with a better total win count throughout the entire group stage. If they have the same count, the winner is the one with a lower win chance percentage on average.
- In the knockout stages, Winner of Group 1 plays against the 2nd placed in Group 2. The 2nd placed of Group 1 plays against the winner of Group 2, etc.
A few examples of winners and losers for 5 rolls per match.
- Player A ends the match with 1 win and 4 losses. Player B ends ends the match with 2 wins and 3 losses. Player B is the winner no matter what the average win chance percentage of the rolls were.
- Both players successfully predict 3 out of 5 rolls. But Player A had an average win chance percentage of 47% while Player B had one of 51. Player A is the winner.
It would be best if the participants wouldn't know each other and had to sign up via a Google spreadsheet with alternative usernames to prevent them from colluding. The results of the other party wouldn't be known until both players complete their sets of X rolls.
Maybe a bit complicated, but that's it.