$50 in BTC Giveaway

[papundekli22]

bc1qadjpn755gd7grw7ja63kc0tjhen3wvyglku3zn

thnaks a lot

[1714763269]

1714763269

[1714763269]

1714763269

[Haunebu]

bc1qcay6pst9y53gaxk5yuwkkad6c9vccs0z3ckvz5

Worth a shot!

[pakhitheboss]

bc1qtgttq2pn4alt8sfdll5nhwyjj4w24hm5ulv0hw

Thanks.

[Mbitr]

Welcome to the forum, Rbah. Thanks  for this giveaway

bc1qrcnx8eza84txhgf3v2wn6rfhjxudhe5q8xah5p

Good luck all 

[rony01941]

WELCOME!
bc1qulqzymg4v2gqqvxsc6mnr4npywswqcyfm3rzgq

[Savemore]

Welcome to the Forum!

bc1qcfn6vxh5ssz0tgd60tfjyfn2l8nu7v990gltncl

[codehtcmail]

Let's see how lucky I am

bc1q293606en2aruadrk3lpsme5pmggzmr2aerw58n

Thanks in advance.

[abzy]

1BnMgz6PRRqPaPVfKqryqmyTTHY239J7MM

Thank you!

[MarcoRg011]

bc1qus6v2ty0nn2lfghxvq5zwc4jf9em3w4zh566e3
Thanks

[Myleschetty]

Welcome on board

BTC Address: bc1qmcqahxa5k8er6vqrntjlyp3chekgj6pzqt2w3q

[MachineGam]

bc1qm9n4ylpa9ddf7j2q87jjyt9vuzq7mx3lf4cx85


ty

[CryptoHeadlineNews]

Happy New Year & Welcome to the forum dear friend.

Can't wait to see who finally emerge the lucky winner on this giveaway. However, here is my address below.. Thanks

bech32 address: bc1q569t82xygdh62d6f0lduedq4k9nk42s0ljcvvs

[paid2]

Happy New Year & Welcome to the forum dear friend.

Can't wait to see who finally emerge the lucky winner on this giveaway. However, here is my address below.. Thanks

bech32 address: bc1q569t82xygdh62d6f0lduedq4k9nk42s0ljcvvs

We should have the answer tomorrow 

[md mohib]

Welcome here
bc1qvjl7vh8yjwtxm6l6pdff5pa0rv863gfzaz49jm

[Rbah]

I'll be rolling it soon, any idea how to roll it, i want to be as much as transparent as I can

[xLays]

I'll be rolling it soon, any idea how to roll it, i want to be as much as transparent as I can

You need to compile those addresses then give them a number. Then use bitcoin block to decide the winner.

Example last two hash digit of block : https://www.blockchain.com/explorer/blocks/btc/773373

Result: 00000000000000000002f4a304f5939bc22e379a208b2b977fd84021d8cb59e2

Winner: 92

 

[BenCodie]

I'll be rolling it soon, any idea how to roll it, i want to be as much as transparent as I can

You need to compile those addresses then give them a number. Then use bitcoin block to decide the winner.

Example last two hash digit of block : https://www.blockchain.com/explorer/blocks/btc/773373

Result: 00000000000000000002f4a304f5939bc22e379a208b2b977fd84021d8cb59e2

Winner: 92

 

To expand on this to help you with compiling the list Rbah, here are the first 3 participants compiled in a format that you can use continue on to do the whole list of entrants.

[10] TheChin0s bc1qnn44lgfzmzl3kk68gccdke4z6vxgwju272nsss
[11] GazetaBitcoin bc1qgfluvq03jcqzvaz6dc00qqgvyvmfuxra6etsd2
[12] CoinEraser bc1q4v2e08evleg047rcfnea97rampclqqzp682pgg 

Code:

[10] TheChin0s [url=https://bitcointalk.org/index.php?topic=5435424.msg61609316#msg61609316]bc1qnn44lgfzmzl3kk68gccdke4z6vxgwju272nsss[/url]
[11] GazetaBitcoin [url=https://bitcointalk.org/index.php?topic=5435424.msg61609528#msg61609528]bc1qgfluvq03jcqzvaz6dc00qqgvyvmfuxra6etsd2[/url] 
[12] CoinEraser [url=https://bitcointalk.org/index.php?topic=5435424.msg61609650#msg61609650]bc1q4v2e08evleg047rcfnea97rampclqqzp682pgg[/url]  

If you're wondering how xLays got 92:
00000000000000000002f4a304f5939bc22e379a208b2b977fd84021d8cb59e2 is the winning hash. 9e2 are the last parts of the hash. Remove the "e" and you get 92.

The reason for the list starting at [10], is if the result the hash is 9e2 like above and you've started counting entrants between 1 and 10, the winner is both [2] and [92]. Starting at 10 should stop you from facing that problem.

[5tift]

Honestly  , I will confirm receipt as soon as it arrives  

Thx for the giveaway

[GazetaBitcoin]

Honestly  , I will confirm receipt as soon as it arrives 

I am not sure if you are making fun or you really believe that you won therefore, for making sure that no confusion goes from here, you did not win anything yet. xLays was merely giving OP an example of how to pick the last two numbers of the block hash.

You need to compile those addresses then give them a number. Then use bitcoin block to decide the winner.

Example last two hash digit of block : https://www.blockchain.com/explorer/blocks/btc/773373

Result: 00000000000000000002f4a304f5939bc22e379a208b2b977fd84021d8cb59e2

Winner: 92

And, in that example, you were the winner. But it was just an example.

Furthermore, as far as I know, bitmover is looking for a solution of choosing the winner. Unless something clear comes up, please wait for an official roll to be made.

[BenCodie]

You need to compile those addresses then give them a number. Then use bitcoin block to decide the winner.

Example last two hash digit of block : https://www.blockchain.com/explorer/blocks/btc/773373

Result: 00000000000000000002f4a304f5939bc22e379a208b2b977fd84021d8cb59e2

Winner: 92

And, in that example, you were the winner. But it was just an example.

Furthermore, as far as I know, bitmover is looking for a solution of choosing the winner. Unless something clear comes up, please wait for an official roll to be made.

LOL! Nice pickup. xLays how long did you spend scanning blocks for you to make this happen ? Or was it just a happy coincidence?